Tikhonov regularization and filter functions
Derive the quadratic estimator, its singular-value filter, and the assumptions behind a bias–noise convergence rate.
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The question for today
What you’ll understand
- Derive the normal equation and bounded inverse gain for α>0.
- Separate object-space shrinkage from data-to-object amplification.
- State a source condition and a compatible noise-dependent parameter balance.
Tikhonov regularization replaces exact inversion with a family of stable approximate inverses. Its penalty makes a chosen solution preferable, and its parameter controls how much weak information survives. We take a bounded linear map A between real Hilbert spaces, squared-norm data misfit, and an identity penalty centered at zero. For singular expansions and source-rate claims we use the compact setting of the preceding lesson and exact data y=Ax† with x† perpendicular to the nullspace.
A positive parameter makes the objective coercive
Minimize one half of the squared residual plus α/2 times the squared object norm. The factor one half fixes the parameter convention: differentiation gives (A*A+αI)x=A*yδ. The operator on the left is bounded, self-adjoint, and bounded below by α, hence invertible for every α>0. The objective is strongly convex and has a unique minimizer for every datum, even when the original equation has no exact solution or many solutions. This is a property of the regularized problem, not proof that the original inverse became identifiable.
The penalty favors the zero-centered minimum-norm solution. A reference object would replace x by x−x₀, changing the selected nullspace component. A general derivative or smoothing penalty has a different nullspace and needs its own coercivity conditions. In particular, one cannot assume uniqueness from the word quadratic if the data and penalty share an uncontrolled null direction. The identity penalty avoids that issue and allows a clean spectral calculation before more structured penalties are introduced.
A filter suppresses division by small singular values
In a singular direction with value σ, the data-to-object multiplier is σ/(σ²+α), rather than 1/σ. Its maximum over nonnegative σ is 1/(2√α), reached at σ=√α. Thus fixed positive α bounds noise amplification. When the input datum is exact, the corresponding object coefficient is multiplied by σ²/(σ²+α). This latter number is a shrinkage or resolution factor between zero and one. Confusing those two multipliers obscures whether one is discussing noise gain or bias on a true object.
Directions with σ² much larger than α are nearly preserved, while those with σ² much smaller than α are strongly damped. A hard truncated-SVD filter instead drops selected modes abruptly; both methods trade weak-direction bias for stability but produce different reconstructions. Nullspace components remain zero under the zero-centered identity penalty. Increasing α is therefore not additional measurement information: it increases reliance on the preferred object and can erase a real weak-direction feature along with its noise.
Rates require source smoothness as well as small noise
For any fixed minimum-norm solution, taking α→0 removes exact-data bias, but a rate needs information about how that object occupies weak singular directions. A standard source condition is x†=(A*A)^νw with 0<ν≤1 and bounded w. Spectrally, multiplication by σ^(2ν) limits those weak coefficients. The residual multiplier α/(σ²+α) then yields bias bounded by a constant times α^ν. This exponent convention uses A*A; writing a power of |A| instead would double the corresponding exponent.
Balancing α^ν against δ/√α gives α proportional to δ^(2/(2ν+1)) when the source bound is treated as fixed, and object error of order δ^(2ν/(2ν+1)). These are conditional deterministic rates, not automatic accuracies for arbitrary images. Classical identity Tikhonov has qualification one in this source convention, so extending the same rate formula to arbitrarily large ν needs further analysis. At a fixed noisy datum, driving α all the way to zero can undo the regularization rather than improve the result.
Work it through
Two different multipliers in a diagonal reconstruction
Use A=diag(1,0.1), yδ=(1,0.2), and α=0.01. Compute the Tikhonov reconstruction and its exact-object resolution factors.
The two normal-equation diagonal entries are 1.01 and 0.02. The right side A*yδ is (1,0.02).
Division gives xαδ=(100/101,1). By contrast, the unregularized inverse of the same datum is (1,2), so the weak-direction data gain has changed from ten to five.
Applied to exact object coefficients, the resolution multipliers are 1/1.01=100/101 and 0.01/0.02=1/2. The second reconstructed coefficient equals half of the unregularized inverse coefficient, not the original data coefficient.
The weak data gain five and the weak object shrinkage one half describe the same filter from two different input spaces.
The living notebook
Explore the model
Interactive lab · function
Inspect the penalty's quadratic geometry
Reset, set coefficient a=0.5 and position x=1. The curve gives penalty x²/2=0.5 and derivative x=1. Compare a fresh Reset, a=0.5 and x=2, giving penalty 2 and derivative 2. This displays the identity-penalty term before multiplication by α, not the full Tikhonov objective or an inverse solver.
- y at chosen x
- 0.608
- Tangent slope · 2ax
- 1.35
- Signed area · ax³/3
- 0.182
This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThe quadratic prior preference grows with object size, independently of whether the data observe that size.
Pause & reason
Check your understanding
Your turn
Try it yourself
Under the source condition with ν=1/2 and fixed source bound, balance the deterministic bias and noise terms. State the resulting α scale and error scale.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Set α^(1/2) and δ/α^(1/2) to the same order.
Compare with the solution
The balance gives α proportional to δ. Both terms then have order δ^(1/2), so the reconstruction error is O(δ^(1/2)) under the stated source condition and noise bound. This is a scaling statement, not a universal parameter constant. Without that source assumption, convergence can still hold with a suitable α sequence, but this particular quantitative rate is not justified.
Keep the idea
Take it with you
- Positive α stabilizes an identity-penalized problem by strong convexity.
- Noise gain and object shrinkage are different spectral multipliers.
- Convergence rates need stated source smoothness and a compatible parameter choice.
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