research40 min studyLesson 843 in Mathematics

The stochastic heat equation and convolutions

Derive spectral covariance and Sobolev thresholds from the Hilbert–Schmidt norm of a heat semigroup acting on cylindrical noise.

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What you’ll understand

  • Construct a stochastic heat convolution through an operator-energy integral.
  • Derive its fixed-time Sobolev regularity threshold.
  • Separate regularity of the forcing, the convolution and its time paths.

The heat equation suppresses high spatial frequencies rapidly, but fresh noise keeps entering at every time. A stochastic convolution balances that smoothing against the infinitely many forced directions. The correct test integrates the squared Hilbert–Schmidt norm of the evolved noise amplitude. A Dirichlet eigenbasis turns this operator condition into an explicit summability problem. It reveals why spatial dimension matters, why a solution can exist in L² even when the noise does not, and why having an L² state does not imply finite gradient energy.

The semigroup belongs inside the stochastic integral

Let A generate a strongly continuous semigroup S on H and let W be cylindrical on U. For a bounded deterministic amplitude B from U to H, the zero-initial-data convolution is Zt=∫0tS(t−r)B dWrZ_t=\int_0^tS(t-r)B\,dW_r when the time integral of ∥S(r)B∥HS2\|S(r)B\|_{\mathrm{HS}}^2 is finite. This condition concerns each fixed time t. Continuity of the H-valued path requires an additional argument; it should not be silently inferred merely from finiteness at individual times.

For the Dirichlet Laplacian on the interval from zero to pi, choose normalized eigenfunctions with eigenvalues minus k squared. With identity noise amplitude, each coordinate is an independent Ornstein–Uhlenbeck convolution. Its variance is the integral of the squared exponential response, equal to one minus exp of minus twice k squared t, divided by twice k squared. The singularity of the full Hilbert–Schmidt norm near time zero is integrable in this one-dimensional setting.

E∥Zt∥H2=∫0t∥S(r)B∥HS2dr,E∣Zk(t)∣2=1−e−2k2t2k2(B=I, A=ΔD)\mathbb E\|Z_t\|_H^2=\int_0^t\|S(r)B\|_{\mathrm{HS}}^2dr,\qquad \mathbb E|Z_k(t)|^2=\frac{1-e^{-2k^2t}}{2k^2}\quad(B=I,\ A=\Delta_D)
The scalar variance uses normalized Dirichlet eigenfunctions on (0,pi), zero initial state, and unit cylindrical noise in every mode.↔ Scroll wide equations horizontally.

Dimension and the requested norm decide summability

Define the spectral Sobolev norm by ∥z∥HAs2=∑kλks∣zk∣2\|z\|_{H_A^s}^2=\sum_k\lambda_k^s|z_k|^2 for positive Dirichlet eigenvalues λk. At a fixed positive time, the high-frequency heat variances behave like 1/(2λk)1/(2\lambda_k). On a smooth bounded d-dimensional domain, Weyl eigenvalue growth therefore gives finite expected squared spectral Sobolev norm exactly when s<1−d/2s<1-d/2 for identity cylindrical forcing. The endpoint diverges. In particular the solution is L²-valued in dimension one, but not in dimensions two or higher under this white spatial covariance.

This is a fixed-time Gaussian Hilbert-space regularity threshold, including negative spectral spaces. In the diagonal Gaussian setting, the same trace criterion also determines almost-sure membership. It is not a statement that no distribution-valued solution exists above the L² dimensional threshold. Nor does it identify pointwise Hölder exponents by ordinary Sobolev embedding alone. Finer path regularity needs increment estimates and modification theorems, and nonlinear equations can require still more careful solution spaces.

E∥Zt∥HAs2=∑kλks1−e−2λkt2λk,λk≍k2/d⟹s<1−d2\mathbb E\|Z_t\|_{H_A^s}^2=\sum_k\lambda_k^s\frac{1-e^{-2\lambda_kt}}{2\lambda_k},\qquad \lambda_k\asymp k^{2/d}\quad\Longrightarrow\quad s<1-\frac d2
The iff threshold is for the stated bounded-domain Dirichlet spectral model at fixed t>0, with every mode forced at unit strength.↔ Scroll wide equations horizontally.

Colored amplitudes and time continuity need their own estimates

On the interval, reducing the noise amplitude in mode k by k to the power minus a changes its variance tail to order k to the power minus twice a minus two. The spectral regularity threshold improves to s less than a plus one-half. The amplitude itself is Hilbert–Schmidt only when a exceeds one-half, so heat smoothing can produce a state even outside that stronger input condition. The distinction is between the amplitude's own summability and the integrated evolved amplitude's summability.

For path continuity one useful sufficient linear criterion strengthens the operator integral with a small singular time weight: integrating r to the minus twice alpha times the squared Hilbert–Schmidt norm for some alpha strictly between zero and one-half supports a factorization argument. Gaussian moments then supply the needed time-integrability exponent. In the one-dimensional white-forced heat case, such a choice exists with alpha below one-quarter. These estimates concern the entire convolution process, unlike a single spectral trace calculation at a fixed time.

Finite state energy but infinite gradient energy

At time one in the one-dimensional Dirichlet model, calculate the first two coordinate variances and bound the full expected L² norm squared. Decide whether the expected squared gradient norm is finite.

  1. Mode one has variance (1−exp(−2))/2, approximately 0.432332. Mode two has variance (1−exp(−8))/8, approximately 0.124958. Their sum is approximately 0.557290.

  2. Every coordinate variance is below 1/(2k²), so the complete expected squared L² norm is below pi²/12, approximately 0.822467. The infinite coordinate sum therefore converges in the state space.

  3. Gradient energy multiplies each variance by k². The resulting summands approach one-half, so their sum diverges. This is consistent with the threshold s<1/2 and rules out claiming H1 regularity from the finite L² calculation.

The result

The heat convolution has a well-defined L² state here, but spatial white forcing prevents finite first-derivative energy.

Explore the model

Interactive lab

Interactive lab · heat

Read the deterministic response used by the convolution

Pause and Reset, then set both controls to spatial mode n=1 and diffusivity κ=1. Two Steps give time 1 and amplitude exp(−1), about 0.367879. Reset, set n=2 and κ=1, and take two Steps; predict exp(−4), about 0.018316. Squaring and integrating these response factors gives the corresponding stochastic mode variances. The scene shows deterministic heat decay, not a forced random realization.

Read the deterministic response used by the convolutionThe exact periodic heat-equation mode is u(x,t) = exp(−κn²t) sin(nx), on [0,2π]. Playback advances physical time. The initial sine is shown separately, and the unnormalized L² norm is √π exp(−κn²t). This analytic instrument does not run a finite-difference solver or test discretization stability. Current readings: Current amplitude: 1; Spatial L² norm: 1.772; Decay rate · κn²: 3.6 /s. All parameters are adjustable with the labeled controls below.Periodic heat equation mode 3 at time 0: the amplitude is 1.0π/2π3π/22π−1−0.500.51x · periodic intervalTemperature perturbation uExact mode · n = 3
Current temperature modeInitial sineCurrent amplitude
Current amplitude
1
Spatial L² norm
1.772
Decay rate · κn²
3.6 /s
t = 0 s

The exact periodic heat-equation mode is u(x,t) = exp(−κn²t) sin(nx), on [0,2π]. Playback advances physical time. The initial sine is shown separately, and the unnormalized L² norm is √π exp(−κn²t). This analytic instrument does not run a finite-difference solver or test discretization stability. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forStochastic convolution energy comes from integrating squared deterministic response operators.

Check your understanding

For unit cylindrical forcing and a smooth bounded d-dimensional Dirichlet domain, which fixed-time spectral Sobolev threshold is correct?

Try it yourself

On (0,pi), use amplitude B ek=k^(−a)ek for a≥0. Derive the fixed-time H_A^s threshold, and compare it with the condition that B itself is Hilbert–Schmidt. Include a=0.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Multiply the heat variance tail by the squared noise amplitude and by the Sobolev weight k^(2s).

Compare with the solution

The weighted variance summands have order k^(2s−2a−2), so the series converges exactly when 2s−2a−2<−1, or s<a+1/2. The operator B itself is Hilbert–Schmidt exactly when the sum of k^(−2a) converges, namely a>1/2. At a=0 the noise remains cylindrical in L², but the heat convolution is L²-valued because zero is below the threshold one-half. These statements concern a fixed positive time and the specified spectral norms.

Take it with you

  • Integrability of the evolved amplitude makes a stochastic convolution exist.
  • Fresh white forcing creates a strict dimension-dependent regularity threshold.
  • State energy, gradient energy and path continuity require different estimates.

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