The Brunn–Minkowski inequality
Use concavity of the volume root to compare convex sums, identify equality, and understand the first-order isoperimetric consequence.
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The question for today
What you’ll understand
- State Brunn–Minkowski with common dimension and positive-volume assumptions.
- Check equality for homothetic bodies and strictness in a concrete rectangle example.
- Explain how infinitesimal ball addition relates volume growth to surface area.
Taking an average of two points stays inside a convex set. Taking an average of two entire convex bodies produces a new body whose volume is constrained in a deeper way. The Brunn–Minkowski inequality says that the d-th root of volume behaves concavely under Minkowski interpolation in d dimensions. The root is essential because volume scales with the d-th power of length. We will check the inequality in exact examples, identify its equality geometry, and trace one consequence for surface area.
Volume roots put lengths on a common scale
Let K and L be compact convex bodies with nonempty interior in the same real d-dimensional Euclidean space. For a number λ between zero and one, their Minkowski interpolation consists of all (1 − λ)x + λy with x in K and y in L. Brunn–Minkowski lower-bounds the volume root of this interpolation by the corresponding weighted average of the two original volume roots. This is a theorem, not a consequence of pointwise convexity alone.
The unweighted version says the volume root of K + L is at least the sum of the individual volume roots. Scaling reduces one version to the other. In dimension one, compact convex bodies are intervals, and their lengths add exactly. In higher dimensions the sum can gain extra volume because the two bodies occupy different directions. The root cannot be omitted from the concavity statement: squares of sides one and two have a midpoint square of area 2.25, below the average input area 2.5, while the corresponding area roots satisfy equality.
Equality is a geometric condition
For positive-volume convex bodies and an interior weight zero less than λ less than one, equality holds exactly when the two bodies are homothetic: one is a positive dilation and translation of the other. If L = sK + v with s positive, convexity gives (1 − λ)K + λL = ((1 − λ) + λs)K + λv. Taking volume roots then gives equality directly. The necessity direction is a substantive part of the equality theorem, not proved by this calculation.
Equal volumes alone do not force equality. A long horizontal rectangle and a long vertical rectangle may have the same area but create a larger-area average. Translations, in contrast, do not affect volumes or the homothety condition. Degenerate zero-volume sets require a separate equality discussion, so we do not extend the positive-volume characterization to them. At endpoint weights zero or one, equality is automatic regardless of shapes and therefore carries no structural information.
A first variation gives an isoperimetric bound
Add a small Euclidean ball εB to K, where B is the unit ball. Steiner’s volume expansion identifies the derivative at ε = 0 with the surface area S(K). Brunn–Minkowski says the volume of the enlarged body is at least the d-th power of |K| to the power 1/d plus ε times the unit-ball volume to the power 1/d. Differentiating this lower bound at zero yields the familiar isoperimetric comparison with a ball of the same volume.
This argument explains why addition of shapes can control boundary size, but it is a consequence sketch, not a complete proof of Brunn–Minkowski. The volume-polynomial facts justify the first-order step for convex bodies, including polytopes with nonsmooth boundaries. For dimension at least two, the result is S(K) at least d times κ_d to the power 1/d times |K| to the power (d − 1)/d. Balls attain equality. The important connection is between how fast a parallel body gains volume and how much boundary it initially has.
Work it through
Equal-area rectangles give a strict inequality
Let K = [0, 2] × [0, 1] and L = [0, 1] × [0, 2]. Compute their midpoint body and check Brunn–Minkowski.
Each rectangle has area two. Their Minkowski sum has side lengths three and three, hence area nine. Scaling the sum by one-half gives the midpoint body with side lengths 1.5 and 1.5.
The midpoint area is 2.25, so its area root is 1.5. The weighted average of the original area roots is √2, approximately 1.414214, strictly smaller.
The aspect ratios are two and one-half. A positive dilation and translation cannot change the aspect ratio or rotate these axis-aligned rectangles, so they are not homothetic; strictness agrees with the equality characterization.
The midpoint body has area 9/4, strictly above the common input area 2. Equal volumes do not imply equality in Brunn–Minkowski.
The living notebook
Explore the model
Interactive lab · matrix
Equal area does not mean the same shape
For each comparison Pause and Reset, then set both controls. First choose diagonal scale a = 1 and shear b = 0; then start a fresh run with a = 1 and b = 1. Predict area one in both selected final shapes but different angles and edge directions. The instrument does not draw their Minkowski average or certify homothety; it isolates why equal-area information alone is insufficient for the equality condition.
- Area scale · det A
- 1.4
- Singular values · σmax, σmin
- 1.597, 0.876
- Condition number · κ₂(A)
- 1.823
The selected matrix is A = [[a,b],[0,1]]. Playback interpolates geometry between the identity and A; readouts always describe A. Its determinant is a and its singular values come from AᵀA. Positive a makes every supported matrix invertible. This two-dimensional family is not a general eigensolver or a learned network. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forAn equality characterization needs geometric structure in addition to matching scalar volumes.
Pause & reason
Check your understanding
Your turn
Try it yourself
Let K be a convex body of volume 16 in real four-dimensional space and L = 2K + v for a fixed translation v. Find the volume of the midpoint body and verify the volume-root equality.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
The convex combination of K with a translated positive multiple of itself is another translated multiple of K.
Compare with the solution
The midpoint body is (K + 2K + v)/2 = (3/2)K + v/2. Its volume is (3/2)⁴ × 16 = 81. The original volume roots are 16^(1/4) = 2 and |L|^(1/4) = (2⁴ × 16)^(1/4) = 4. Their average is three, equal to 81^(1/4). Translation has no effect on these volumes. This is the homothetic equality case; using the arithmetic mean of raw volumes would instead give an unrelated quantity.
Keep the idea
Take it with you
- The d-th root makes volume scale like length under Minkowski addition.
- Positive-volume equality at an interior weight means homothety.
- First-order growth under ball addition connects Brunn–Minkowski to surface-area bounds.
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