advanced30 min studyLesson 888 in Mathematics

Nonconforming methods and Strang lemmas

Add consistency defects to approximation error when spaces or assembled forms differ from the continuous problem.

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What you’ll understand

  • Define a common error norm and a consistency functional for a nonconforming method.
  • Derive an approximation-plus-consistency Strang estimate.
  • Explain why persistent quadrature or load errors can survive refinement.

Galerkin orthogonality depends on more than solving a matrix accurately. A nonconforming space may contain tests unavailable in the continuous weak problem, and quadrature or geometry approximation may alter the assembled forms. Strang-type estimates account for these departures by combining approximation capacity, discrete stability, and a consistency defect. The word consistency means a quantified residual in a stated test norm, rather than a claim that an implementation resembles the differential equation informally.

Define an error space before subtracting unlike objects

Let the exact solution lie in a continuous space V and the discrete solution in V_h, which need not be a subspace of V. Assume a genuine norm is defined on their sum, or on a suitable regularity-enriched sum containing the exact solution. The discrete bilinear form must extend to the pairs used in the analysis and be bounded there. Without that extension, writing a_h(u,w_h) can be meaningless even if the discrete matrix itself is perfectly well defined.

A broken gradient seminorm alone is not a norm on arbitrary discontinuous cellwise functions: every piecewise constant has zero gradient on each cell. Nonconforming boundary constraints, face-average matching, or jump penalties must remove or control the relevant kernel. Choose a norm and prove uniform discrete coercivity in it. These details distinguish a valid nonconforming approximation from an unsupported attempt to copy the conforming proof using elementwise derivatives and no control of jumps.

Rh(wh)=Fh(wh)−ah(u,wh),δh=sup⁡wh≠0∣Rh(wh)∣∥wh∥h.R_h(w_h)=F_h(w_h)-a_h(u,w_h),\qquad \delta_h=\sup_{w_h\ne0}\frac{|R_h(w_h)|}{\|w_h\|_h}.
This consistency functional requires a meaningful bounded extension involving the exact solution; the norm must control all discrete null directions.↔ Scroll wide equations horizontally.

Stability controls a discrete correction

Suppose a_h is coercive with constant alpha_h on V_h and bounded with constant M_h when its first argument is an error from the common sum space and its second is discrete. Compare u_h with an arbitrary v_h. Coercivity bounds their difference by the approximation mismatch u−v_h and the consistency residual, divided by alpha_h. The triangle inequality adds the original approximation term. Taking the best candidate yields the displayed sufficient version of the second Strang estimate.

For a conforming method with perturbed quadrature, one can instead organize the residual into bilinear-form and load perturbations; the first Strang lemma tracks those variational crimes explicitly. Either organization needs uniform stability, meaningful continuity bounds, approximation tending to zero, and consistency defects tending to zero in the relevant norms. A small algebraic residual for the perturbed system does not ensure that its solution approaches the unperturbed weak solution.

∥u−uh∥h≤(1+Mhαh)inf⁡vh∈Vh∥u−vh∥h+δhαh.\|u-u_h\|_h\le\left(1+\frac{M_h}{\alpha_h}\right)\inf_{v_h\in V_h}\|u-v_h\|_h+\frac{\delta_h}{\alpha_h}.
This bound assumes the common norm, bounded extension and discrete coercivity just stated; it is generally not sharp.↔ Scroll wide equations horizontally.

Weak continuity can make nonconforming consistency small

For Crouzeix–Raviart affine elements, neighboring traces need agree only in their face averages, with corresponding homogeneous boundary averages. Elementwise integration by parts expresses the consistency defect in terms of exact normal fluxes paired with jumps. The zero-average jump cancels constant flux components, and a regularity estimate controls the remainder. This explains how a nonconforming space can converge, but it is not permission to ignore the face terms or to assume a rate without regularity and mesh hypotheses.

The same framework reveals why a fixed multiplicative stiffness error need not disappear on a finer mesh. If the assembled energy remains ten percent too large while the load stays exact, increasingly accurate spaces approximate a different variational problem. Solver tolerances and quadrature accuracy therefore need to be compatible with the desired discretization accuracy. When domains or boundary data are approximated, their contribution belongs in the same explicit consistency and data-error accounting rather than being hidden inside the mesh label.

A stable but perturbed one-equation problem

For the source-two interval problem with one interior hat, replace the exact stiffness four by 1.1 times four but keep the load one. Compute the new coefficient and its extra error relative to the exact Galerkin coefficient.

  1. The exact Galerkin coefficient is one quarter. The perturbed equation is (22/5)c_h=1, giving c_h=5/22.

  2. The coefficient difference is 1/4−5/22=1/44. Since the hat’s gradient energy is four, the squared energy distance between the two discrete functions is 4·(1/44)²=1/484.

  3. The exact Galerkin error is energy-orthogonal to the whole discrete space. Therefore the perturbed function’s squared energy error is 1/12+1/484=31/363, larger than the exact-form error 1/12.

The result

The modified stiffness stays positive, but stability alone does not remove its consistency bias. Refinement with the same persistent relative perturbation targets a different operator.

Explore the model

Interactive lab

Interactive lab · function

A changed quadratic changes a stationary point

On paper consider E(x)=a x²−x. Reset and set a=1,x=0.5; predict the displayed quadratic slope one, balancing the omitted linear term’s slope negative one. Reset, set a=1.1,x=0.5; predict quadratic slope 1.1, so the stationary point moves to 1/(2.2)=5/11. The instrument shows a x² and its tangent, not E or a finite element quadrature rule. Changes retain time; Reset restores both controls and zero time.

A changed quadratic changes a stationary pointThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA positive but persistently perturbed energy can have a different minimizer; stability and consistency are separate requirements.

Check your understanding

What extra term appears in a Strang estimate beyond best approximation?

Try it yourself

Assume the stated Strang bound with alpha_h=1, M_h=1, best-approximation error at most 0.02 and consistency dual norm at most 0.03. Compute the guaranteed error bound. If approximation tends to zero while consistency stays 0.03, does the bound prove convergence to zero?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use both terms; a nonvanishing second term cannot be removed by improving only the first.

Compare with the solution

The bound is (1+1/1)·0.02+0.03/1=0.07. If the approximation term tends to zero but the consistency defect remains bounded only by 0.03, this estimate leaves a 0.03 error floor and does not prove convergence to zero. It also does not prove the actual error must equal that floor; a sharper analysis could reveal cancellations, but convergence cannot be concluded from these assumptions alone.

Take it with you

  • Nonconforming analysis needs a common error norm and a meaningful extension of the discrete form.
  • Strang estimates combine approximation with a quantified consistency defect and stability constants.
  • A stable solve of a persistently perturbed variational problem can converge to the wrong limit.

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