advanced35 min studyLesson 572 in Mathematics

Algebraic integers, traces, and norms

Use multiplication maps and embeddings to calculate field trace and norm, keeping the ambient extension explicit.

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What you’ll understand

  • Calculate trace and norm from a multiplication matrix.
  • Account for conjugate multiplicities in a larger ambient field.
  • Recognize units using integral norms.

Trace and norm compress multiplication by a field element into two rational invariants. They can be computed through matrices or through embeddings, and agreement between those descriptions is a powerful check. The ambient extension matters: an element lying in a proper subfield has repeated conjugates when viewed in the larger field. Integrality makes these invariants integers, while the norm detects units only after the element is known to belong to the integer ring. We will keep those qualifications attached to every calculation.

Multiply, then take trace or determinant

For a number field K of degree n and α∈K\alpha\in K, multiplication mα:x↦αxm_\alpha:x\mapsto\alpha x is a Q-linear endomorphism of the n-dimensional vector space K. Define the field trace as its matrix trace and the field norm as its determinant. Different rational bases give conjugate matrices, so these values are basis independent. The trace is additive and Q-linear, while the norm is multiplicative. The norm is not generally additive, and replacing a determinant by the product of displayed coordinates has no basis-independent meaning.

Every number field is separable over Q, so there are n distinct embeddings into the complex numbers. After extending scalars, multiplication diagonalizes according to those embeddings, making trace their sum and norm their product. Complex embeddings occur in conjugate pairs when the base field is Q. Their paired norm contribution is nonnegative real, but real embeddings can contribute signs. Therefore a nonzero algebraic integer's rational norm can be negative; taking its absolute value is a separate operation used for ideal norms and lattice volumes.

Tr⁡K/Q(α)=tr⁡(mα)=∑σσ(α),NK/Q(α)=det⁡(mα)=∏σσ(α)\operatorname{Tr}_{K/\mathbb Q}(\alpha)=\operatorname{tr}(m_\alpha)=\sum_\sigma\sigma(\alpha),\qquad N_{K/\mathbb Q}(\alpha)=\det(m_\alpha)=\prod_\sigma\sigma(\alpha)
Both sums and products range over all n embeddings of the finite separable number field K.↔ Scroll wide equations horizontally.

The minimal polynomial may have smaller degree

Let F=Q(α) have degree d and let K contain F with degree r over F. The characteristic polynomial of multiplication by α on K is its degree-d minimal polynomial raised to the power r. Thus its field trace in K is r times its trace in F, and its norm in K is the r-th power of its norm in F. Reading only the constant term of the minimal polynomial is therefore insufficient when the requested norm is relative to a larger ambient field.

Trace and norm are also transitive in field towers, with the appropriate relative versions at each stage. A relative norm lies in the intermediate field before its rational norm is taken. Matrix dimensions and polynomial degrees provide easy checks for accidental mixing: a degree-four ambient multiplication map must have a degree-four characteristic polynomial even when the element satisfies a quadratic equation. Repeated roots in that characteristic polynomial do not contradict separability of the field extension; they reflect an element that does not generate the entire field.

Tr⁡K/Q(α)=rTr⁡F/Q(α),NK/Q(α)=NF/Q(α)r,F=Q(α), r=[K:F]\operatorname{Tr}_{K/\mathbb Q}(\alpha)=r\operatorname{Tr}_{F/\mathbb Q}(\alpha),\qquad N_{K/\mathbb Q}(\alpha)=N_{F/\mathbb Q}(\alpha)^r,\quad F=\mathbb Q(\alpha),\ r=[K:F]
The ambient degree supplies multiplicities for conjugates of an element lying in a proper subfield.↔ Scroll wide equations horizontally.

Integrality and units have separate roles

Multiplication by an algebraic integer preserves the integer ring. In an integral basis its matrix has integer entries, so its trace and determinant are integers. The converse statement that arbitrary integer trace and norm imply integrality is safe in a quadratic field, where they give the entire monic polynomial, but not as a general high-degree criterion. More characteristic coefficients are involved in higher degree. One should use the full minimal-polynomial or integral-extension criterion rather than two numerical tests outside their valid range.

For an element of the full integer ring, being a unit is equivalent to having rational norm plus or minus one. One direction follows by multiplicativity and integral norms of an inverse. For the other, the monic characteristic equation with constant term a unit expresses an integral inverse as a polynomial in the element. Without the hypothesis of integrality, norm plus or minus one alone does not establish membership in the unit group of the integer ring. Principal ideal norm is the absolute field norm, so it records the same magnitude while forgetting its sign.

An integral norm-one unit

In K=Q(sqrt(3)), calculate trace and norm of alpha=2+sqrt(3) using the basis (1,sqrt(3)), then find its inverse.

  1. Multiplication sends 1 to 2+sqrt(3) and sqrt(3) to 3+2sqrt(3). Its matrix is [[2,3],[1,2]], whose columns are the coordinates of those two products.

  2. The trace is four and determinant is 4−3=1. The conjugates 2+sqrt(3) and 2−sqrt(3) give the same sum and product, independently checking the matrix conventions.

  3. The product of alpha with 2−sqrt(3) is one. Both elements are in Z[sqrt(3)]=O_K, so alpha is a unit of the integer ring. Its minimal polynomial x²−4x+1 also yields the inverse as 4−alpha.

The result

The trace is four, the signed norm is one, and the inverse is 2−sqrt(3). An integer multiplication matrix verifies integrality and the unit condition together.

Explore the model

Interactive lab

Interactive lab · matrix

A determinant can distinguish integer invertibility

Pause and Reset, then set both controls to a=1 and b=1; predict determinant 1 and an integer inverse. Reset and set a=2 and b=1; predict determinant 2 and an inverse requiring a denominator. These triangular matrices illustrate determinant versus integer-lattice invertibility; they are not the actual multiplication matrices of the worked quadratic element. Readouts describe the final selected matrix.

A determinant can distinguish integer invertibilityThe selected matrix is A = [[a,b],[0,1]]. Playback interpolates geometry between the identity and A; readouts always describe A. Its determinant is a and its singular values come from AᵀA. Positive a makes every supported matrix invertible. This two-dimensional family is not a general eigensolver or a learned network. Current readings: Area scale · det A: 1.4; Singular values · σmax, σmin: 1.597, 0.876; Condition number · κ₂(A): 1.823. All parameters are adjustable with the labeled controls below.Matrix A with first row 1.4, 0.6 and second row zero, one; display interpolates between identity and A while final determinant remains 1.4.−4−2024−2−1012x · equal geometric scaleyA = [ 1.4 0.6 ; 0 1 ]Display blend: 0% · final values below
Interpolated geometryOriginal unit squareSelected final transform
Area scale · det A
1.4
Singular values · σmax, σmin
1.597, 0.876
Condition number · κ₂(A)
1.823
t = 0 s

The selected matrix is A = [[a,b],[0,1]]. Playback interpolates geometry between the identity and A; readouts always describe A. Its determinant is a and its singular values come from AᵀA. Positive a makes every supported matrix invertible. This two-dimensional family is not a general eigensolver or a learned network. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forFor an integral multiplication map, a unit determinant is the algebraic condition that multiplication has an integral inverse.

Check your understanding

An element alpha lies in a quadratic subfield F of a degree-four number field K, with [K:F]=2. How does its norm in K relate to its norm in F?

Try it yourself

Take K=Q(sqrt(2),sqrt(3)) and alpha=sqrt(2). Find its trace and norm from K to Q and compare with its quadratic minimal polynomial.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The four embeddings choose the signs of the two square roots independently. Each conjugate of sqrt(2) is therefore repeated twice.

Compare with the solution

The embedding values are sqrt(2), sqrt(2), −sqrt(2), and −sqrt(2). Their sum is zero and their product is four. The minimal polynomial x²−2 has norm −2 in Q(sqrt(2)), but the K-norm is (−2)²=4 because K has degree two over that subfield. The degree-four characteristic polynomial is (x²−2)², so its constant term agrees with the four-dimensional determinant.

Take it with you

  • Field trace and norm are the trace and determinant of multiplication.
  • Conjugates repeat when the ambient field is larger than the generated subfield.
  • The norm-unit criterion assumes the element is integral.

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