advanced28 min studyLesson 452 in Physics

Spin-orbit coupling and atomic multiplets

Construct LS-coupled terms and use angular-momentum algebra to predict fine-structure intervals.

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What you’ll understand

  • Distinguish configurations, terms, levels, and magnetic substates.
  • Derive the LS spin-orbit energy from the total-angular-momentum identity.
  • Check the interval rule and identify its coupling assumptions.

An atomic configuration gives orbital occupations but rarely specifies a single energy. Electron repulsion first organizes many states into terms, and spin-orbit coupling can split each term into levels with different total angular momentum. Spectroscopy uses a compact notation for this hierarchy. Reading that notation correctly is as useful as calculating a matrix element: the superscript counts spin multiplicity, the letter labels orbital angular momentum, and the subscript identifies one level within a term.

Add angular momenta in the appropriate order

In LS coupling, add individual electron orbital angular momenta to obtain LL, and their spins to obtain SS. Then couple these totals to JJ. This order is useful when electrostatic term separations dominate spin-orbit mixing. The term symbol is 2S+1LJ^{2S+1}L_J, using capital S, P, D, and F for orbital values zero through three. The letter S and the spin symbol S play different roles, so read the superscript and the letter separately.

For specified LL and SS, the allowed JJ values run in unit steps from ∣L−S∣|L-S| through L+SL+S. Each level has 2J+12J+1 magnetic substates in zero external field. Summing their counts reproduces (2L+1)(2S+1)(2L+1)(2S+1). This is a useful completeness check when nonequivalent angular momenta are coupled. For equivalent electrons, antisymmetry can forbid whole LS terms before this coupling step; naive addition of distinguishable spins and orbitals would overcount the physical states.

J=∣L−S∣,…,L+S,∑J(2J+1)=(2L+1)(2S+1)J=|L-S|,\ldots,L+S,\qquad \sum_J(2J+1)=(2L+1)(2S+1)
L, S, and J are dimensionless quantum numbers; angular-momentum magnitudes contain hbar. The identity counts states within one allowed LS term.↔ Scroll wide equations horizontally.

Turn a scalar interaction into an energy

Within an isolated LS term, an effective spin-orbit Hamiltonian may be written Hso=AL⋅S/ℏ2H_{\mathrm{so}}=A\mathbf L\cdot\mathbf S/\hbar^2, where AA has energy units. Squaring J=L+S\mathbf J=\mathbf L+\mathbf S expresses the dot product through three commuting squared angular momenta. This eliminates any need to assign definite classical directions to L and S. Their magnitudes are quantum eigenvalues, and a coupled state generally lacks separate definite projections for the two vectors.

The resulting level shifts have a weighted center of gravity at zero relative to the unsplit term. Adjacent levels satisfy the Landé interval rule: the difference between levels J and J minus one is AJAJ. The sign of A decides their ordering. That sign is not fixed universally by the notation; for a many-electron term it can reflect shell filling and effective interactions. If observed intervals strongly violate the rule, configuration interaction or intermediate coupling may be physically relevant.

EJ=A2[J(J+1)−L(L+1)−S(S+1)],EJ−EJ−1=AJE_J=\frac A2\left[J(J+1)-L(L+1)-S(S+1)\right],\qquad E_J-E_{J-1}=AJ
A and E are energies in the same units. This first-order effective description assumes one well-isolated LS term and weak mixing with other terms.↔ Scroll wide equations horizontally.

Separate symmetry labels from an approximation

In a rotationally invariant atom, total J and its projection remain valuable labels even when LS coupling fails. For heavier atoms, individual electron spin-orbit energies can compete with electrostatic separations. A jj-coupled starting basis then couples each electron orbital and spin first, followed by the individual j values. Neither basis changes the Hilbert space. The quality of the approximation depends on which Hamiltonian terms are diagonal or small in that basis.

A multiplet in an observed spectrum contains transitions between several levels, not merely the levels of one term drawn horizontally. Different allowed transitions can share or nearly share frequencies, and their intensities require matrix elements and populations. Counting substates therefore does not predict an intensity pattern by itself. In the two-state lab, phase changes illustrate why probabilities in one basis fail to specify a state. It has no controls for L, S, exchange integrals, or a real multiplet Hamiltonian.

⟨L⋅S⟩=ℏ22[J(J+1)−L(L+1)−S(S+1)]\left\langle\mathbf L\cdot\mathbf S\right\rangle=\frac{\hbar^2}{2}\left[J(J+1)-L(L+1)-S(S+1)\right]
This identity follows from angular-momentum addition. Its use as a complete energy formula additionally requires the effective Hamiltonian stated above.↔ Scroll wide equations horizontally.

Resolve a triplet P term

An isolated 3P^3P term has A=2 meVA=2\,\mathrm{meV} in the effective Hamiltonian. Find its level shifts, degeneracies, and adjacent intervals.

  1. The multiplicity gives S=1S=1, while P means L=1L=1. Angular-momentum addition permits J=0,1,2J=0,1,2, so the bracket in the energy formula is J(J+1)−4J(J+1)-4.

  2. Substitution gives shifts −4,−2,+2 meV-4,-2,+2\,\mathrm{meV}. The respective degeneracies are one, three, and five, whose sum is nine as required by the product of orbital and spin dimensions.

  3. Subtract adjacent shifts to obtain 22 and 4 meV4\,\mathrm{meV}. Also check the weighted sum: 1(−4)+3(−2)+5(2)=01(-4)+3(-2)+5(2)=0, confirming the chosen term center.

The result

The triplet P term splits into three levels with intervals in the ratio one to two for positive A.

Explore the model

Interactive lab

Interactive lab · quantum

Probabilities do not specify coupling

Reset and set mixing angle 90∘90^\circ and relative phase 0∘0^\circ; predict equal basis probabilities and positive Bloch x. Repeat from Reset with both controls set to 90∘90^\circ and 180∘180^\circ; probabilities stay equal while Bloch x reverses. This pure two-state phase comparison does not construct LS-coupled multiplets.

Probabilities do not specify couplingA normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Current readings: Probability |0⟩: 71.1%; Probability |1⟩: 28.9%; Bloch (x, y, z): 0.78, 0.45, 0.42. All parameters are adjustable with the labeled controls below.xyz|0⟩|1⟩Basis probabilitiesP(0)71.1%P(1)28.9%
Bloch vector / P(0)P(1)Phase latitude
Probability |0⟩
71.1%
Probability |1⟩
28.9%
Bloch (x, y, z)
0.78, 0.45, 0.42
t = 0 s

A normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forAn energy depending on coherence cannot be inferred from two populations alone.

Check your understanding

An isolated LS term has L = 2 and S = 1. Which total-J set is complete?

Try it yourself

For a 2D^2D term with A=4 meVA=4\,\mathrm{meV}, find the two J values and their separation. State how the ordering changes if A changes sign.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use L = 2 and S = 1/2, then apply either the energy expression or the adjacent interval rule.

Compare with the solution

The levels have J=3/2,5/2J=3/2,5/2. Their shifts are −3A/2=−6 meV-3A/2=-6\,\mathrm{meV} and A=4 meVA=4\,\mathrm{meV}, so the upper-minus-lower interval for positive A is 10 meV10\,\mathrm{meV}. Reversing A reverses both shifts and their order, leaving the magnitude of the separation at 10 meV10\,\mathrm{meV}. The two degeneracies, four and six, sum to ten.

Take it with you

  • An allowed LS term contains all J values permitted by the angular-momentum triangle rule.
  • The effective spin-orbit constant has energy units and determines level ordering.
  • The interval rule diagnoses an isolated LS-coupled term; it is not a universal spectral law.

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