Homotopies and homotopy equivalence
Distinguish continuous deformation of maps from homeomorphism and verify a deformation retraction explicitly.
On this page
The question for today
What you’ll understand
- Check all endpoint and continuity conditions in a homotopy.
- Construct homotopy inverses from a deformation retraction.
- Distinguish contractibility, homotopy equivalence, and homeomorphism.
Topology can study a space through maps that deform continuously rather than through exact coordinate descriptions. A thick circular band and its central circle are not homeomorphic, yet every point of the band can move radially onto that circle without tearing or filling its hole. Homotopy equivalence captures this relationship. The proof must specify a continuous deformation of the entire map, not merely a collection of unrelated paths chosen separately for individual points.
A homotopy is one continuous map
For continuous maps , a homotopy from f to g is a continuous map , where , with and . Each time slice is a map, but continuity in both variables together is essential. Choosing a path from f(x) to g(x) for each x need not produce a continuous family. If the deformation must fix a subspace A, impose for all a and all times; this is a homotopy relative to A.
When the target is a convex subset of a real vector space, the straight-line formula joins any two continuous maps whose values lie there. Convexity ensures the entire interpolation stays in the target. The same formula can fail on a punctured plane: interpolating opposite points may pass through the forbidden origin. A useful verification checklist is therefore endpoint values, joint continuity, target membership, and any relative condition. A visually plausible deformation that leaves the prescribed space is not a homotopy of maps into that space.
An inverse only up to deformation
A map f from X to Y is a homotopy equivalence if some g from Y to X satisfies and . The composites need not equal the identities. A homeomorphism supplies such an equivalence with exact inverse composites, but an equivalence can forget contractible thickness or branches. Contractibility means the identity is homotopic to a constant map, equivalently that the nonempty space is homotopy equivalent to a point. Path connectedness alone is far weaker: it supplies paths between points without choosing the coherent contraction required by a homotopy.
A retraction fixes A pointwise, so the inclusion i obeys . A deformation retraction additionally deforms the identity of X to ir while keeping A fixed throughout. It therefore makes i and r homotopy inverses. An arbitrary retraction need not do this: the remaining composite ir may fail to be homotopic to the identity. The fixed-subspace condition also distinguishes a strong deformation retraction from a deformation that merely ends on A. Naming the maps and the two composite conditions prevents these notions from being conflated.
What homotopy equivalence preserves
Composing homotopies with continuous maps preserves their endpoint identities, which makes homotopy equivalence an equivalence relation. Topological invariants defined through homotopy classes, such as homotopy groups with appropriate basepoint bookkeeping, consequently agree for homotopy-equivalent spaces. This does not preserve every geometric quantity: lengths, areas, curvature, and even manifold dimension can change. A point and a closed interval are homotopy equivalent, while no homeomorphism identifies their underlying spaces. The desired invariant determines whether this coarser comparison is appropriate.
A deformation retraction can simplify a calculation before algebra enters. A punctured plane retracts radially onto a circle, a cylinder retracts along its interval coordinate, and a finite tree can contract by removing its terminal branches. Each example still requires a well-defined global formula or a compatible cellwise construction. In particular, a space with a hole cannot be declared contractible merely because a small piece of it is. Later the fundamental group will obstruct some proposed contractions, while higher homotopy groups detect holes invisible to loops.
Work it through
Retract a closed annulus
Let . Verify a deformation retraction onto the circle of radius two using .
The denominator never vanishes on A, so the formula is jointly continuous. At time zero it is x; at time one it is , on the selected circle.
Its radius is , a convex combination of a number in [1,3] and two. Thus every intermediate point remains inside the annulus. For a point already of radius two, the scalar multiplier is one at every time.
The terminal radial map r fixes that circle, so and H deforms to ir relative to the circle. For example, moves to at time one-half and to at time one.
The annulus and its radius-two circle are homotopy equivalent through an explicit deformation retraction; the calculation does not contract the circle to a point.
The living notebook
Explore the model
Interactive lab · matrix
A continuous family of invertible maps
Pause and Reset; set diagonal scale to 0.5 and shear to 1, then Play. Predict the interpolating matrix (1−s)I+sA has determinant 1−0.5s, always positive for 0≤s≤1. Reset, set scale to 2 and shear to −1, and compare determinant 1+s. Readouts describe the selected final matrix, while geometry interpolates.
- Area scale · det A
- 1.4
- Singular values · σmax, σmin
- 1.597, 0.876
- Condition number · κ₂(A)
- 1.823
The selected matrix is A = [[a,b],[0,1]]. Playback interpolates geometry between the identity and A; readouts always describe A. Its determinant is a and its singular values come from AᵀA. Positive a makes every supported matrix invertible. This two-dimensional family is not a general eigensolver or a learned network. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThese formulas give homotopies through linear homeomorphisms of the plane. The square instrument does not depict the annulus or prove that a space with a hole contracts.
Pause & reason
Check your understanding
Your turn
Try it yourself
Construct a deformation retraction of onto . Does this construction alone say the cylinder is contractible?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Keep the circle coordinate fixed and shrink only the interval coordinate.
Compare with the solution
Use . It is continuous, begins at the identity, ends on the bottom circle, and fixes that circle at every time. Thus the cylinder is homotopy equivalent to a circle. This is not a contraction to a point; it does not remove the remaining circle, whose nontrivial fundamental group will obstruct contractibility.
Keep the idea
Take it with you
- A homotopy is jointly continuous and must stay in its stated target.
- A deformation retraction supplies both homotopy-inverse composite conditions.
- Homotopy equivalence preserves homotopy information while allowing geometric thickness to disappear.
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