advanced27 min studyLesson 497 in Physics

Acoustic and optical phonon branches

Count lattice branches from primitive-cell degrees of freedom, interpret low-wavevector motion and polarization, and separate optical branch labels from optical activity.

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What you’ll understand

  • Count acoustic and optical branches in a stable three-dimensional crystal.
  • Interpret in-phase translation and internal relative motion at long wavelength.
  • Distinguish branch character, polarization, and electromagnetic selection rules.

Acoustic and optical identify different kinds of collective lattice motion. The names are useful, but they can obscure simple counting rules and important exceptions. Three displacement components per atom determine the number of branches; translation symmetry explains three acoustic branches; internal relative motion supplies the rest. We will connect this count to actual displacement patterns and to quantized mode populations, while avoiding the false conclusion that every optical branch must absorb light.

Count coordinates in the primitive cell

For r atoms per primitive cell in a three-dimensional crystal, the dynamical matrix has 3r eigenvalues at each independent wavevector. In a mechanically stable unpinned bulk crystal with no extra accidental zero modes, three branches approach zero frequency at the zone centre because of rigid translations. These are acoustic branches. The remaining 3r−33r-3 are optical branches, describing internal cell motion with finite zone-centre restoring frequencies. A monoatomic Bravais crystal therefore has no optical branches in its primitive description.

For a periodic sample with Nc primitive cells, each branch has Nc independent wavevectors. Multiplying gives 3rNc3rN_c, exactly three times the total atom count. The acoustic zero modes at the zone centre still belong in the count of mechanical coordinates, although uniform translations are not finite-frequency oscillators. Enlarging the chosen cell folds branches and can make a primitive acoustic mode appear as a finite-frequency folded branch. That label change does not create a new physical coordinate or a new species of vibration.

Nbranches=3r,Nac=3,Nopt=3r−3,Ncoordinates=3rNc=3NatomN_{\mathrm{branches}}=3r,\qquad N_{\mathrm{ac}}=3,\qquad N_{\mathrm{opt}}=3r-3,\qquad N_{\mathrm{coordinates}}=3rN_c=3N_{\mathrm{atom}}
These counts assume a stable unpinned three-dimensional periodic crystal and a true primitive cell. Lower-dimensional membranes, substrates, extra symmetries, or instabilities require their own low-frequency analysis.↔ Scroll wide equations horizontally.

Polarization and internal phase are different labels

At long wavelength an acoustic mode moves atoms within each cell nearly together, while neighboring cells vary slowly in phase. In an isotropic elastic limit one acoustic polarization is longitudinal and two are transverse. In anisotropic crystals the eigenvectors may be only approximately longitudinal or transverse away from special symmetry directions. Acoustic does not mean longitudinal: transverse shear waves are acoustic as well. Nor does an acoustic branch have to remain linear throughout the Brillouin zone. Its low-frequency character is a statement about the zone-centre limit.

An optical zone-centre mode has relative motion of basis atoms. For a two-atom one-dimensional example, its physical displacement amplitudes obey zero cell centre-of-mass motion, so the heavier atom has a smaller amplitude of opposite sign. Electromagnetic optical activity requires an oscillating dipole or another allowed coupling, determined by charges, symmetry, and polarization. Some optical modes are infrared inactive, while Raman scattering has different selection rules. The historical branch name is therefore not a guarantee of visibility in a particular optical measurement.

acoustic at q→0: um≃uM,two-atom optical at q=0: mum+MuM=0,nˉqν=1eℏωqν/(kBT)−1\text{acoustic at }q\to0:\ u_m\simeq u_M,\qquad \text{two-atom optical at }q=0:\ mu_m+Mu_M=0,\qquad \bar n_{\mathbf q\nu}=\frac{1}{e^{\hbar\omega_{\mathbf q\nu}/(k_BT)}-1}
The displacement relations are physical, unweighted amplitudes in the simple two-atom chain. The final formula is the equilibrium Bose occupation of a positive-frequency harmonic mode with zero phonon chemical potential.↔ Scroll wide equations horizontally.

Occupation is not the number of available modes

Quantization assigns a mode energy ℏω(n+1/2)\hbar\omega(n+1/2), where n is a nonnegative integer. The available mode count is fixed by the mechanical coordinates; temperature changes their mean occupation rather than creating additional branches. Low-frequency acoustic modes are readily thermally excited, while a high-frequency optical mode can remain weakly populated when its energy quantum exceeds thermal energy. The zero-point contribution remains even when the mean excitation number tends to zero, but its temperature-independent part does not contribute to harmonic constant-volume heat capacity.

Polar crystals add another distinction: a long-wavelength longitudinal optical displacement can create a macroscopic electric field and acquire a different frequency from a transverse optical displacement. Correct treatment requires the effective charges and dielectric response, not simply the short-range spring matrix. Degeneracies, branch crossings, and mixing can complicate labels at finite wavevector. Follow the eigenvectors and symmetry as well as the plotted frequencies, and specify whether a claimed optical splitting follows from a physical long-range interaction or merely from a chosen toy force model.

Count branches and populate one optical oscillator

A stable unpinned three-dimensional crystal has four atoms per primitive cell and 1000 periodic cells. Count acoustic and optical branches and all displacement coordinates. A positive-frequency optical mode has ℏω=kBTln⁡3\hbar\omega=k_BT\ln3; find its equilibrium mean excitation number and mean total oscillator energy.

  1. Four atoms give twelve branches. Three are acoustic and nine optical. Multiplying all twelve by 1000 wavevectors gives 12000 coordinates, matching three components for 4000 atoms.

  2. The selected oscillator has eℏω/(kBT)=3e^{\hbar\omega/(k_BT)}=3. Its mean phonon number is nˉ=1/(3−1)=1/2\bar n=1/(3-1)=1/2. This does not mean only half of the mode exists; it is an ensemble occupation average.

  3. Including zero-point energy, ⟨E⟩=ℏω(nˉ+1/2)=ℏω=kBTln⁡3\langle E\rangle=\hbar\omega(\bar n+1/2)=\hbar\omega=k_BT\ln3. The excitation energy alone is half of that value. The uniform acoustic translations require separate zero-mode handling rather than insertion into this positive-frequency oscillator formula.

The result

The crystal has 3 acoustic and 9 optical branches, totaling 12000 displacement coordinates. The specified optical mode has mean occupation one-half and total mean energy kBT ln3.

Explore the model

Interactive lab

Interactive lab · waves

In-phase and opposite-phase displacement analogies

Reset and set BOTH Phase difference = 0° and Amplitude ratio = 1; predict aligned component waves. For a fresh run, Reset and set Phase difference = 180° and Amplitude ratio = 0.5; predict opposite component phases with unequal amplitudes. Inspect the component curves or Play each run.

In-phase and opposite-phase displacement analogiesTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThis fixed-frequency wave pair illustrates relative phase only. It does not enforce centre-of-mass weighting, compute acoustic or optical frequencies, or model electromagnetic optical activity.

Check your understanding

How many optical branches occur in a stable unpinned three-dimensional primitive crystal with three atoms per cell?

Try it yourself

In the simple diatomic chain, masses m = 2 units and M = 6 units have a zone-centre optical displacement um=0.30 A˚u_m=0.30\,\mathrm{\mathring A}. Find the heavy-atom amplitude. State the corresponding acoustic amplitude relation and the acoustic/optical branch counts for a three-dimensional two-atom primitive crystal.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use physical centre-of-mass motion rather than equal mass-weighted eigenvector components. Count three coordinates per atom only for the three-dimensional crystal.

Compare with the solution

For the optical chain mode, 2(0.30)+6uM=02(0.30)+6u_M=0, so uM=−0.10 A˚u_M=-0.10\,\mathrm{\mathring A}. Its minus sign denotes opposite motion. The acoustic zone-centre relation is uM=umu_M=u_m, independent of mass for a rigid translation. A stable unpinned three-dimensional two-atom primitive crystal has six branches: three acoustic and three optical. The scalar chain itself has only one acoustic and one optical branch because it retained one displacement direction per atom.

Take it with you

  • Primitive-cell coordinates fix branch count independently of temperature or occupation.
  • Acoustic branches include transverse motion; optical labels do not guarantee optical activity.
  • Physical amplitudes, mass weighting, and electromagnetic coupling supply different information.

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