Read the gravity–capillary dispersion relation
Compare gravity, surface tension, and depth to determine surface-wave phase and group speeds.
On this page
The question for today
What you’ll understand
- Identify the assumptions and restoring mechanisms in the surface-wave dispersion relation.
- Check deep-water and shallow-water limits independently of gravity–capillary dominance.
- Calculate the phase-to-group speed ratios in gravity and capillary limits.
Ripples on a fluid surface are not ordinary bulk sound. Gravity restores a displaced surface, surface tension penalizes curvature, and the fluid motion extends below the interface. These ingredients produce a dispersion relation that depends on wavelength and depth. We will use it as a compact map of physical regimes, checking which terms may be neglected before calculating how crests and wave packets move.
A surface disturbance couples flow and boundary motion
Take a horizontal fluid layer of uniform depth h, density ρ, and surface tension σ, with an impermeable flat bottom. For small-amplitude waves in an inviscid incompressible fluid with irrotational motion, a velocity potential obeys Laplace’s equation below the surface. The kinematic boundary condition makes the surface move with the fluid. The linear dynamic condition balances pressure with gravity and the surface-tension curvature contribution. Solving the depth dependence and matching these conditions gives the gravity–capillary dispersion relation.
The idealization neglects viscosity, background current, and the inertia of the medium above the surface, whose pressure is treated as uniform. Wavenumber k is positive here and refers to a horizontal spatial period. Small wave slope and sufficiently small displacement relative to the relevant geometric scales justify linearizing the moving boundary. These assumptions differ from compressible sound: incompressibility is compatible with surface propagation because the restoring dynamics involve the moving boundary rather than compression of the fluid bulk.
Depth and restoring-force dominance are different tests
Deep water means kh is much larger than one, so the hyperbolic tangent is close to one. Gravity dominance additionally requires σk²/(ρg) much smaller than one. Under both conditions, angular frequency approaches the square root of gk, phase speed is the square root of g/k, and group speed is half of phase speed. Saying only that a wave is in deep water does not establish gravity dominance; sufficiently short deep-water ripples can instead be dominated by surface tension.
For deep-water capillary dominance, the same ratio is much larger than one. Angular frequency then scales as k to the three-halves power, and group speed is three-halves of phase speed. The crossover wavenumber is the square root of ρg/σ, where the two restoring terms are equal. Shallow water is another independent limit, kh much smaller than one. There the leading relation becomes ghk²+(σh/ρ)k⁴. It is nondispersive only when the capillary term is also negligible.
Use the slope of the dispersion, not a guessed speed
In deep water with both restoring terms retained, differentiating the square-root dispersion gives group velocity. Dividing by phase velocity yields a ratio that interpolates from one half in the gravity limit to three halves in the capillary limit. At the crossover, group and phase speeds coincide even though the overall dispersion is not linear. Equality at one wavenumber does not make all packets nondispersive; nearby components can still accumulate different group delays and distort the envelope.
Use the spectral lab to inspect how shorter spatial scales enter a surface-like profile, while keeping its limits explicit. At mode count twelve, predict whether raising coefficient decay from zero to three suppresses fine ripples, then compare with mode count one. These settings change only a prescribed finite sum of sin(nx−t)/nᵖ. Its modes all have the same temporal frequency, so it does not obey the gravity–capillary dispersion relation, model depth, or predict the relative motion of a real surface-wave envelope and its crests.
Work it through
Check both limits before using a speed ratio
Use a model liquid with g=10 m/s², ρ=1000 kg/m³, σ=0.1 N/m, depth h=1 m, and k=10 m⁻¹. Decide whether deep-water gravity formulas are appropriate, then estimate phase and group speed.
The depth parameter is kh=10, so tanh(kh) is very close to one. The capillary-to-gravity ratio is σk²/(ρg)=0.1×100/(1000×10)=0.001, also small.
The gravity approximation gives ω=√(gk)=√100=10 rad/s. Phase speed is ω/k=1 m/s and group speed is approximately 0.5 m/s.
Keeping the capillary correction gives ω²=100+0.1=100.1 s⁻² in the deep-water formula. This is consistent with the small relative correction rather than a completely different regime.
Both tests support the deep-water gravity approximation: crests move at about 1 m/s, while a narrow-band envelope moves at about 0.5 m/s.
The living notebook
Explore the model
Interactive lab · spectral
Separate spatial detail from a propagation law
Compare coefficient decay p=0 and p=3 at mode count N=12, then compare N=1. Predict how high-mode suppression changes spatial detail. These controls do not vary depth, gravity, or surface tension.
- Sum at x = π/2
- 0.867
- Smallest wavelength
- 2π / 5
- Highest-mode coefficient
- 0.2
A finite sum of sin(nx − t)/nᵖ. Playback changes t; increasing the cutoff includes finer spatial scales. This is not a proof about a continuum limit or renormalization. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA Fourier profile is visible, but its fixed mode frequencies do not simulate gravity–capillary wave transport.
Pause & reason
Check your understanding
Your turn
Try it yourself
A gravity-dominated wave enters shallower water while remaining in the linear, shallow-water regime. If depth changes from 4 m to 1 m with g=9 m/s², compare its long-wave speed before and after. Can you apply the deep-water one-half group-speed rule?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use √(gh) only after stating both shallow-water and negligible-capillarity assumptions.
Compare with the solution
The long-wave speeds are √36=6 m/s and √9=3 m/s. In this leading shallow gravity approximation, phase and group speeds coincide; the deep-water one-half rule does not apply. Reflection, amplitude adjustment, and changing wavelength across a transition require additional matching beyond this local speed comparison.
Keep the idea
Take it with you
- Depth and gravity–capillary dominance are independent approximation checks.
- Deep gravity packets move at half the crest speed; deep capillary packets move at three-halves.
- Surface waves can propagate through an incompressible fluid because the restoring dynamics act at its moving boundary.
Read further
Original sources and deeper explanations to follow at your own pace.
Optional progress, saved in this browser when available. Revisit any lesson at any time.
Lesson not marked complete.