advanced33 min studyLesson 653 in Physics

Vacuum energy and normal ordering

Separate volume and ultraviolet divergences, define free-vacuum Wick ordering, and identify what vacuum subtraction does and does not establish.

On this page

What you’ll understand

  • Distinguish an infinite volume factor from a divergent energy density.
  • Compute a free-vacuum subtraction at a stated regulator.
  • Explain why normal ordering is not a universal interacting or gravitational renormalization prescription.

The free-field vacuum is not a state in which every oscillator coordinate is zero. It has fluctuations and a zero-point contribution from each mode. Summing those contributions exposes both the infinite spatial volume and the unlimited number of short-wavelength modes. Normal ordering is a useful free-vacuum convention that subtracts specified contractions. It changes operator definitions and the chosen energy zero, while leaving free-particle gaps intact. It does not eliminate every ultraviolet problem or solve the gravitational vacuum-energy question.

Two limits produce different infinities

Place a real scalar field in a periodic box and keep finitely many modes. Its vacuum energy is then a finite sum of half the positive frequency of each retained oscillator. Enlarging the box increases the number of modes proportionally to volume. Dividing by volume removes that extensive factor, but increasing the momentum cutoff still adds more short-distance modes per unit volume. These are logically distinct limits and should be controlled separately.

For a massless field with a spherical sharp spatial cutoff, the density grows as the fourth power of cutoff in three space dimensions. This simple estimate diagnoses ultraviolet sensitivity. A spatial cutoff selects a frame, so its raw stress tensor cannot be assumed to have Lorentz-invariant vacuum equation of state. A regulator is a definition of an intermediate calculation, and symmetry-compatible renormalization requires more than reading a divergent energy integral as a measured cosmological constant.

E0=12∑pregulatedEp,ρ0(Λ)=12∫∣p∣<Λd3p(2π)3∣p∣=Λ416π2E_0=\frac12\sum_{\mathbf p}^{\mathrm{regulated}}E_{\mathbf p},\qquad \rho_0(\Lambda)=\frac12\int_{|\mathbf p|<\Lambda}\frac{d^3p}{(2\pi)^3}|\mathbf p|=\frac{\Lambda^4}{16\pi^2}
The second equality is for a massless real scalar in 3+1 dimensions, ℏ = c = 1. Λ has energy dimension one and ρ₀ dimension four. The box regulates volume; massless zero modes need omission or a small-mass prescription. The density integral is its continuum nonzero-momentum expression. The sharp spatial cutoff regulates high momentum but does not preserve boost invariance.↔ Scroll wide equations horizontally.

Ordering subtracts contractions in a chosen vacuum

For bosonic free modes, normal ordering puts creation operators to the left of annihilation operators without adding commutators during the definition of the ordered expression. Comparing it with the original operator then introduces the commutator terms. For a single oscillator coordinate, the ordered square differs from the original square by its vacuum variance. The resulting operator has zero vacuum expectation, even though the original coordinate continues to fluctuate in the vacuum.

For a field, the analogous contraction at coincidence is ultraviolet singular. One can first smear separated fields or retain a cutoff, subtract the chosen vacuum two-point function, and then define a Wick polynomial through an appropriate limit. The subtraction depends on the selected state and its singularity structure. A different background or vacuum need not use the same contraction. Normal ordering therefore records a reference construction rather than an assertion that local products of distributions were already ordinary operators.

q=a+a†2ω,[a,a†]=1,:q2:=q2−12ω,⟨n∣q2∣n⟩=2n+12ωq=\frac{a+a^{\dagger}}{\sqrt{2\omega}},\quad [a,a^{\dagger}]=1,\quad :q^2:=q^2-\frac1{2\omega},\quad \langle n|q^2|n\rangle=\frac{2n+1}{2\omega}
q is one unit-mass oscillator coordinate in natural units and ω > 0 has energy dimension one. The colons refer to its specified Fock vacuum. The finite oscillator formula illustrates the subtraction without a coincident-field divergence.↔ Scroll wide equations horizontally.

Free Wick products do not settle every energy problem

Higher powers have several possible pair contractions, so subtracting only their vacuum mean is generally insufficient to obtain the Wick-ordered operator. A regulated fourth power contains a quadratic subtraction and a constant term with combinatorial coefficients. These terms follow from reorganizing creation and annihilation operators. They matter when matrix elements between excited states are computed, not merely when the vacuum expectation is checked.

In flat-space free dynamics a constant energy subtraction leaves evolution of observables unchanged. Comparing boundary geometries, however, requires a common physical subtraction and regulator; independently erasing each geometry's vacuum energy would discard the difference of interest. Interacting theories need composite-operator renormalization and parameter counterterms beyond free normal ordering. Coupling to gravity adds a renormalized cosmological term and stress-tensor conditions. None of those tasks is completed merely by setting a free Fock-vacuum expectation to zero.

:ϕ4:C=ϕ4−6Cϕ2+3C2,C=⟨0∣ϕ2∣0⟩reg:\phi^4:_C=\phi^4-6C\phi^2+3C^2,\qquad C=\langle0|\phi^2|0\rangle_{\mathrm{reg}}
This identity is understood at a common finite Gaussian free-field regulator, with the same contraction C throughout. The continuum Wick polynomial requires an appropriate local subtraction procedure. It is not a claim that an arbitrary interacting φ⁴ product is defined by this one formula.↔ Scroll wide equations horizontally.

Subtract a variance without removing fluctuations

A unit-mass oscillator has ω = 2 in natural units and is in number state n = 3. Find its vacuum coordinate variance, its coordinate second moment in that state, and the expectation of :q²:.

  1. The vacuum variance is 1/(2ω)=1/41/(2\omega)=1/4. It is positive even though the mean coordinate is zero.

  2. The state second moment is (2n+1)/(2ω)=7/4=1.75(2n+1)/(2\omega)=7/4=1.75. Number eigenstates have no preferred coordinate sign.

  3. The normal-ordered expectation subtracts the vacuum contraction: 7/4−1/4=3/27/4-1/4=3/2. The coordinate variance itself remains 7/4.

The result

The vacuum variance is 1/4, the state second moment is 7/4, and ⟨:q²:⟩ is 3/2 in the corresponding coordinate units.

Explore the model

Interactive lab

Interactive lab · spectral

Adding short scales is a separate operation

Reset and set BOTH Mode count N to 2 and Coefficient decay p to 1; inspect the finite sine sum. Then Reset and set BOTH N to 4 and p to 1; predict added shorter spatial structure. This instrument uses sin(nx−t)/n^p with one common time frequency. It illustrates adding spatial modes, not relativistic dispersion, zero-point energy, a vacuum subtraction, or a convergence proof.

Adding short scales is a separate operationA finite sum of sin(nx − t)/nᵖ. Playback changes t; increasing the cutoff includes finer spatial scales. This is not a proof about a continuum limit or renormalization. Current readings: Sum at x = π/2: 0.867; Smallest wavelength: 2π / 5; Highest-mode coefficient: 0.2. All parameters are adjustable with the labeled controls below.01.573.144.716.28−2.56−1.2801.282.56x · radiansFinite sine sum
Finite sumHighest included mode
Sum at x = π/2
0.867
Smallest wavelength
2π / 5
Highest-mode coefficient
0.2
t = 0 s

A finite sum of sin(nx − t)/nᵖ. Playback changes t; increasing the cutoff includes finer spatial scales. This is not a proof about a continuum limit or renormalization. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA truncation makes a finite expression; identifying its physical continuum limit requires further analysis.

Check your understanding

What follows from normal ordering the free Hamiltonian in its chosen vacuum?

Try it yourself

For the stated massless sharp-cutoff estimate, double Λ at fixed volume. Find the vacuum energy-density ratio and the associated change in the shortest length scale proportional to 1/Λ. Explain what this does not predict.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use the power of Λ in the integral result, then distinguish a regulator parameter from a physical measurement.

Compare with the solution

The density ratio is 24=162^4=16, and the shortest retained length scale halves. At fixed volume the regulated total energy also increases by sixteen. This is a sensitivity estimate for the chosen noncovariant regulator, not a prediction that an observed cosmological constant changes when an analyst changes cutoff. A physical comparison requires renormalized parameters and a specified gravitational or boundary problem.

Take it with you

  • Infinite volume and ultraviolet mode density are separate sources of divergent vacuum energy.
  • Normal ordering subtracts contractions relative to a specified free vacuum.
  • Boundary comparisons, interactions, and gravity require more than an arbitrary reset of the energy zero.

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