Enveloping algebras and Casimir elements
Use PBW and invariant forms to construct central operators while declaring the normalization of their eigenvalues.
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The question for today
What you’ll understand
- Distinguish universal enveloping relations from identities in one representation.
- Construct a basis-independent quadratic Casimir using a specified invariant form.
- Reconcile algebraic, Killing-form, and angular-momentum eigenvalue conventions.
A Lie bracket specifies commutators, but representations also involve products of generators. The universal enveloping algebra packages those products without imposing accidental identities of one finite matrix model. Its center supplies operators acting by scalars on simple highest-weight modules. Quadratic Casimirs are the first examples, and their numerical eigenvalues are meaningless without a declared invariant-form normalization. Here g is finite-dimensional complex semisimple and the characteristic is zero.
PBW preserves ordered monomials rather than making generators commute
Construct U(g) from the tensor algebra by imposing x⊗y−y⊗x=[x,y]. Any Lie-algebra representation extends uniquely to an associative representation of U(g). After choosing an ordered basis of g, PBW says its ordered monomials form a vector-space basis of U(g). Thus g embeds in U(g), and the associated graded algebra for the degree filtration is the symmetric algebra S(g). The associated graded statement does not say U(g) itself is commutative; lower-degree bracket terms survive before taking that graded limit.
A finite-dimensional matrix representation usually has a large kernel as a U(g)-module, even if its restriction to g is faithful. For example, sufficiently high powers of a raising operator can vanish on a finite highest-weight module, while the corresponding ordered monomial remains nonzero in U(g). These are representation-specific annihilator relations. Confusing them with the defining enveloping relations would incorrectly collapse all Verma modules to the dimensions of one chosen matrix example.
Invariance produces a central element with a scale
The tensor Σxᵢ⊗xⁱ is independent of the basis and invariant under the adjoint action because it corresponds to the identity through the bilinear form. Multiplication into U(g) then produces ΩB, which commutes with every generator and hence is central. Scaling B by a nonzero constant c scales its dual basis and ΩB by 1/c. Centrality survives, but numerical eigenvalues change. A phrase such as the Casimir therefore needs a form convention, especially when comparing a Killing-form calculation with a physics normalization.
Choose an invariant form whose induced root inner product has long roots of squared length two on each simple factor. The quadratic Casimir then acts on a highest-weight module of weight λ by (λ,λ+2ρ), with the same induced weight pairing. This can be checked on a highest vector and extended through centrality to its cyclic module. For sl(2), taking B(x,y)=tr(xy) gives Ω=h²/2+ef+fe and eigenvalue m(m+2)/2 on L(m). The Killing form is four times this trace form, so its Casimir is one quarter as large.
The full center contains more information than one quadratic number
In higher rank, a quadratic eigenvalue does not generally distinguish all simple modules. For sl(3), the standard module and its dual have highest weights ω₁ and ω₂ and the same normalized quadratic eigenvalue 8/3, yet they are nonisomorphic. Higher central elements provide further information. The Harish-Chandra isomorphism, in a rho-shifted convention, identifies Z(U(g)) with Weyl-invariant polynomial functions on h*. The central character on L(λ) evaluates those polynomials at λ+ρ. This structural theorem is stated here, not derived from the quadratic example.
The shift is essential: ordinary Weyl-invariant polynomials evaluated at λ+ρ correspond to the dot-action organization of highest weights. One must state the shift before comparing central-character formulas. On finite simple modules Schur's lemma gives scalar central action; on reducible or nonsemisimple modules a central operator need not be one scalar on the entire space. Keep the universal element, its action in a particular module, and a chosen numerical normalization separate. That separation lets the same invariant algebra connect representation classification, differential operators, and physical symmetry without conflicting factors.
Work it through
Three conventions for one sl(2) representation
For L(3), compute the trace-form Casimir, Killing-form Casimir, and J² eigenvalues directly from a highest vector.
On the highest vector v₀, hv₀=3v₀ and ev₀=0. Therefore fev₀=0, while efv₀=[e,f]v₀+fev₀=3v₀.
The trace-form Casimir contributes 9/2 from h²/2 and 3 from ef, giving 15/2. The Killing-form Casimir divides this by four, giving 15/8.
The angular-momentum convention divides the trace-form value by two, giving 15/4. With j=3/2, j(j+1)=(3/2)(5/2)=15/4, confirming the relation.
The three values 15/2, 15/8, and 15/4 describe explicitly different normalized central elements. Their difference is a declared scale choice, not a disagreement about L(3).
The living notebook
Explore the model
Interactive lab · function
Recover a Casimir polynomial from a quadratic readout
Reset, set a=0.5 and x=1. The raw height is 1/2; adding the integer label m=1 gives c₁=3/2. Compare a fresh run with Reset, a=0.5 and x=2: height 2 plus m=2 gives c₂=4. The instrument plots m²/2 and the linear term is added analytically. Only nonnegative integer m labels finite sl(2) simple modules; the continuous slider does not extend that classification to arbitrary real values.
- y at chosen x
- 0.608
- Tangent slope · 2ax
- 1.35
- Signed area · ax³/3
- 0.182
This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA numerical invariant needs both its polynomial formula and its normalization and admissible labels.
Pause & reason
Check your understanding
Your turn
Try it yourself
Use the adjoint sl(2) module, whose highest weight is m=2. Compute the trace-form and Killing-form Casimir eigenvalues and explain why neither result asserts that the universal Casimir equals a scalar identity in U(g).
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Insert m=2 into cₘ and use the factor-four relation between forms.
Compare with the solution
The trace-form value is 2(2+2)/2=4, and the Killing-form value is 1. These are scalar actions in the selected adjoint representation. A universal central element can act by different scalars in different simple modules; for example its trace-form value is zero on the trivial module and 3/2 on L(1). Thus it is not universally equal to the number 4 times the identity. The representation map has imposed a central-character relation in its own quotient.
Keep the idea
Take it with you
- PBW distinguishes universal products from finite representation identities.
- An invariant form determines a quadratic Casimir and its scale.
- Rho-shifted central characters encode more information than a single quadratic eigenvalue.
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