Lorentz oscillator susceptibility
Derive dispersive electric response from a damped bound charge and audit resonance signs.
On this page
The question for today
What you’ll understand
- Derive susceptibility with the declared phasor convention.
- Connect damping to positive absorbed power.
- Distinguish free ringdown from a steady driven resonance.
A dielectric can respond strongly to one color and weakly to another because its internal charges have natural dynamical timescales. The Lorentz model represents one such response by a charge attached to a restoring force and coupled to damping. Although real electronic transitions are quantum mechanical, this classical model exposes the mechanism linking a resonance, a phase lag and absorption. It also gives a compact sign check for any proposed frequency-dependent permittivity.
Drive a bound charge
Let a particle of charge and mass move by a small displacement from equilibrium. A harmonic restoring force supplies a natural angular frequency , while a positive damping rate removes mechanical energy. The applied macroscopic field is taken as the driving field, an approximation that absorbs local-field effects into fitted parameters. The displacement must remain small enough for both the restoring law and the polarization response to be linear.
Insert the convention into the mechanical equation. Acceleration contributes a negative squared frequency, while damping contributes a negative imaginary term in the denominator. Multiply the displacement by its charge to form a dipole, then multiply by the number density of identical oscillators. The charge appears squared in the susceptibility, so an electron's negative charge does not make an ordinary low-frequency dielectric susceptibility negative. It determines the displacement direction before the dipole is formed.
Separate phase response and absorption
Write the real detuning as the difference of squared natural and driving frequencies. Multiplying numerator and denominator by the complex conjugate separates the real and imaginary response. Below resonance the real part is positive; above resonance it becomes negative for this isolated oscillator contribution. Exactly at the undamped natural frequency the real contribution vanishes, while the imaginary contribution is positive. That statement concerns the susceptibility, not necessarily the full permittivity with background contributions included.
The polarization current amplitude is . Averaging its product with the real electric field gives a positive material heating rate proportional to the imaginary susceptibility. This is the physical reason the sign of the damping term matters. With zero damping, driving exactly at resonance does not produce a finite stationary response: energy accumulates and the steady harmonic ansatz fails there. Taking a small positive damping before a resonant limit avoids hiding that singular behavior.
Use limiting behavior as a diagnostic
Far below resonance, the charge follows the field almost quasistatically and the susceptibility approaches a positive constant. Far above resonance, inertia dominates and the response falls as the inverse squared frequency with a negative real sign. A finite damping smooths the transition and gives a finite linewidth. The driving frequency of maximum displacement is slightly shifted from the natural frequency when damping is appreciable; different observables need not peak at exactly the same frequency.
A real dielectric can require a sum of resonances and an approximately constant background over the measured band. The model parameters then summarize a chosen frequency range rather than revealing one literal spring per atom. The oscillator lab illustrates how a prepared displacement loses amplitude after release. Its initial velocity is zero and it has no continuing drive. Consequently its decay rate can support intuition about linewidth, but its displayed motion cannot be read as a driven susceptibility spectrum.
Work it through
Complex response away from resonance
Choose , , and . Find the susceptibility, its phase, and the relative permittivity with unit background.
The squared-frequency detuning is , and the damping factor is . Thus the response is , a dimensionless ratio.
Multiply by to obtain . The positive imaginary component agrees with passive damping in the chosen convention.
The phase of susceptibility is . Because real fields use a negative time exponential, this positive phasor phase describes polarization delayed relative to the electric field. Add the vacuum background to obtain .
The susceptibility is 3 + i with an 18.4° phase lag, and the relative permittivity is 4 + i.
The living notebook
Explore the model
Interactive lab · oscillator
Ringdown and material memory
For a fresh run, Reset and set BOTH Damping ratio ζ = 0.10 and Natural frequency ω₀ = 1. Repeat after Reset with ζ = 0.50 and ω₀ = 1. Predict faster decay of the oscillation envelope across several cycles in the second trace, then Step or Play both from time zero. This unit-mass model starts at x = 1 with zero velocity and positive stiffness; it has no driving-frequency control and does not calculate susceptibility.
- Displacement x(t)
- 1
- Velocity v(t)
- 0
- Regime
- underdamped
Unit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forDamping shortens ringdown memory; a driven frequency response requires a separate calculation.
Pause & reason
Check your understanding
Your turn
Try it yourself
At , take and . Find the susceptibility. Then double the damping and determine what happens to the absorbed power at this same frequency and fixed field amplitude.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
At this frequency the real detuning is zero. Use the imaginary susceptibility in the time-averaged heating formula.
Compare with the solution
Initially the denominator is , so . Doubling damping gives denominator and . At fixed frequency and field, the heating rate is proportional to the imaginary susceptibility and therefore halves. Larger damping does not always mean greater resonant heating under a fixed drive: it also reduces the induced motion. This comparison changes a model parameter between two stationary experiments, rather than describing time-dependent damping during one trajectory.
Keep the idea
Take it with you
- Positive damping gives positive imaginary electric susceptibility under e⁻ⁱωᵗ.
- Absorption and dispersive phase response share one dynamical denominator.
- Free ringdown and steady driven motion answer different experimental questions.
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