advanced29 min studyLesson 499 in Physics

Anharmonicity and thermal expansion

Derive a weak-asymmetry shift in mean bond length, relate volume-dependent phonons to expansion, and distinguish quasiharmonic thermodynamics from full anharmonic dynamics.

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What you’ll understand

  • Explain why a symmetric fixed harmonic well does not shift its mean on heating.
  • Compute a leading classical expansion from a weak cubic potential term.
  • Interpret mode Grüneisen parameters and the limits of quasiharmonic predictions.

Heating a harmonic oscillator increases its displacement variance, but does not move the centre of a symmetric potential well. Thermal expansion therefore requires physics beyond a fixed quadratic energy. An asymmetric bond potential supplies a simple classical mechanism, while volume-dependent phonon frequencies provide a bulk thermodynamic description. We will connect these viewpoints, declare their approximation regimes, and distinguish a frequency shift with volume from the scattering processes that give phonons finite lifetimes.

Asymmetry shifts the mean, not just the variance

Let y denote a bond-length change from its zero-temperature minimum and expand the local potential as U=Ky2/2+Ay3/3+Cy4/4U=Ky^2/2+Ay^3/3+Cy^4/4. Positive K makes the reference minimum locally stable, while higher terms provide a physically bounded potential. The pure quadratic Boltzmann distribution is even in y, so its mean vanishes at every classical temperature. Its variance grows as thermal energy divided by K. Larger excursions alone are therefore insufficient to explain a larger average bond length.

Treat a weak cubic term perturbatively in the classical canonical distribution. Expanding the Boltzmann weight to first order in A gives a mean proportional to minus the Gaussian fourth moment. The fourth moment is three times the variance squared, producing the result below. A negative cubic coefficient makes the potential softer on its positive-extension side and shifts the mean positively. This is a local weak-anharmonic approximation; a cubic polynomial alone is unbounded and cannot define a global equilibrium ensemble without stabilizing higher terms.

⟨y⟩≃−A kBTK2,⟨y2⟩0=kBTK,∣A∣kBT/KK≪1,CkBTK2≪1\langle y\rangle\simeq-\frac{A\,k_BT}{K^2},\qquad \langle y^2\rangle_0=\frac{k_BT}{K},\qquad \frac{|A|\sqrt{k_BT/K}}{K}\ll1,\quad\frac{Ck_BT}{K^2}\ll1
This leading classical result uses U = Ky²/2 + Ay³/3 + Cy⁴/4 near one stable well. K, A, and C have units energy/length², energy/length³, and energy/length⁴; the final two conditions keep corrections small over thermal excursions.↔ Scroll wide equations horizontally.

Bulk expansion follows phonon free energy

A crystal's equilibrium volume minimizes free energy at the applied pressure. The quasiharmonic approximation computes harmonic phonons separately at different volumes and uses their volume-dependent frequencies in the vibrational free energy. It captures an important part of anharmonic thermodynamics even though each fixed-volume calculation remains harmonic. A mode Grüneisen parameter measures minus the logarithmic frequency derivative with respect to volume. Positive values mean that expansion softens the mode, increasing its thermal entropy and tending to favor a larger equilibrium volume.

Differentiating the vibrational pressure with temperature gives a heat-capacity-weighted Grüneisen expression for volume expansion. The denominator contains the isothermal bulk modulus, which penalizes volume change. Modes contribute according to their own heat capacities, so the effective weighting can change with temperature as different frequencies become populated. Negative mode parameters can produce negative expansion when their weighted contribution dominates. Geometry, collective transverse motion, electronic effects, and structural proximity can all matter; a simple picture of every individual bond lengthening is not a universal explanation.

γqν=−∂ln⁡ωqν∂ln⁡V,αV=1V(∂V∂T)P≃1BTV∑qνγqνCqν\gamma_{\mathbf q\nu}=-\frac{\partial\ln\omega_{\mathbf q\nu}}{\partial\ln V},\qquad \alpha_V=\frac1V\left(\frac{\partial V}{\partial T}\right)_P\simeq\frac{1}{B_TV}\sum_{\mathbf q\nu}\gamma_{\mathbf q\nu}C_{\mathbf q\nu}
This quasiharmonic vibrational expression uses dimensionless mode gamma, mode heat capacity C in J/K, volume in m³, and isothermal bulk modulus B_T in Pa. Alpha_V consequently has units K⁻¹. Additional electronic or other thermal contributions require separate accounting.↔ Scroll wide equations horizontally.

Frequency shifts and finite lifetimes are different effects

A quasiharmonic frequency changes when the equilibrium volume changes, but the fixed-volume modes in that approximation still have infinite harmonic lifetime. Explicit cubic and quartic interactions between normal coordinates also produce temperature-dependent self-energy shifts and scattering linewidths. Those effects are needed for intrinsic thermal resistance and can matter strongly near structural instabilities. A calculation can therefore predict expansion reasonably while still omitting the interactions necessary to predict a measured phonon lifetime or thermal conductivity.

The local classical bond derivation is inappropriate when quantum freezing controls the populated fluctuations; quantum free energies then supply the correct temperature dependence. Quasiharmonic theory also fails when large excursions, unstable harmonic modes, or strong explicit anharmonicity invalidate its fixed-volume oscillator description. Compare its predictions with structural data and mode behavior rather than assuming that heating always gives positive linear expansion. For small isotropic strain, the linear expansion coefficient is one-third of the volumetric coefficient; confusing those two definitions creates a factor-of-three error even when the underlying thermodynamics is correct.

A weakly asymmetric bond well

A classical illustrative bond has K=4 eV A˚−2K=4\,\mathrm{eV\,\mathring A^{-2}}, A=−2 eV A˚−3A=-2\,\mathrm{eV\,\mathring A^{-3}}, and stabilizing C=0.30 eV A˚−4C=0.30\,\mathrm{eV\,\mathring A^{-4}}. At kBT=0.08 eVk_BT=0.08\,\mathrm{eV}, estimate the mean extension and check the weak-anharmonic conditions.

  1. The harmonic variance is kBT/K=0.08/4=0.02 A˚2k_BT/K=0.08/4=0.02\,\mathrm{\mathring A^2}, so its root-mean-square fluctuation is about 0.141 A˚0.141\,\mathrm{\mathring A}. This width alone would not shift a purely harmonic mean.

  2. The first-order mean is −AkBT/K2=−(−2)(0.08)/16=0.010 A˚-Ak_BT/K^2=-(-2)(0.08)/16=0.010\,\mathrm{\mathring A}. Its positive sign agrees with the negative cubic coefficient's softer extension side.

  3. The cubic perturbation parameter is 2(0.141)/4≃0.0712(0.141)/4\simeq0.071 and the quartic one is 0.30(0.08)/16=0.00150.30(0.08)/16=0.0015. Both are small, supporting the leading estimate within this classical local model. The positive quartic term also prevents the cubic truncation's unbounded-energy problem.

The result

The predicted mean bond extension is approximately 0.010 ångström, smaller than the thermal fluctuation width, with small perturbative corrections under the stated classical assumptions.

Explore the model

Interactive lab

Interactive lab · function

A symmetric harmonic well has equal opposite displacements

Reset and set BOTH Coefficient a = 0.5 and Position x = 1; predict value 0.5 and slope 1. For a fresh comparison, Reset and set a = 0.5 and x = −1; predict the same value and slope −1. Inspect paused readouts or Step.

A symmetric harmonic well has equal opposite displacementsThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe quadratic illustrates harmonic symmetry. It has no cubic or quartic term, thermal distribution, average bond length, volume, or expansion coefficient, so it cannot simulate anharmonic expansion.

Check your understanding

Why can a fixed symmetric harmonic well have growing thermal fluctuations but no thermal shift of its mean?

Try it yourself

A quasiharmonic isotropic solid has heat-capacity-weighted gamma = 2, volumetric heat capacity 2×106 J m−3 K−12\times10^6\,\mathrm{J\,m^{-3}\,K^{-1}}, and bulk modulus 100 GPa. Estimate alphaV, the linear coefficient, and the fractional volume increase for a small 50 K rise with constants held fixed.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Using heat capacity per volume cancels V in the Grüneisen formula. Divide the volumetric coefficient by three for isotropic linear expansion.

Compare with the solution

The volumetric coefficient is αV=2(2×106)/(1011)=4×10−5 K−1\alpha_V=2(2\times10^6)/(10^{11})=4\times10^{-5}\,\mathrm{K^{-1}}. The isotropic linear coefficient is αL=αV/3≃1.33×10−5 K−1\alpha_L=\alpha_V/3\simeq1.33\times10^{-5}\,\mathrm{K^{-1}}. For the stated small rise, ΔV/V≃αVΔT=0.002\Delta V/V\simeq\alpha_V\Delta T=0.002, or 0.2 percent. The constant-parameter estimate neglects changes of gamma, heat capacity, and bulk modulus over the interval and should not be extrapolated through a phase transition.

Take it with you

  • A fixed harmonic well broadens on heating but needs asymmetry to shift its mean.
  • Quasiharmonic expansion uses volume-dependent mode frequencies and heat-capacity weighting.
  • Explicit anharmonic scattering, quantum effects, and large excursions require additional physics.

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