research38 min studyLesson 697 in Physics

Nonrelativistic effective field theories

Separate rest energy from residual motion and explain how a large scattering length changes the organization of contact interactions.

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What you’ll understand

  • Assign distinct velocity scaling to energy and spatial momentum.
  • Evaluate the first relativistic correction to a nonrelativistic dispersion.
  • Diagnose when contact interactions need nonperturbative resummation.

A heavy particle moving slowly is still a low-energy degree of freedom when its residual motion matters. Removing its rest-energy oscillation does not mean deleting the particle. Nonrelativistic EFTs exploit the hierarchy between the mass, momentum, and kinetic energy, while retaining fields for particles near their mass shell. They can also describe strong low-energy scattering: a small momentum relative to the interaction range does not always imply that every contact interaction can be treated in ordinary perturbation theory.

Strip the rest oscillation and keep the particle

For a stable massive field in an appropriate particle-number sector, factor out the rapid phase associated with its rest mass. Modes corresponding to antiparticles or pair creation are then separated by an energy of order the mass and can be matched into local coefficients when inaccessible. The remaining field varies slowly. Its spatial momentum scales as mv and its residual energy as mv squared, with v much smaller than one. Time derivatives and spatial derivatives therefore have different velocity orders.

The leading kinetic equation is first order in time and second order in space. Expanding the relativistic dispersion gives a positive quadratic kinetic energy and a negative quartic momentum correction. The latter is a small perturbation when p/m is small; treating a truncated negative quartic as a globally valid Hamiltonian at arbitrarily large p would extend it beyond its purpose. Coupling to gauge fields requires gauge-covariant derivatives and matching additional spin or magnetic interactions rather than only replacing an energy formula.

Ekin=m2+p2−m=p22m−p48m3+O(p6/m5),∣p∣∼mv,Ekin∼mv2E_{\mathrm{kin}}=\sqrt{m^2+\mathbf p^2}-m=\frac{\mathbf p^2}{2m}-\frac{\mathbf p^4}{8m^3}+O(p^6/m^5),\qquad |\mathbf p|\sim mv,\quad E_{\mathrm{kin}}\sim mv^2
Natural units are used, m and p are energies, and v is a small velocity parameter. The rest energy has been subtracted. This expansion assumes a relativistic one-particle dispersion and does not include an interaction potential.↔ Scroll wide equations horizontally.

A low-energy pole can enhance otherwise short-range interactions

For elastic S-wave scattering below inelastic thresholds, the effective-range expansion expresses momentum times cotangent of the phase shift as a series in momentum squared. The scattering length a and effective range re have length units. The amplitude has an additional imaginary term fixed by elastic unitarity. If a is comparable to the interaction range R, a perturbative low-momentum expansion may be suitable. A much larger scattering length introduces a new low-energy scale, inverse absolute a, below inverse R.

When k times a is order one or larger while kR remains small, repeatedly inserting the leading contact interaction is not suppressed. Summing those iterations can produce the shallow pole or enhanced scattering required by the data. A reorganized counting treats the enhanced contribution at leading order while still expanding range corrections systematically. This is an EFT with a controlled low-energy expansion, even though its leading contact sector is nonperturbative.

kcot⁡δ0=−1a+re2k2+⋯ ,f0(k)=1kcot⁡δ0−ik,f0(k)≃1−1/a−ik(∣re∣k2 small)k\cot\delta_0=-\frac1a+\frac{r_e}{2}k^2+\cdots,\qquad f_0(k)=\frac1{k\cot\delta_0-ik},\qquad f_0(k)\simeq\frac1{-1/a-ik}\quad(|r_e|k^2\text{ small})
k is relative momentum in inverse-length units, δ0 is the elastic S-wave phase shift, and f0 has length units. The final leading form keeps the unitarity term to all orders while neglecting effective-range and higher shape terms; it requires their size to be checked against the retained denominator.↔ Scroll wide equations horizontally.

Different low-energy systems need different counting rules

Pionless nuclear EFT, nonrelativistic atomic EFT, and nonrelativistic gauge theories retain different degrees of freedom and interactions. Long-range photons, explicit pions, or several closely spaced thresholds can introduce scales beyond the simple contact example. A shallow bound state can require a special leading treatment even when the underlying couplings are not weak. It is therefore unsafe to infer a universal diagram hierarchy solely from the canonical dimension of a contact operator.

Regularization and subtraction should make the chosen counting transparent without changing physical scattering. Different schemes reshuffle loop contributions and contact coefficients, so a large coefficient can partly reflect the chosen convention. Physical low-energy scales, the pole position, and observable convergence supply the stronger diagnostics. Relativistic corrections and range corrections can be independent expansion parameters; satisfying p/m much smaller than one does not by itself establish that a particular effective-range truncation meets a requested precision.

The first relativistic correction is small but signed

A free particle has m=1.0 GeV and momentum p=0.10 GeV. Compute its nonrelativistic kinetic energy, the first relativistic correction, and their sum in MeV. State the correction relative to the leading kinetic energy.

  1. The leading term is p2/(2m)=0.0100/2=0.0050 GeV=5.0 MeVp^2/(2m)=0.0100/2=0.0050\,\mathrm{GeV}=5.0\,\mathrm{MeV}. The rest energy is not included in this number.

  2. The correction is −p4/(8m3)=−0.0001/8=−0.0000125 GeV=−0.0125 MeV-p^4/(8m^3)=-0.0001/8=-0.0000125\,\mathrm{GeV}=-0.0125\,\mathrm{MeV}. Its negative sign follows the expansion of the square root.

  3. The sum is 4.9875 MeV, and the fractional correction is −0.0125/5=−0.0025, or −0.25 percent. The small expansion parameter p/m=0.10 supports the expansion; the exact kinetic energy is about 4.98756 MeV.

The result

The leading energy is 5.0 MeV, its first correction is −0.0125 MeV, and the retained result is 4.9875 MeV.

Explore the model

Interactive lab

Interactive lab · function

A quadratic low-momentum energy

For each fresh comparison, Reset and set BOTH Coefficient a=0.50 and Position x. Compare x=0.50 and x=1.00, predicting y=0.125 and 0.500, with slopes 0.50 and 1.00. In normalized units this is the leading E=p²/(2m) curve. The instrument does not include rest energy, the negative p⁴ correction, antiparticles, scattering lengths, or a nonperturbative contact sum.

A quadratic low-momentum energyThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA quadratic kinetic energy is a leading approximation tied to a momentum-to-mass hierarchy.

Check your understanding

For a short-range interaction, why can ka>1 coexist with a useful low-energy EFT when kR≪1?

Try it yourself

An elastic S-wave channel has a=20 fm, negligible effective range at the requested accuracy, k=0.10 fm−1, and interaction range R=1 fm. Compute ka, kR, and the leading complex amplitude f0=1/(−1/a−ik). Explain which expansion needs resummation.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Rationalize the complex denominator after evaluating 1/a. Small kR controls range effects, while ka controls whether a simple series of leading-contact iterations decreases.

Compare with the solution

The products are ka=2 and kR=0.10. The denominator is −0.050−0.10i fm−1-0.050-0.10i\,\mathrm{fm^{-1}}, so f0=(−0.050+0.10i)/(0.0502+0.102)=(−4+8i) fmf_0=(-0.050+0.10i)/(0.050^2+0.10^2)=(-4+8i)\,\mathrm{fm}. Its squared magnitude is 80 fm². The large value ka=2 prevents a naive expansion in repeated factors of ika, so the leading denominator is retained as a resummed expression. Range effects can still be expanded if the assumed negligible effective range and higher terms are verified. The value kR alone does not prove those corrections are exactly zero.

Take it with you

  • Nonrelativistic EFT retains slow particles after factoring out their rest energy.
  • Energy and spatial momentum carry different velocity orders.
  • Large scattering lengths can require a nonperturbative leading sector within a systematic EFT.

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