core29 min studyLesson 191 in Physics

Derive the linear acoustic equations

Connect compression, pressure gradients, and inertia to the small-amplitude sound-wave equation.

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What you’ll understand

  • Linearize mass and momentum balance around a uniform resting fluid.
  • Identify the material assumptions behind a sound-wave equation.
  • Separate particle motion from propagation of a pressure pattern.

A loudspeaker moves air back and forth, yet its sound travels across a room. The distinction between local material motion and a traveling disturbance is the starting point of acoustics. We will derive a one-dimensional model from conservation laws rather than assume that every oscillation automatically makes a wave. The resulting equations are powerful precisely because their small-amplitude and material assumptions are visible.

Compression is a change of density

Consider a fluid initially at rest, with constant equilibrium density and pressure. Write its density as an equilibrium value plus a small perturbation, and call its small longitudinal particle velocity u. A short fixed interval gains mass when more fluid enters than leaves. At first order, the difference between these boundary flows is equilibrium density times the spatial derivative of u. Uniform translation therefore changes no density; a velocity that decreases along the interval compresses it.

The exact continuity equation contains the product of density perturbation and velocity. Linearization drops that product because both factors are already small. This is an ordering argument, not a claim that products never matter. Perturbation density divided by equilibrium density, and particle speed divided by sound speed, must remain much less than one. The equilibrium must also vary slowly enough that treating it as uniform over the region of interest is justified.

∂tρ1+ρ0∂xu=0,ρ=ρ0+ρ1\partial_t\rho_1+\rho_0\partial_xu=0,\qquad \rho=\rho_0+\rho_1
Mass conservation to first order about a uniform fluid at rest; density perturbation and particle velocity are small.↔ Scroll wide equations horizontally.

Pressure gradients accelerate matter

A fluid element feels pressure forces from both ends. Equal pressures cancel; a pressure that decreases to the right pushes the element rightward. Dividing the net force by its mass gives the linear momentum equation. The pressure itself can be large while its perturbation is small. A uniform atmospheric background supplies no net acceleration in this idealized horizontal problem. Ignoring viscosity and external forcing makes the equation conservative, not universally exact for real sound.

Close the pair of balance laws with a constitutive relation between pressure and density perturbations. For reversible, locally adiabatic changes, the proportionality is the isentropic derivative of pressure with respect to density. Differentiate continuity in time and substitute the momentum equation to obtain a wave equation. Its speed depends on material stiffness relative to inertia. Conservation alone does not specify that stiffness; an equation of state and the thermal regime are essential inputs.

ρ0∂tu=−∂xp1,p1=c2ρ1,∂t2p1=c2∂x2p1\rho_0\partial_tu=-\partial_xp_1,\qquad p_1=c^2\rho_1,\qquad \partial_t^2p_1=c^2\partial_x^2p_1
Here c²=(∂p/∂ρ) at fixed specific entropy, evaluated at equilibrium; the fluid is inviscid and initially uniform.↔ Scroll wide equations horizontally.

What travels, and what does not

A right-moving sinusoidal pressure disturbance has phase kx−ωt and satisfies ω=ck in this nondispersive model. A fixed crest advances at c while individual fluid elements oscillate about their equilibrium positions to first order. Their excursions are not the distance traveled by the crest. Mean streaming and net mass transport, when present in real experiments, require higher-order effects or boundaries beyond this first-order description. Do not infer permanent transport simply from a moving pressure maximum.

Use the two-wave lab to test linear superposition. Before moving the phase control, predict what equal amplitudes and a half-cycle phase difference will do to the sum. Then compare with a quarter-cycle offset. The display contains two same-direction sinusoids, not a density field or a compressible-fluid solver. Its exact cancellation illustrates linear addition; it cannot reveal viscosity, shocks, thermal losses, or the opposite-direction motion needed for standing sound in a pipe.

p1=Pcos⁡(kx−ωt),ω=ck,λ=2πkp_1=P\cos(kx-\omega t),\qquad \omega=ck,\qquad \lambda=\frac{2\pi}{k}
P is a small pressure amplitude, k is angular wavenumber, and wavelength is a spatial period.↔ Scroll wide equations horizontally.

Check a proposed sound wave

In an ideal uniform fluid, take c=300 m/s and angular wavenumber k=2 rad/m. A proposed pressure wave has amplitude 3 Pa. Find its angular frequency and wavelength, and assess the traveling-wave amplitude ordering if equilibrium density is 1.5 kg/m³.

  1. The wave equation requires angular frequency ck, so multiply 300 by 2 to obtain 600 rad/s. This is angular frequency, not cycles per second.

  2. Convert angular wavenumber into wavelength using 2π/k. The result is π metres, approximately 3.14 m; ordinary frequency is 600/(2π), about 95.5 Hz.

  3. The bulk modulus is ρ₀c²=1.5×300²=135000 Pa. The ratio P/(ρ₀c²)=3/135000≈0.0000222 equals the fractional density amplitude and particle Mach number for this traveling wave, supporting the small-amplitude ordering.

The result

The consistent wave has angular frequency 600 rad/s and wavelength π m. The small fractional density and velocity amplitudes support this model but do not by themselves establish uniformity or negligible dissipation.

Explore the model

Interactive lab

Interactive lab · waves

Test the linear addition rule

The controls change the phase difference and amplitude ratio of two waves sin(2x−t) and a sin(2x−t+phase). Predict cancellation at ratio one and phase 180° before testing it.

Test the linear addition ruleTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forSuperposition belongs to the linear model. This diagram has no fluid-density or pressure-to-velocity calculation.

Check your understanding

Which term is omitted specifically because this is a first-order expansion about rest?

Try it yourself

For the same fluid, double k while leaving the small pressure amplitude unchanged. Determine the new angular frequency and wavelength, and explain whether a fluid element must travel one wavelength each cycle.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use the nondispersive relation and distinguish a pattern from the particles carrying it.

Compare with the solution

Angular frequency doubles to 1200 rad/s and wavelength halves to π/2 m. A fluid element merely oscillates with a small displacement; a pressure crest travels one wavelength in a period. The wave speed remains 300 m/s within the stated uniform linear model.

Take it with you

  • Linear acoustics couples mass conservation, momentum conservation, and a material relation.
  • Pressure-pattern speed and local particle velocity describe different motions.
  • Small amplitude does not remove thermal, boundary, or viscosity assumptions.

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