Connections and curvature
Differentiate vector fields consistently, distinguish coordinate coefficients from curvature, and declare the curvature sign convention.
On this page
The question for today
What you’ll understand
- Explain the Leibniz rule supplied by a connection.
- State the two conditions characterizing the Levi-Civita connection.
- Recognize nonzero Christoffel coefficients in a flat coordinate system.
A vector field assigns a tangent vector to each point, but neighboring tangent spaces are different vector spaces. Differentiating its coordinate components alone does not produce an invariant comparison. A connection supplies a consistent rule for that comparison and for parallel transport along curves. Curvature measures a failure of successive covariant derivatives to commute after accounting for the vector fields' own commutator. These ideas explain why a rotating coordinate basis can produce nonzero connection coefficients even when the underlying geometry is flat.
A connection corrects naive differentiation
A connection on the tangent bundle assigns a vector field ∇ₓY to two vector fields X and Y. It is linear over smooth functions in X and obeys a product rule in Y: differentiating fY produces X(f)Y plus f∇ₓY. In coordinates, derivatives of Y's components are supplemented by terms containing Christoffel coefficients. Those coefficients compensate for the changing coordinate basis. They are not tensor components, because their transformation law includes second derivatives of the coordinate change.
A connection can be chosen without a metric, and an arbitrary choice can have torsion or fail to preserve lengths. For a Riemannian metric there is exactly one connection that is both torsion-free and metric-compatible: the Levi-Civita connection. Torsion-free means ∇ₓY−∇ᵧX=[X,Y]. Metric compatibility means differentiation respects the inner product, so parallel transport preserves lengths and angles. Neither condition alone gives the uniqueness theorem. The two requirements together tie differential comparison to the declared geometry.
Curvature has a convention and a tensorial meaning
Use the convention . The bracket correction removes effects caused merely by using noncommuting vector fields. With this convention, sectional curvature for orthonormal vectors u,v is g(R(u,v)v,u); a unit round sphere has sectional curvature +1. Other books negate R or arrange its indices differently. A sign disagreement should therefore be resolved by comparing definitions and a known example, not by replacing symbols until formulas look alike.
Unlike the Christoffel coefficients, curvature is tensorial: its value at a point depends only on the input vectors at that point, not on how they were extended to nearby vector fields. One can choose coordinates making Levi-Civita coefficients vanish at a given point, but cannot erase a nonzero curvature tensor there by relabeling coordinates. Curvature also governs infinitesimal parallel transport around small loops. Global transport around large noncontractible loops can contain information not settled by a local curvature test alone.
Polar coordinates are a useful false alarm
The Euclidean plane away from the origin has polar metric dr²+r²dθ². Its nonzero Levi-Civita coefficients include Γʳθθ=−r and Γθrθ=Γθθr=1/r. These terms describe the rotation and scaling of the coordinate basis. They do not imply intrinsic curvature. Substituting them into the curvature formula cancels the derivative and product terms. A coordinate singularity at r=0 is likewise not a geometric singularity of the Euclidean plane; the chart simply fails there.
For an affinely parametrized straight Euclidean trajectory, the polar-coordinate geodesic equation reads r̈−rθ̇²=0 and θ̈+2ṙθ̇/r=0. A nonzero radial coordinate acceleration can therefore coexist with zero intrinsic acceleration. This is a practical diagnostic whenever an unfamiliar chart produces complicated equations. First ask whether the terms arise from changing basis vectors, then compute an invariant such as curvature. The visual bending of embedded arrows and the number of nonzero coefficients are unreliable substitutes for that invariant.
Work it through
Watch curvature cancel in a curved-looking basis
For the flat polar metric, compute at r=2 using the stated convention.
The needed derivatives are , , and . At r=2 the two nonzero coefficients are −2 and 1/2.
The first nested derivative is . The second is , since ∂θr=0.
Coordinate vector fields commute, so their bracket is zero. Subtracting the nested derivatives gives . The nonzero connection coefficients have produced no curvature in this component.
The result is zero, consistent with the flat Euclidean plane. Nonzero Christoffel coefficients alone do not diagnose curvature.
The living notebook
Explore the model
Interactive lab · fields
Do not confuse a rotating field with curvature
Set q=0 and vary rotation Ω in the planar vector-field lab. Predict how the arrow at (1,0) turns and changes magnitude. This is the ordinary vector field Ω(−y,x) on a flat plane, not a connection or parallel-transport display. Its nonzero curl describes a field, while Riemannian curvature describes how a declared connection compares tangent spaces.
- Fx at (1, 0)
- 0.833
- Fy at (1, 0)
- 0.5
- Field magnitude there
- 0.972
The softened illustration is q·r/(r² + 0.2) + Ω(−y, x). Moving markers indicate local direction, not integrated particle paths or a Maxwell solution. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA swirling arrow pattern and a curved metric are different mathematical objects, requiring different tests.
Pause & reason
Check your understanding
Your turn
Try it yourself
At r=2, a Euclidean geodesic has polar velocity (ṙ,θ̇)=(0,1). What radial coordinate acceleration does its geodesic equation require?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use r̈−rθ̇²=0 rather than setting each coordinate acceleration to zero.
Compare with the solution
It requires . This is not a physical outward force: the corresponding radial Cartesian acceleration contribution is r̈−rθ̇²=0. With ṙ=0, the angular equation also gives θ̈=0 at this instant. The coordinate basis accounts for the apparent acceleration.
Keep the idea
Take it with you
- Connections compare vector fields and obey a directional product rule.
- Levi-Civita means metric-compatible and torsion-free together.
- Curvature is invariant data; connection coefficients can be nonzero in a flat chart.
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