research27 min studyLesson 75 in Physics

Spontaneous symmetry breaking and the Higgs mechanism

Expand around a vacuum, derive radial and angular modes, and separate global symmetry breaking from gauge redundancy.

Before you begin
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What you’ll understand

  • Derive the small-fluctuation masses of a complex scalar.
  • Explain how a gauge field acquires a longitudinal polarization in the Higgs mechanism.
  • State why a gauge-fixed scalar expectation value is not a gauge-invariant order parameter.

A symmetric equation can admit states that do not share the symmetry. For a global symmetry this can produce a physical family of vacua and a massless mode. For a gauge redundancy, the same circle in a drawing contains equivalent descriptions, so the interpretation changes. We will keep these cases separate while deriving their shared local expansion.

Expand the potential, not just the picture

Take a complex scalar with canonical kinetic term ∣∂ϕ∣2|\partial\phi|^2 and potential V=λ(∣ϕ∣2−v2/2)2V=\lambda(|\phi|^2-v^2/2)^2, where λ>0\lambda>0 and v>0v>0. For a global U(1), minima satisfy ∣ϕ∣=v/2|\phi|=v/\sqrt2. In a neighborhood of a selected vacuum write ϕ=(v+h)eiπ/v/2\phi=(v+h)e^{i\pi/v}/\sqrt2. The radial coordinate hh and angular coordinate π\pi have canonical quadratic kinetic terms, although higher interactions make the polar-coordinate metric field dependent.

Expand the potential: V=λv2h2+λvh3+λh4/4V=\lambda v^2h^2+\lambda vh^3+\lambda h^4/4. Compare its quadratic term with mh2h2/2m_h^2h^2/2, yielding mh2=2λv2m_h^2=2\lambda v^2. There is no angular potential, so π\pi is massless at this classical level. For a genuine spontaneously broken continuous global symmetry, Goldstone's theorem protects the corresponding gapless behavior under its assumptions, including a suitable infinite-volume limit and Lorentz-invariant setting.

ϕ=v+h2eiπ/v,V=λv2h2+λvh3+λ4h4,mh2=2λv2\phi=\frac{v+h}{\sqrt2}e^{i\pi/v},\qquad V=\lambda v^2h^2+\lambda vh^3+\frac{\lambda}{4}h^4,\qquad m_h^2=2\lambda v^2
This is a local, tree-level expansion of the stated scalar model. The chosen v is the classical vacuum scale and should not be confused with a scheme-independent measured parameter beyond tree level.↔ Scroll wide equations horizontally.

Gauging changes the degree-of-freedom bookkeeping

Now use Dμ=∂μ−igAμD_\mu=\partial_\mu-igA_\mu. The scalar kinetic term contains (v+h)2(∂μπ/v−gAμ)2/2(v+h)^2(\partial_\mu\pi/v-gA_\mu)^2/2. In a suitable local gauge the angular coordinate is removed from that expression, leaving a vector mass term g2v2AμAμ/2g^2v^2A_\mu A^\mu/2. Compare with the Proca normalization to obtain mA=gvm_A=gv. The original massless vector's two physical polarizations and the scalar angular degree of freedom reorganize into three massive-vector polarizations.

This is the Higgs mechanism, not the insertion of an arbitrary gauge-breaking mass by hand. Covariant gauges retain an angular field and ghosts with gauge-dependent masses; their contributions cancel appropriately in physical quantities. The radial excitation remains a physical mode in the weakly coupled expansion. The phrase that a vector 'eats' a scalar is only a mnemonic for the changed polarization count, not a literal process in which a particle is swallowed.

∣Dμϕ∣2=12(∂μh)2+12(v+h)2(∂μπv−gAμ)2,mA2=g2v2|D_\mu\phi|^2=\frac12(\partial_\mu h)^2+\frac12(v+h)^2\left(\frac{\partial_\mu\pi}{v}-gA_\mu\right)^2,\qquad m_A^2=g^2v^2
The equality holds in the polar patch away from φ = 0. The vector mass formula is tree level; physical pole masses include radiative corrections.↔ Scroll wide equations horizontally.

What is actually broken?

Without gauge fixing, a local gauge-variant field average cannot serve as an ordinary physical order parameter. Elitzur's theorem in its standard gauge-invariant lattice setting rules out spontaneous breaking of the local gauge redundancy. A nonzero scalar expectation value in a chosen gauge remains a useful perturbative coordinate, but it is not a direct gauge-invariant measurement. The Higgs regime is characterized through physical spectra, correlation functions, and suitable gauge-invariant diagnostics.

Global symmetry breaking also requires attention to limits. A finite symmetric system ordinarily has a symmetric expectation value unless an external source selects a direction. One takes an infinite-volume limit before removing an infinitesimal source to define a broken phase. A classical Mexican-hat plot does not by itself prove a quantum phase transition, determine finite-temperature behavior, or guarantee a sharp distinction between every Higgs and confining regime for every matter representation. Those questions depend on the full theory and its observables.

Count before and after gauging

At tree level let v = 10 in chosen mass units, λ = 0.125, and g = 0.3. Determine the radial and vector masses and count physical degrees of freedom.

  1. Compute m_h² = 2 × 0.125 × 100 = 25, so m_h = 5.

  2. Compute m_A = gv = 3. The vector has three massive physical polarizations.

  3. Before the reorganization there are two massless-vector polarizations and two real scalar components, giving four degrees of freedom. Afterwards there are three vector polarizations and one radial mode, also four.

The result

The Higgs mechanism changes how the same four physical degrees of freedom are represented. It does not create a fifth physical scalar Goldstone particle in this gauged one-complex-scalar model.

Explore the model

Interactive lab

Interactive lab · oscillator

Connect a quadratic fluctuation to a frequency

Set damping ζ to zero and vary natural frequency ω₀ in the unit-mass oscillator with x(0)=1 and velocity(0)=0. A steeper quadratic potential gives faster small oscillations, just as the radial field's quadratic curvature determines its zero-momentum tree-level frequency. The lab is not a Higgs potential, a gauge-field simulation, or a quantum phase diagram.

Connect a quadratic fluctuation to a frequencyUnit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Current readings: Displacement x(t): 1; Velocity v(t): 0; Regime: underdamped. All parameters are adjustable with the labeled controls below.02.557.510−1.15−0.5700.571.15Time · sDisplacementunderdamped
Displacement x(t)Current time
Displacement x(t)
1
Velocity v(t)
0
Regime
underdamped
t = 0 s

Unit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forMass follows from the quadratic fluctuation operator; the full symmetry and gauge interpretation requires the field theory.

Check your understanding

Which statement is compatible with Elitzur's theorem and the perturbative Higgs mechanism?

Try it yourself

Set g = 0 while keeping the scalar potential unchanged. What becomes of the angular mode, and which statement still requires an infinite-volume quantum argument?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Removing gauging restores a global U(1) transformation of the scalar.

Compare with the solution

In the classical expansion the angular scalar is massless and is no longer absorbed into a massive gauge field. Calling it a Goldstone boson of a spontaneously broken quantum global symmetry requires the phase and limiting assumptions of Goldstone's theorem; the potential drawing alone does not establish them.

Take it with you

  • Masses follow from canonically normalized quadratic fluctuations.
  • The Higgs mechanism reorganizes polarizations while preserving gauge-consistent predictions.
  • Gauge-fixed expectation values and gauge-invariant phase diagnostics must be distinguished.

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