Coherence decides whether amplitudes or intensities add
Compare field-linear and intensity-linear imaging without confusing their transfer functions.
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The question for today
What you’ll understand
- Derive the cross term for two coherent image contributions.
- State when incoherent intensity convolution is valid.
- Interpret coherent and incoherent cutoff frequencies with the correct input quantity.
The same lens can give different images of an object under different illumination. Its aperture has not changed, but the correlations between object points have. Coherent imaging adds complex fields before detection, preserving interference between their contributions. Spatially incoherent imaging loses those cross terms on averaging and adds intensities. The distinction changes the forward model, the meaning of a transfer function, and which object information can be inferred from a recorded intensity.
Field linearity precedes square-law detection
For a deterministic coherent field, propagation through a linear optical system is linear in complex amplitude. In a shift-invariant region the image field is the convolution of the object field with an amplitude impulse response a. The camera then records its modulus squared, up to a calibration factor. This final step is nonlinear in the object field. Consequently there is generally no single intensity PSF that convolves arbitrary coherent object intensities to give their camera image.
Consider two object contributions that produce fields A and B at one detector position. Their detected intensity contains two separate squared amplitudes and a cross term that depends on relative phase. Changing phase can alter the intensity without changing either individual contribution. A phase-only object can thus become visible after propagation or filtering even though its transmitted intensity is uniform in its own plane. Predicting that image requires its phase distribution and the coherent propagation operator, not only its local brightness.
Averaging produces the incoherent rule
For spatially incoherent object emission, distinct points have zero mutual field correlation on the measurement average. Averaging the squared field sum eliminates cross terms between different points. The resulting image intensity is the convolution of object intensity with the normalized squared modulus of the amplitude impulse response. Temporal narrowband assumptions are still needed if one wants a single wavelength-dependent impulse response; a broadband camera usually adds wavelength-dependent intensity images with spectral weights.
Partial coherence lies between these cases and requires the mutual intensity, a two-position correlation, rather than just one field or one intensity map. The two-point formula retains a cross term multiplied by a complex degree of coherence. Saying that incoherent light never interferes is misleading: a beam can interfere with a sufficiently matched copy of itself. The relevant statement here is that the specific distinct object-point contributions are mutually uncorrelated under the observation average.
A doubled support is not an unrestricted resolution claim
For a clear scalar paraxial pupil with numerical aperture NA at wavelength λ, the coherent amplitude transfer function has transverse support up to NA/λ in object-space cycles per metre. The incoherent intensity OTF can extend to 2NA/λ because it is a pupil autocorrelation. These act on different input quantities. Comparing the numbers alone does not prove that incoherent imaging is always superior: contrast, object type, noise, phase sensitivity, and a chosen resolution criterion all affect the practical comparison.
Use the wave lab to test the cross term directly. Reset and set both controls to phase zero degrees and ratio one, predicting field amplitude two. Reset and set phase 180 degrees and ratio one, predicting zero. At a quarter-cycle difference the amplitude is the square root of two. The plotted sum is a field, not measured intensity; square its amplitude to make the optical comparison. This fully coherent pair cannot be changed into incoherent illumination by simply selecting a fixed phase.
Work it through
Three phases at one detector point
Two coherent object contributions each give unit field amplitude at a selected image point. Find the intensities for relative phases zero, π/2, and π radians. Compare with mutually incoherent contributions of the same individual intensities.
Each contribution separately has intensity one. For a coherent pair the total is 2+2cosφ, since the product of their amplitudes is one.
At phases zero, π/2, and π, the cosines are one, zero, and minus one. The recorded intensities are therefore four, two, and zero.
For mutually incoherent contributions the averaged cross term vanishes. Their recorded mean is always one plus one, or two, independent of an arbitrary chosen phase label.
Coherent intensities are 4,2,0; the incoherent mean is 2. Equal individual intensities do not determine a coherent image.
The living notebook
Explore the model
Interactive lab · waves
Phase changes an image contribution
Reset and set BOTH controls to phase 0° and ratio 1; predict sum amplitude 2. Reset and set phase 180° and ratio 1; predict zero. Square amplitudes to compare intensity. Both runs remain fully coherent.
- Sum at x = 0
- 0.866
- Resultant amplitude
- 1.732
- Phase difference
- 60°
Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA fixed phase setting changes coherent interference; it does not implement incoherent averaging.
Pause & reason
Check your understanding
Your turn
Try it yourself
At a detector point, two coherent field amplitudes have magnitudes one and one half and relative phase π. Compute total intensity and compare with the incoherent mean. Find the visibility if their relative phase is scanned coherently.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use the squared difference for destructive interference, then obtain extrema from the squared sum and difference.
Compare with the solution
The destructive intensity is (1−0.5)²=0.25. The incoherent mean is 1²+0.5²=1.25. A phase scan gives maximum (1+0.5)²=2.25 and minimum 0.25, so visibility is (2.25−0.25)/(2.25+0.25)=0.8. A nonzero minimum here comes from amplitude imbalance, not incomplete coherence.
Keep the idea
Take it with you
- Coherent propagation is field-linear and detection is quadratic.
- Spatial incoherence makes the averaged image intensity linear in object intensity.
- Amplitude and intensity transfer cutoffs compare different objects.
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