advanced27 min studyLesson 507 in Physics

Read acceleration from the curvature tensor

Distinguish local band mass, holes, and an orbit-dependent cyclotron mass.

On this page

What you’ll understand

  • Define inverse effective mass through the band Hessian.
  • Handle anisotropy and negative curvature correctly.
  • Compute a cyclotron mass for an elliptical parabolic orbit.

Effective mass packages how a band’s velocity changes when a force shifts its wavevector. It is a curvature property, not a replacement for the electron’s rest mass in every equation. In more than one dimension it is generally a tensor, so force and acceleration need not align. Magnetic orbits probe yet another useful mass, determined by the energy dependence of an enclosed reciprocal-space area rather than by an arbitrary single curvature direction.

Differentiate velocity once more

Ignore Berry curvature for this conventional local acceleration calculation and take a band isolated enough for semiclassical motion. Differentiating the band velocity while using hbar times k velocity equal to force gives acceleration as the energy Hessian divided by hbar squared acting on force. This defines the inverse effective-mass tensor. The Hessian is symmetric for a smooth scalar band, and its principal axes identify directions where acceleration and force are parallel.

At a nondegenerate parabolic minimum all principal curvatures are positive. At a band maximum they are negative, so electron acceleration can oppose the applied force without implying a negative fundamental rest mass. Describing an almost filled band in terms of missing electrons leads to positively charged holes with a positive mass near a simple maximum. Near inflection points the local curvature mass may diverge even when the band velocity is finite, limiting a constant-mass approximation.

(m−1)ij=1ℏ2∂2E∂ki∂kj,v˙i=∑j(m−1)ijFj(m^{-1})_{ij}=\frac1{\hbar^2}\frac{\partial^2E}{\partial k_i\partial k_j},\qquad \dot v_i=\sum_j(m^{-1})_{ij}F_j
k is in m⁻¹, E in J, and the inverse-mass tensor in kg⁻¹. This local conventional formula neglects Berry contributions and assumes the force changes k within the same smooth band.↔ Scroll wide equations horizontally.

Anisotropy changes magnetic motion

For a two-dimensional parabolic band with principal masses mx and my, contours of constant energy are ellipses in wavevector space. In a perpendicular magnetic field, the Lorentz force moves k around such a contour while doing no work. Combining the two component equations gives a frequency proportional to magnetic field divided by the geometric mean of the principal masses. The orbit is closed only in the appropriate band region; open Fermi-surface trajectories need not have this simple periodic motion.

The cyclotron mass may also be obtained from the derivative of reciprocal orbit area with respect to energy. For an ellipse that derivative gives precisely the geometric mean, providing an independent check. In a general nonparabolic band the cyclotron mass depends on energy and field direction, and need not equal a density-of-states mass or any one Hessian eigenvalue. Quantum oscillations require further quantization conditions, which should not be inferred from a classical orbit alone.

E−Ec=ℏ2kx22mx+ℏ2ky22my,mc=ℏ22π∂Ak∂E=mxmy,ωc=e∣B∣mcE-E_c=\frac{\hbar^2k_x^2}{2m_x}+\frac{\hbar^2k_y^2}{2m_y},\qquad m_c=\frac{\hbar^2}{2\pi}\frac{\partial A_k}{\partial E}=\sqrt{m_xm_y},\qquad \omega_c=\frac{e|B|}{m_c}
Ak is a closed k-space orbit area in m⁻²; mc is a positive cyclotron-mass magnitude for this electron-like ellipse, and ωc is angular frequency in s⁻¹. Both principal masses are positive here.↔ Scroll wide equations horizontally.

Fit the appropriate neighborhood

A curvature extracted from a wide energy fit can differ from the local band-edge curvature that controls low-energy acceleration. Conversely, an extremely narrow finite-difference estimate can amplify numerical eigenvalue noise. Check the fit window, wavevector resolution, units, and whether nearby bands change character. A tensor fit must retain mixed derivatives when the chosen coordinates are not principal axes; setting them to zero by habit can invent a false alignment of force and acceleration.

The function lab illustrates the sign of curvature in one coordinate. Reset and set coefficient to 1 and position to 1; predict value 1 and tangent slope 2. Reset and set coefficient to −1 and position to 1; predict value −1 and slope −2. The selected parabolas have opposite curvature, analogous to opposite conventional inverse-mass signs. This dimensionless function model contains no hbar, tensor fitting, magnetic orbit, or cyclotron-frequency calculation.

E(k)≃E(k0)+ℏv0δk+ℏ22m∗(δk)2E(k)\simeq E(k_0)+\hbar v_0\delta k+\frac{\hbar^2}{2m^*}(\delta k)^2
δk=k−k₀ is a local wavevector displacement in m⁻¹. A finite slope v₀ in m/s can coexist with either curvature sign; the expansion is local and omits higher powers.↔ Scroll wide equations horizontally.

An elliptical orbit

An electron-like parabolic band has mx=0.25me and my=me. In perpendicular B=1 T, find its cyclotron mass, angular frequency, and period. Use e/me=1.76×10¹¹ s⁻¹T⁻¹.

  1. The orbit’s effective cyclotron mass is the geometric mean: √(0.25me×me)=0.50me. It is neither the arithmetic mean 0.625me nor simply the smaller principal mass.

  2. The angular frequency is (e/me)B/(mc/me)=1.76×10¹¹/0.50=3.52×10¹¹ s⁻¹. This is angular rate, so using its reciprocal alone would miss a factor of two pi in the period.

  3. The full orbit period is 2π/ωc≈1.78×10⁻¹¹ s, or 17.8 ps. The positive frequency quoted is a magnitude; charge sign and field direction determine the sense of traversal.

The result

The cyclotron mass is 0.50me, angular frequency 3.52×10¹¹ s⁻¹, and period about 17.8 ps.

Explore the model

Interactive lab

Interactive lab · function

Compare opposite curvature signs

Reset and set a=1, x=1; predict y=1 and slope 2. Reset and set a=−1, x=1; predict y=−1 and slope −2.

Compare opposite curvature signsThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe parabolas have opposite curvature. This illustrates a local curvature sign, not a tensor band calculation or a magnetic-field trajectory.

Check your understanding

For a smooth anisotropic band with nonzero mixed curvature, which relation is generally correct?

Try it yourself

A local inverse-mass tensor is [[2,1],[1,2]]/me in two coordinates. Apply force (F₀,0) and find acceleration direction and the two principal masses.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Multiply the tensor by force, then diagonalize the symmetric 2×2 matrix using the equal and opposite component directions.

Compare with the solution

Acceleration is (2F₀/me,F₀/me), at arctan(1/2)≈26.6° to the force direction. The inverse-mass eigenvalues are 3/me along (1,1) and 1/me along (1,−1). Their corresponding principal masses are me/3 and me. Both are positive, but the laboratory axes are not the principal axes.

Take it with you

  • Inverse effective mass is the Hessian of energy divided by hbar squared.
  • Negative electron curvature near a maximum motivates a hole description.
  • Cyclotron mass measures an orbit area derivative and can differ from a directional curvature mass.

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