advanced28 min studyLesson 229 in Physics

Phase matching lets weak sources build coherently

Derive the finite-length sinc factor and distinguish energy matching from momentum matching.

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What you’ll understand

  • Compute collinear wavevector mismatch for three-wave mixing.
  • Integrate a uniform undepleted nonlinear source along a crystal.
  • Distinguish temporal coherence length from nonlinear coherence length.

A nonlinear crystal can produce the correct new frequency locally and still give a weak output. Radiation generated at different positions must arrive with phases that reinforce one another. Dispersion can make the generated wave slip out of phase with the nonlinear source that drives it. Phase matching controls this accumulation. A short derivation with a constant pump reveals both the familiar sinc envelope and the assumptions hidden behind a simple squared-length conversion rule.

Frequency matching and wavevector matching differ

For sum-frequency generation in a time-independent material, the source frequency is ω₃=ω₁+ω₂. This temporal relation also expresses the photon-energy balance for the corresponding parametric process. Each propagating wave has wavevector magnitude n(ω)ω/c for its particular polarization and direction. Since refractive index depends on frequency, the frequency sum does not generally imply that the output wavevector equals the sum of the inputs. Efficient buildup requires their vector mismatch to be sufficiently small over the interaction length.

For collinear second-harmonic generation, define mismatch Δk=k₂ω−2kω. In a normally dispersive isotropic transparent material this is typically nonzero because the two frequencies see different refractive indices. Birefringent phase matching uses different polarization-dependent indices, with angle or temperature tuning, to reduce mismatch. Material transparency and a nonzero effective tensor coefficient remain necessary. Solving an index equality for a hypothetical material does not by itself prove that an accessible crystal orientation supports the desired interaction.

ω3=ω1+ω2,Δk=k3−k1−k2,ΔkSHG=2ωc[n(2ω)−n(ω)]\omega_3=\omega_1+\omega_2,\qquad \Delta\mathbf k=\mathbf k_3-\mathbf k_1-\mathbf k_2,\qquad \Delta k_{\mathrm{SHG}}=\frac{2\omega}{c}[n(2\omega)-n(\omega)]
Angular frequencies are in rad/s and wavevectors or Δk are in inverse metres. The final expression assumes collinear propagation with specified effective indices; vector matching is required more generally.↔ Scroll wide equations horizontally.

Integrate all the source slices

Take plane waves, negligible absorption, constant pumps, and a uniform effective nonlinearity. In the slowly varying envelope approximation the generated envelope is a constant coupling factor times the integral of exp(−iΔkz) along the crystal. The exponential tracks the phase of each source slice relative to the generated carrier. Evaluate the integral by centering its phase at the midpoint. The result is a length factor multiplied by a sinc and an overall phase that does not affect the output intensity.

At exact matching the amplitude grows linearly with length and the generated intensity grows quadratically, but only until the neglected physics becomes appreciable. Away from matching the first intensity zero occurs at |Δk|L=2π. Define nonlinear coherence length as π/|Δk|, the length over which the source and generated field slip by π. This is unrelated to the temporal coherence length set by laser linewidth. At one nonlinear coherence length the uniform-source intensity is already reduced to 4/π² of its perfectly matched value for that same length.

A3(L)=C∫0Le−iΔkz dz=CLe−iΔkL/2sinc⁡ ⁣(ΔkL2),ℓc=π∣Δk∣A_3(L)=C\int_0^L e^{-i\Delta k z}\,dz=CL e^{-i\Delta k L/2}\operatorname{sinc}\!\left(\frac{\Delta k L}{2}\right),\qquad \ell_c=\frac{\pi}{|\Delta k|}
sinc(x)=sin(x)/x with sinc(0)=1. C is a constant source coefficient with amplitude-per-metre units. L and ℓ_c are metres; the formula assumes undepleted plane-wave pumps, uniform coupling, and negligible loss.↔ Scroll wide equations horizontally.

Engineering accumulation without ignoring limits

Quasi-phase matching reverses the sign of the effective nonlinearity periodically. Its reciprocal grating vector compensates the wavevector mismatch; a first-order period is 2π/|Δk| for a simple collinear design. Sign reversals keep successive contributions useful but generally reduce the effective coupling relative to ideal uniform perfect matching. This engineered spatial modulation does not change the frequency sum. Focused beams, finite pulse walk-off, absorption, and pump depletion require more complete coupled propagation models.

The wave lab shows only how two coherent contributions can add or cancel. Reset and set both controls to phase zero degrees and ratio one, predicting amplitude two. Reset and set phase 180 degrees and ratio one for a new run, predicting zero. Regard them as two source-slice contributions brought to one observation point. Their fixed equal frequency permits the phase comparison, but they are not pump and harmonic fields. The lab has no crystal length, wavevector mismatch, poling, or energy-conversion calculation.

Compare one coherence length with perfect matching

A uniform undepleted source has wavevector mismatch Δk=π per millimetre. For a crystal length of 1.0 mm, calculate the nonlinear coherence length and the output intensity relative to an otherwise identical perfectly matched crystal of the same length. Then locate the first zero as length increases.

  1. The coherence length is π divided by |Δk|, giving 1.0 mm. Keep mismatch and length in consistent units; in SI the mismatch is 1000π m⁻¹.

  2. At length 1.0 mm, the sinc argument ΔkL/2 is π/2. Its value is 2/π, so the intensity ratio is (2/π)²≈0.405.

  3. The first nontrivial zero has sinc argument π. Solving ΔkL/2=π gives L=2.0 mm, twice the nonlinear coherence length, within the same constant-pump idealization.

The result

The nonlinear coherence length is 1.0 mm, the one-millimetre intensity ratio is about 0.405, and the first zero occurs at 2.0 mm.

Explore the model

Interactive lab

Interactive lab · waves

Contributions accumulate with relative phase

Reset and set BOTH controls to phase 0° and ratio 1; predict amplitude 2. Reset and set phase 180° and ratio 1; predict zero. These are fixed-frequency source-contribution analogues, with no nonlinear conversion or length control.

Contributions accumulate with relative phaseTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forFrequency-allowed sources can cancel in the output when their accumulated phases differ.

Check your understanding

In the uniform undepleted plane-wave model, when does the first generated-intensity zero occur?

Try it yourself

A device has positive mismatch Δk=400π m⁻¹. Find the first-order quasi-phase-matching period and the sign-reversal domain length for a 50% duty-cycle grating. Explain whether the grating changes the sum-frequency relation.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The grating wavevector has magnitude 2π/Λ. A sign reversal occupies half of one full period.

Compare with the solution

Set 2π/Λ=400π m⁻¹, giving Λ=0.005 m=5.0 mm. Each equal sign domain is Λ/2=2.5 mm, also π/|Δk|. The static grating supplies spatial wavevector, not temporal frequency, so ω₃=ω₁+ω₂ still holds. Its effective coupling and conversion efficiency require the grating Fourier coefficient and propagation conditions.

Take it with you

  • Frequency matching does not automatically match wavevectors in a dispersive medium.
  • Uniform-source buildup gives a sinc amplitude and a squared sinc intensity.
  • Quasi-phase matching adds spatial periodicity while preserving the frequency relation.

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