Fixed-point local well-posedness
Construct a nonlinear evolution through its integral equation, choosing a complete solution space and proving a quantitative contraction.
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The question for today
What you’ll understand
- Distinguish existence, uniqueness, and dependence on initial data in a stated function space.
- Close the cubic Schrödinger Duhamel map in periodic H¹.
- Check both ball preservation and strict contraction with explicit constants.
A nonlinear partial differential equation is not solved merely by writing its integral form. The integral equation becomes a construction only after a function space, a closed complete domain, and estimates have been chosen. Local well-posedness packages existence with uniqueness and stable dependence on the data in that specified setting. The proof also explains its own lifespan: a small time factor must defeat the size of the nonlinearity on the proposed solution ball.
Put the evolution into a complete space
Consider the cubic equation i times u_t plus u_xx equals kappa times |u|²u on the one-dimensional torus of length two pi. The initial datum belongs to H¹, and kappa is a fixed real coefficient. The free group U(t)=exp(it partial_xx) is unitary on H¹, as its Fourier multipliers have modulus one. Seek u in the Banach space of continuous H¹-valued functions on [0,T], with the supremum norm. This records the initial condition strongly and provides completeness for the fixed-point argument.
In one spatial dimension H¹ embeds into bounded functions and is a multiplication algebra. The cubic map therefore sends H¹ to H¹ and is locally Lipschitz there. A product derivative contains one differentiated factor and two undifferentiated bounded factors, giving a cubic norm bound; factoring a difference gives a quadratic Lipschitz coefficient on a ball of radius R. This is why dimension and regularity are part of the theorem. The identical algebra argument does not work in every H¹ space in higher dimensions.
Two inequalities have different jobs
Write M for the H¹ norm of the data and suppose the nonlinear bound and difference bound use a common constant K, enlarged if necessary. Unitarity and integration over time give an image bound M plus |kappa| T K R cubed. The difference of two images is at most |kappa| T K R squared times their distance. Choose R=2M when M is positive, and choose T so the nonlinear correction is at most M while the Lipschitz factor is strictly below one. Zero data have the zero solution and can be handled separately.
Ball preservation ensures the iteration remains inside the domain where the estimates hold. Strict contraction ensures convergence to one fixed point there. Neither condition should be omitted or substituted for the other. Uniqueness in the full local continuous-H¹ class follows by applying the same difference estimate on sufficiently short subintervals and patching them. Comparing solutions from two nearby initial data adds the free evolution of their initial difference, yielding continuous, indeed locally Lipschitz, dependence on a common sufficiently short interval.
State what kind of solution was constructed
The fixed point is a mild solution continuous in H¹. The equation gives its time derivative in H minus one, because taking two spatial derivatives lowers Sobolev regularity by two. A classical pointwise solution requires more regularity; the fixed-point theorem should not quietly claim it for arbitrary H¹ data. Smooth data can be treated with a persistence-of-regularity argument, showing that higher regularity continues while the relevant control remains available. That argument is an additional estimate rather than a consequence of notation.
The construction is local and works for either sign of kappa. Global existence requires a continuation argument and bounds that prevent the controlling norm from escaping. The torus has no whole-space dispersive decay of the usual kind, but the high-regularity multiplication estimate was enough here. Later Strichartz estimates will replace this simple algebra argument for rougher whole-space data. Comparing those proofs helps identify which ingredient actually supplies smallness: interval length, the linear orbit in a spacetime norm, or the initial norm itself.
Work it through
Choose a valid lifespan from stated bounds
Assume |kappa|=1, M=2, and a common product constant K=3 in the displayed estimates. Test R=4 and T=1/96 for ball preservation and contraction.
The free term has norm at most two. The nonlinear correction is bounded by TKR³=(1/96)·3·64=2, so the image norm is at most four and stays in the closed radius-four ball.
The difference coefficient is TKR²=(1/96)·3·16=1/2. It is strictly below one, so the map is a contraction on that complete closed ball.
Banach's theorem supplies a unique fixed point in the ball. The constants were hypotheses for this calculation, not universal numerical values of every Sobolev multiplication inequality.
The proposed interval passes both checks. Increasing the interval without rechecking both bounds would remove the quantitative justification, even if a solution happens to exist longer.
The living notebook
Explore the model
Interactive lab · optimization
Inspect the contraction property independently
Pause and reset, then set both controls to step size η = 0.5 and initial x₀ = 2. Predict the exact iterates 2, 1, 0.5 under multiplier 0.5 and inspect them with Step. For a fresh comparison, pause and reset, then set η = 2.5 and x₀ = 2; predict multiplier −1.5 and expanding alternating errors. This is a scalar iteration on a quadratic, not Picard iteration of a PDE or a way to measure its Sobolev constants. It isolates why a Lipschitz coefficient below one matters after a domain is chosen.
- Position x0
- 2
- Objective x²/2
- 2
- Iteration behavior
- Stable step
Gradient descent on f(x) = x²/2: xₙ = (1 − η)ⁿx₀. Playback advances two discrete iterations per second. Values outside |x| ≤ 4 are explicitly reported. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA contraction factor is a quantitative property to prove; an iteration formula alone does not provide it.
Pause & reason
Check your understanding
Your turn
Try it yourself
Under the same two estimates, let |kappa|=1, M=1/2, K=2, R=1, and T=1/4. Verify the image bound and difference coefficient. Explain why this constructs a mild H¹ solution rather than automatically a classical one.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Compute TKR³ and TKR² separately, then recall the regularity of two spatial derivatives.
Compare with the solution
The nonlinear contribution is (1/4)·2·1=1/2, giving image norm at most one, exactly the permitted radius. The difference factor is also one half, hence strict contraction. The result is a continuous H¹-valued fixed point of the integral equation. Two spatial derivatives of an H¹ function belong only to H minus one in general, so pointwise differentiability of every term is not guaranteed. Classical regularity requires stronger data and an additional persistence argument.
Keep the idea
Take it with you
- Well-posedness is always stated in a function space and includes uniqueness and data dependence.
- Ball preservation and contraction are distinct estimates with distinct logical roles.
- Local mild existence does not by itself provide classical regularity or global control.
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