research34 min studyLesson 603 in Mathematics

Eisenstein series and lattice sums

Derive modular symmetry from absolutely convergent lattice reindexing and isolate the exceptional behavior of weight two.

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What you’ll understand

  • Justify lattice-sum convergence under the strict weight bound k>2.
  • Convert the lattice normalization Gₖ to constant-term-one Eₖ.
  • Explain why the holomorphic E₂ is quasimodular rather than an ordinary full-level weight-two form.

Summing a homogeneous function over the nonzero points of a lattice produces symmetry because an integral change of basis merely permutes the summands. That argument needs a convergence theorem before it can justify reordering. We use the lattice generated by 1 and τ in the upper half-plane, with integer weight k>2. Even weights give the nonzero holomorphic Eisenstein series; odd weights cancel in opposite lattice pairs.

Two-dimensional counting determines the convergence threshold

For τ in a compact subset of the upper half-plane, the real linear map (m,n)↦mτ+n is uniformly invertible. Its length is bounded below by a positive compact-dependent constant times √(m²+n²). The number of integer pairs in a shell of radius roughly R is proportional to R. Thus absolute convergence is controlled by the sum of R to the power 1−k. It converges exactly on the safe range k>2 used here, uniformly on compact subsets.

Normal convergence makes the lattice sum holomorphic and permits reindexing by an invertible integral matrix. The transformed lattice differs by the scalar factor (cτ+d)⁻¹, so homogeneity gives weight k. This proof does not consist of differentiating a divergent series formally. At odd integral k, pairing (m,n) with (−m,−n) gives zero because absolute convergence permits that grouping. At even k≥4 the result has a nonzero limit at infinity, supplied by the lattice row m=0.

Gk(τ)=∑(m,n)∈Z2∖{(0,0)}(mτ+n)−k,k>2,Ek(τ)=Gk(τ)2ζ(k)(k≥4 even)G_k(\tau)=\sum_{(m,n)\in\mathbb Z^2\setminus\{(0,0)\}}(m\tau+n)^{-k},\qquad k>2,\qquad E_k(\tau)=\frac{G_k(\tau)}{2\zeta(k)}\quad(k\ge4\text{ even})
The sum is absolutely and locally uniformly convergent in this range. Gₖ has constant term 2ζ(k), whereas Eₖ is normalized to constant term one.↔ Scroll wide equations horizontally.

Divisor sums appear after reorganizing convergent Fourier data

For even k≥4, the normalized expansion is Eₖ=1−(2k/Bₖ)Σσₖ₋₁(n)qⁿ, where Bₖ is the Bernoulli number in the convention B₂=1/6 and σᵣ(n) sums the rth powers of positive divisors. The divisor sum arises because an exponent n can be factored as a positive lattice index times a Fourier index. It is arithmetic information extracted from an analytic lattice sum. Individual coefficients can grow polynomially even though the series converges when |q|<1, because exponential q decay dominates that growth.

The two basic examples are E₄=1+240q+2160q²+6720q³+⋯ and E₆=1−504q−16632q²−122976q³+⋯. These are constant-term-one conventions; some texts instead normalize the coefficient of q to one, changing every displayed numerical factor. Products add weights, so combinations of E₄ and E₆ will create further forms. Their existence alone does not yet prove that every full-level form is such a polynomial; the later dimension argument supplies that completeness statement.

Ek(τ)=1−2kBk∑n≥1σk−1(n)qn,σr(n)=∑d∣ndr,q=e2πiτE_k(\tau)=1-\frac{2k}{B_k}\sum_{n\ge1}\sigma_{k-1}(n)q^n,\qquad \sigma_r(n)=\sum_{d\mid n}d^r,\qquad q=e^{2\pi i\tau}
This formula uses the actual weight k rather than an index denoting half the weight. It applies here to even k≥4.↔ Scroll wide equations horizontally.

Weight two requires an anomalous or nonholomorphic correction

At k=2 the absolute lattice sum fails its convergence test, so the previous reindexing proof cannot be recycled unchanged. The holomorphic series E₂=1−24Σσ₁(n)qⁿ exists on the upper half-plane but satisfies an extra term in its transformation law: E₂(γτ)=(cτ+d)²E₂(τ)+6c(cτ+d)/(πi). The anomaly disappears for translations but not for inversion. It is therefore called quasimodular, and it is not a counterexample to the absence of nonzero holomorphic full-level weight-two forms.

Subtracting 3/(πy) gives E₂*, which transforms with pure weight two but is no longer holomorphic because it depends on the imaginary part. The two corrected features cannot be silently combined into an ordinary holomorphic modular form. This distinction matters whenever derivatives or logarithmic derivatives of modular forms appear. Differentiation introduces related anomalous terms, and E₂ can compensate for them in suitable differential operators. Here the exact transformation law is stated as a theorem; the lattice convergence calculation explains why an exceptional phenomenon is possible, rather than proving that formula by itself.

Build and compare the first arithmetic coefficients

Compute the q² coefficient of E₄ and the q² coefficient of E₆ from divisor sums, then compute the q coefficient of E₄E₆.

  1. The positive divisors of 2 are 1 and 2, so σ₃(2)=1+8=9. The E₄ coefficient is 240·9=2160.

  2. Likewise σ₅(2)=1+32=33, so the E₆ coefficient is −504·33=−16632. The minus sign belongs to its Bernoulli normalization.

  3. Because both constant terms are one, the q coefficient in their product is 240−504=−264. The product has weight 10, constant term one, and this coefficient agrees with normalized E₁₀; proving equality uses the one-dimensional weight-10 space later.

The result

The calculations distinguish constant normalization, divisor exponents, and product convolution. Agreement of one coefficient is evidence until the ambient modular space and a valid equality criterion are supplied.

Explore the model

Interactive lab

Interactive lab · vectors

Watch a lattice generator approach degeneracy

Reset, set angle=90° and magnitude=1, representing a second generator τ=i alongside the fixed real generator 1. Compare a fresh Reset with angle=30° and magnitude=1, giving imaginary part 1/2. Predict that the real basis remains independent but has smaller determinant. A further fresh Reset at angle=0°, magnitude=1 makes the pair dependent and leaves the upper-half-plane setting. The vector diagram shows generator geometry, not a convergent Eisenstein sum.

Watch a lattice generator approach degeneracyPlayback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Current readings: x component: 1.393; y component: 0.975; Magnitude: 1.7. All parameters are adjustable with the labeled controls below.−7.46−3.7303.737.46−3.5−1.7501.753.5xyvvₓ = 1.39
Vectorx / y projectionsTrace marker
x component
1.393
y component
0.975
Magnitude
1.7
t = 0 s

Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forUniform lattice estimates require staying in compact subsets away from degenerate real generators.

Check your understanding

Why does the absolute-convergence proof for Gₖ require k>2?

Try it yourself

Use the E₂ inversion law to determine E₂(i). Explain why this value does not make E₂ a weight-two modular form.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The point i is fixed by S, whose c=1,d=0. Keep the anomalous term when substituting τ=i.

Compare with the solution

Inversion gives E₂(i)=i²E₂(i)+6i/(πi)=−E₂(i)+6/π, so E₂(i)=3/π. A genuine weight-two full-level form would instead satisfy f(i)=−f(i), forcing f(i)=0. E₂ avoids that conclusion exactly through its nonzero anomaly. The corrected E₂*(i)=E₂(i)−3/π is zero, as pure weight-two transformation requires, but E₂* is not holomorphic.

Take it with you

  • Absolute lattice reindexing is justified for integral k>2.
  • E₄ and E₆ here have constant term one, with divisor-sum coefficients.
  • E₂ exchanges ordinary modularity for holomorphy; E₂* makes the opposite exchange.

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