advanced37 min studyLesson 375 in Mathematics

Plancherel and Fourier inversion

Extend Fourier analysis from test functions to L² while distinguishing norm inversion from absolutely convergent pointwise integrals.

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What you’ll understand

  • State Plancherel with the Euclidean 2π convention.
  • Identify hypotheses for absolute integral inversion.
  • Compute energy identities for Gaussian and interval inputs.

A transform should preserve enough information to reconstruct its input, but reconstruction can mean different things in different spaces. For rapidly decaying smooth functions, an ordinary inverse integral works at every point. For square-integrable inputs, the Fourier transform extends by completion as a unitary operator, and inversion is first a statement in norm. Confusing these meanings can turn a correct energy argument into an invalid pointwise integral. We keep the Euclidean exponential exp of minus two pi i x times frequency and use ordinary Lebesgue measure on both sides.

Inversion begins on a test class

For f∈S(Rd)f\in\mathcal S(\mathbb R^d), both its transform and its inverse integral are absolutely integrable in the relevant variables, and Fourier inversion recovers f(x)f(x) for every xx. One rigorous strategy inserts a Gaussian frequency cutoff, uses Fubini on the regularized integral, identifies a spatial approximate identity, and then removes the cutoff. The approximation argument matters: naively substituting one unregularized oscillatory integral into another and declaring the inner integral a point mass is not an application of ordinary Fubini.

A useful broader theorem assumes f∈L1(Rd)f\in L^1(\mathbb R^d) and f^∈L1(Rd)\widehat f\in L^1(\mathbb R^d). The inverse integral then defines a continuous representative equal to ff almost everywhere. At every point where the chosen input representative is continuous, the same value is recovered. Without the second integrability hypothesis, that inverse integral need not converge absolutely. A regularized or distributional inversion may still exist, but it is a different assertion requiring its own interpretation.

f(x)=∫Rdf^(ξ)e2πix⋅ξ dξ(f∈S(Rd))f(x)=\int_{\mathbb R^d}\widehat f(\xi)e^{2\pi i x\cdot\xi}\,d\xi\qquad(f\in\mathcal S(\mathbb R^d))
The positive exponential is the inverse convention. In this test class inversion is pointwise with an absolutely convergent integral.↔ Scroll wide equations horizontally.

Preserve the norm, then complete

On Schwartz functions, the inner product is preserved by the Fourier transform. In particular the spatial and frequency squared norms agree, without an additional prefactor under this normalization. Since Schwartz functions are dense in L², approximating any L² input by them gives a Cauchy sequence of transforms with the same distances. Its L² limit defines the extended transform independently of the approximating sequence. Extending the inverse in the same way makes the transform unitary and onto the frequency L² space.

An L² function need not be integrable, so its transform cannot always be defined by the original absolute integral. Even when the input is also integrable and its ordinary transform exists, that transform need not be integrable enough for absolute inverse integration. Norm inversion nevertheless recovers the input equivalence class. Pointwise assertions require further conditions or a specified limiting procedure. Unitarity is a powerful statement about average energy and stability, but no point evaluation is a bounded operation on the entire L² space.

∥f^∥L2(Rd)=∥f∥L2(Rd),F−1Ff=f in L2(f∈L2)\|\widehat f\|_{L^2(\mathbb R^d)}=\|f\|_{L^2(\mathbb R^d)},\qquad\mathcal F^{-1}\mathcal Ff=f\ \text{in }L^2\quad(f\in L^2)
Plancherel defines a unitary extension, with equality and inversion understood modulo null sets.↔ Scroll wide equations horizontally.

Energy checks can justify otherwise difficult integrals

Once an explicit transform has been found for an integrable square-integrable input, Plancherel evaluates its frequency energy without directly integrating an oscillatory squared expression. This is especially useful for interval indicators, whose transforms decay like a reciprocal frequency and need not have absolutely integrable magnitude. The squared magnitude is integrable, exactly as the theorem predicts. The removable value at zero frequency is the input's total mass, and getting it right checks both the scale and normalization.

Energy preservation also controls error: replacing a signal by an L² approximation produces exactly the same L² error between their transforms. It does not preserve every norm or every feature. A small-energy spike can have large pointwise amplitude, and its transform can spread over a broad frequency range. When an application needs a peak, a derivative, or a tail integral, ask for bounds in the relevant space rather than treating the L² identity as a universal guarantee of reconstruction quality.

Check both sides of a Gaussian's energy

Let f(x)=exp(−2pi x²). Calculate its transform and verify the squared L² norms on both sides.

  1. Gaussian scaling with a=2 gives the transform (1/√2)exp(−pi xi²/2). This is an ordinary Schwartz transform, so the formulas may be integrated absolutely.

  2. The spatial squared norm is the integral of exp(−4pi x²). Scaling the standard Gaussian integral gives 1/2.

  3. The transform's squared magnitude is (1/2)exp(−pi xi²). Its integral is also 1/2. Thus Plancherel matches the squared norms, while the norms themselves are both 1/√2.

The result

Both energy integrals are one half. Confusing a squared norm with a norm, or changing transform conventions midway, would spoil this simple check.

Explore the model

Interactive lab

Interactive lab · heat

Track an explicitly known mode norm

Pause and Reset, then set both controls to mode n=1 and diffusivity κ=1. After two Steps, time is one: predict the displayed unnormalized spatial L² norm √π exp(−1). Reset and set n=2 and κ=1; after two Steps predict √π exp(−4). The instrument integrates over one period with ordinary dx; normalized circle measure would instead give amplitude divided by √2. This is a damped mode, not a unitary Fourier evolution.

Track an explicitly known mode normThe exact periodic heat-equation mode is u(x,t) = exp(−κn²t) sin(nx), on [0,2π]. Playback advances physical time. The initial sine is shown separately, and the unnormalized L² norm is √π exp(−κn²t). This analytic instrument does not run a finite-difference solver or test discretization stability. Current readings: Current amplitude: 1; Spatial L² norm: 1.772; Decay rate · κn²: 3.6 /s. All parameters are adjustable with the labeled controls below.Periodic heat equation mode 3 at time 0: the amplitude is 1.0π/2π3π/22π−1−0.500.51x · periodic intervalTemperature perturbation uExact mode · n = 3
Current temperature modeInitial sineCurrent amplitude
Current amplitude
1
Spatial L² norm
1.772
Decay rate · κn²
3.6 /s
t = 0 s

The exact periodic heat-equation mode is u(x,t) = exp(−κn²t) sin(nx), on [0,2π]. Playback advances physical time. The initial sine is shown separately, and the unnormalized L² norm is √π exp(−κn²t). This analytic instrument does not run a finite-difference solver or test discretization stability. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forNorm comparisons are meaningful only after distinguishing the transform operation, the physical evolution, and the measure normalization.

Check your understanding

What does Fourier inversion for an arbitrary L² input guarantee without additional hypotheses?

Try it yourself

For a>0 let f be the indicator of [−a,a] on the real line. Find its transform, including its removable value at zero, and use Plancherel to evaluate its frequency squared-magnitude integral.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Integrate the exponential over the interval first. The spatial squared norm is the interval length.

Compare with the solution

For nonzero xi the transform is sin(2pi a xi)/(pi xi); its limit at zero is 2a, agreeing with the interval's mass. The spatial squared norm is the integral of the indicator, namely 2a. Plancherel therefore gives the integral over all real xi of |sin(2pi a xi)/(pi xi)|² equal to 2a. The input is in both L¹ and L², so its ordinary transform agrees with the L² extension, although absolute integrability of the transform itself is not required for this energy identity.

Take it with you

  • Schwartz inversion is pointwise; general L² inversion is a norm statement.
  • The 2π Euclidean convention makes Plancherel an exact isometry.
  • Energy identities do not automatically control pointwise or uniform error.

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