Skin depth and conducting boundaries
Derive good-conductor penetration and surface impedance while checking the regime of the approximation.
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The question for today
What you’ll understand
- Derive the complex wavenumber in a local good conductor.
- Compute amplitude skin depth and surface resistance.
- Identify displacement-current, nonlocal and finite-thickness limits.
An alternating electromagnetic field does not generally fill a conductor uniformly. Induced currents oppose rapid penetration, and the field decreases within a surface layer. Skin depth quantifies that layer in a particular approximation: a homogeneous local conductor with nearly real conductivity and permeability, driven at a frequency where conduction current dominates displacement current. Deriving that approximation carefully connects bulk attenuation, phase lag, surface heating and the familiar ideal-conductor boundary condition.
Reduce the bulk dispersion relation
Take a conductor occupying positive z, with no internal impressed source and a tangential electric field. Use the convention . Let conductivity be real and positive and permeability approximately real and positive at the driving frequency. Maxwell equations give a squared wavenumber with an imaginary conduction term. When , where denotes the approximately real background permittivity, that term dominates and selects equal positive real and imaginary wavenumber components.
The decaying solution has a phase that advances into the conductor while its amplitude falls. Its imaginary wavenumber defines the amplitude skin depth. Increasing frequency, conductivity or permeability decreases that depth in this regime. The conclusion about frequency depends on treating the material parameters as approximately constant: a frequency-dependent Drude conductivity or magnetic resonance can invalidate simple inverse-square-root extrapolation. Neither a dc conductivity table nor an ideal-conductor argument proves this approximation remains valid at optical frequencies.
Read the boundary through an impedance
Faraday's law fixes the magnetic amplitude accompanying the penetrating electric field. Their ratio is a complex surface impedance. With the chosen convention its imaginary part is negative; changing the time convention changes that sign while leaving the positive resistive part and heating unchanged. Declare the field directions when forming this ratio: take electric field along x, magnetic field along y and energy flow into positive z. This removes an otherwise easy normal-vector sign ambiguity.
The real part of surface impedance gives the cycle-averaged power entering and dissipating per unit area for a prescribed peak tangential magnetic amplitude. A perfect conductor is the limiting boundary with vanishing surface impedance, not an ordinary material of literally infinite microscopic acceleration. For large but finite conductivity, a small tangential electric field remains and produces a finite surface loss. Replacing that field by exactly zero discards the very term needed to estimate heating or cavity damping.
Know when the surface layer picture fails
The intensity of a single penetrating wave decreases as the square of its amplitude, so its intensity decay length is half the skin depth defined here. A sheet only a small fraction of a skin depth thick requires fields on both sides and cannot be treated as a semi-infinite absorber. Curved surfaces require the skin depth to be small compared with the relevant curvature scale before the planar local boundary approximation becomes reliable.
Local conductivity can also fail when the carrier mean free path is comparable to the penetration scale, producing an anomalous skin regime. Superconductors, strongly magnetic media and rapidly varying conductivity require their own constitutive treatment. Magnetic diffusion offers a useful connection within the ordinary quasistatic regime: neglecting displacement current gives a diffusion equation for magnetic field. The heat lab illustrates exact decay of periodic diffusion modes, but it does not solve the driven half-space boundary problem that defines skin depth.
Work it through
A conducting half-space
A local conductor has , and is driven at . Assume the good-conductor regime. Find skin depth, surface resistance and the amplitude remaining at twice that depth.
Convert ordinary frequency to angular frequency: . Substitution gives .
The surface resistance is . It is the real part of the impedance, which here is , rather than its magnitude.
At the field-amplitude ratio is . The corresponding intensity ratio is , consistent with its shorter decay length.
The amplitude skin depth is 0.503 mm, the surface resistance is 1.99 mΩ, and 13.5% of the surface field amplitude remains at two skin depths.
The living notebook
Explore the model
Interactive lab · heat
Diffusion penalizes short spatial scales
For each independent run, Reset and set BOTH controls. First use Spatial mode n = 1 and Diffusivity κ = 0.40; then Reset and use n = 2 and κ = 0.40. Predict four times the exponential decay rate in the second run and compare after one Step. The analytic periodic solution exp(−κn²t)sin(nx) illustrates diffusion in dimensionless coordinates; it does not model a driven conducting boundary, electromagnetic reflection or a spatial skin-depth profile.
- Current amplitude
- 1
- Spatial L² norm
- 1.772
- Decay rate · κn²
- 3.6 /s
The exact periodic heat-equation mode is u(x,t) = exp(−κn²t) sin(nx), on [0,2π]. Playback advances physical time. The initial sine is shown separately, and the unnormalized L² norm is √π exp(−κn²t). This analytic instrument does not run a finite-difference solver or test discretization stability. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forDiffusive relaxation rates grow with squared spatial wavenumber, while skin depth comes from a different driven boundary problem.
Pause & reason
Check your understanding
Your turn
Try it yourself
A thick conductor has and a peak surface magnetic amplitude . Find its average absorbed power per area. If conductivity increases fourfold at fixed frequency, permeability and prescribed H, how does that power change?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use one half times Rs times the squared peak H. In this approximation Rs scales as the inverse square root of conductivity.
Compare with the solution
Initially . Increasing conductivity fourfold halves surface resistance to , so the new absorbed power is . Holding the surface magnetic amplitude fixed is essential; a different driving constraint can change the comparison. This result describes integrated loss through the conducting layer, not the volumetric heating at one depth. A thin sheet or a conductor outside the local good-conductor regime would require recalculating its field distribution.
Keep the idea
Take it with you
- Skin depth here is a field-amplitude length in a specified good-conductor regime.
- Surface impedance retains the small tangential electric field responsible for heating.
- Optical dispersion, nonlocal transport and finite thickness can invalidate the simple formula.
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