advanced32 min studyLesson 253 in Physics

Separate bound fields from outgoing radiation

Identify the inverse-square and inverse-distance parts of the point-charge field and test their large-sphere flux.

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What you’ll understand

  • Classify the velocity and acceleration terms by their large-distance scaling.
  • Use the transverse wave relation with the correct SI factor of c.
  • Explain why nonzero Poynting flux near a charge is insufficient to establish radiation.

Electric and magnetic fields around a moving charge contain more than radiation. A charge's accompanying field transports and stores energy even when its velocity is constant. The useful distinction is asymptotic: acceleration produces a transverse field that decays slowly enough to carry finite energy through arbitrarily large spheres. We will separate that term from the faster-decaying velocity field, keeping all kinematic quantities at the retarded event and declaring which distance limit is being taken.

Two terms from one exact solution

Differentiate the Liénard–Wiechert potentials with the chain rule for retarded time. The result divides naturally into a term proportional to inverse distance squared and one proportional to inverse distance times the time derivative of beta. The first is often called the velocity field because it survives uniform motion. The second is the acceleration field. These names refer to terms in the prescribed-source solution, rather than two independently adjustable electromagnetic fields around a single physical trajectory.

The denominator kappa is one minus n dotted into beta. Its powers encode changes in emission time and geometry under differentiation. The acceleration term contains a nested cross product, which is perpendicular to n. Replacing the derivative of beta by ordinary acceleration requires dividing acceleration by c. Missing that conversion changes the field by a factor of light speed. The exact formulas are valid outside a smooth subluminal point-charge worldline in free space, before any far-zone approximation.

E=q4πϵ0[(1−β2)(n−β)κ3R2+n×[(n−β)×β˙]cκ3R]tr,κ=1−n⋅β\mathbf E=\frac{q}{4\pi\epsilon_0}\left[\frac{(1-\beta^2)(\mathbf n-\boldsymbol\beta)}{\kappa^3R^2}+\frac{\mathbf n\times[(\mathbf n-\boldsymbol\beta)\times\dot{\boldsymbol\beta}]}{c\kappa^3R}\right]_{t_r},\qquad \kappa=1-\mathbf n\cdot\boldsymbol\beta
β=v/c is dimensionless and its dot is d/dtᵣ, in s⁻¹. R is the retarded separation in metres, q is in coulombs, and E is in V/m. All bracketed quantities share the same retarded time.↔ Scroll wide equations horizontally.

A finite flux survives the sphere limit

For outgoing radiation the magnetic field equals n cross the electric radiation field divided by c. Hence the radial Poynting vector has magnitude epsilon zero times c times the squared radiation electric field. A sphere supplies an area proportional to distance squared, exactly compensating the inverse-square intensity. Radiation is thus diagnosed through a finite asymptotic flux, not merely a field that is visible at a chosen detector or a nonzero local cross product of fields.

By contrast, the velocity field squared contributes intensity scaling as inverse distance to the fourth power. Its integrated large-sphere contribution falls as inverse distance squared. The mixed velocity–acceleration contribution falls as inverse distance after integration. When comparing the same outgoing event at successively larger spheres, observation time must also advance by travel time. Holding reception time fixed can instead compare different stages of a source history and obscure this scaling argument.

Brad=1cn×Erad,Srad=ϵ0c∣Erad∣2n,R2Srad=O(1)\mathbf B_{\mathrm{rad}}=\frac1c\mathbf n\times\mathbf E_{\mathrm{rad}},\qquad \mathbf S_{\mathrm{rad}}=\epsilon_0c|\mathbf E_{\mathrm{rad}}|^2\mathbf n,\qquad R^2S_{\mathrm{rad}}=O(1)
B is in teslas and S in W/m². The last statement is a far-zone limit along a fixed outgoing emission history, with bounded source motion and the radiation coefficient held fixed.↔ Scroll wide equations horizontally.

Near-field transport is not automatically radiation

An observer near the charge can see substantial energy move between the source and its accompanying field. This stored energy can return later. A uniformly moving charge also has both electric and magnetic fields and generally a nonzero Poynting vector, but no acceleration term. The presence of magnetic field, temporal variation at a detector, or instantaneous outward flow through part of a nearby surface therefore does not independently establish radiative loss. Surface geometry and the complete energy balance matter.

In the slow-motion limit, kappa approaches one and the acceleration field becomes a transverse projection of acceleration divided by c squared and distance. Along the acceleration axis that leading field vanishes; sideways it is largest. The vector lab exposes this projection without representing a charge field. Predict the transverse component first, square it on paper to infer the relative angular intensity, and keep the distinction between field amplitude and intensity explicit throughout the comparison.

Erad≃q4πϵ0c2Rn×(n×a),∣Erad∣∝asin⁡θR(β≪1)\mathbf E_{\mathrm{rad}}\simeq\frac{q}{4\pi\epsilon_0c^2R}\mathbf n\times(\mathbf n\times\mathbf a),\qquad |\mathbf E_{\mathrm{rad}}|\propto\frac{a\sin\theta}{R}\quad(\beta\ll1)
a=dv/dtᵣ is acceleration in m/s², θ is its angle to n, and this leading nonrelativistic radiation field is in V/m. Its sign follows the nested cross product; its magnitude uses sinθ.↔ Scroll wide equations horizontally.

Separate distance scalings at one emission phase

At R=10 m, the magnitudes of two specified field terms are 12 V/m for the velocity term and 3 V/m for the acceleration term. At the same retarded geometry, find each term at R=30 m and compare their separate integrated-flux scalings.

  1. The distance increases by three. The inverse-square velocity amplitude therefore becomes 12/9=4/3 V/m, while the inverse-distance radiation amplitude becomes 3/3=1 V/m.

  2. The velocity-term intensity falls by 81, while the sphere area increases by nine. Its separate sphere-integrated contribution therefore falls by nine. This is a scaling comparison, not the complete field energy balance.

  3. The radiation intensity falls by nine and area rises by nine, leaving its sphere-integrated radiation power unchanged. Mixed terms have another scaling and cannot be replaced by a sum of the two separate squared magnitudes.

The result

At 30 m the amplitudes are 4/3 V/m and 1 V/m. The separate velocity contribution to large-sphere flux is one ninth as large, while the radiation contribution is unchanged.

Explore the model

Interactive lab

Interactive lab · vectors

Extract a transverse component

For each fresh run Reset and set BOTH controls: angle 30°, magnitude 2; then Reset and set angle 90°, magnitude 2. Regard x as the sightline. Predict transverse y components 1 and 2, hence relative squared projections 1 and 4. The vector model computes projections, not retarded Maxwell fields.

Extract a transverse componentPlayback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Current readings: x component: 1.393; y component: 0.975; Magnitude: 1.7. All parameters are adjustable with the labeled controls below.−7.46−3.7303.737.46−3.5−1.7501.753.5xyvvₓ = 1.39
Vectorx / y projectionsTrace marker
x component
1.393
y component
0.975
Magnitude
1.7
t = 0 s

Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forRadiation amplitude follows a transverse projection; intensity involves its square.

Check your understanding

Which large-distance behavior identifies a nonzero radiation field for a localized outgoing source?

Try it yourself

A slow charge accelerates at fixed magnitude. Compare leading radiation intensities at angles 30° and 90° to the acceleration at equal distance. Then double the observation distance for both.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Intensity is proportional to sin²θ/R², whereas field amplitude is proportional to sinθ/R.

Compare with the solution

At 30° the intensity is one quarter of the 90° value because sin²30°=1/4. Doubling both distances divides each intensity by four, preserving their 1:4 ratio. A sphere-integrated radiation power remains independent of radius when it encloses the same outgoing radiation history; intensity at a particular point does not.

Take it with you

  • Velocity fields decay as 1/R², while acceleration fields contain the 1/R radiation term.
  • Outgoing vacuum radiation obeys B=n×E/c and S=ε₀cE²n.
  • Local Poynting flow and asymptotic radiative loss answer different questions.

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