core24 min studyLesson 952 in Physics

Thermal, shot, and flicker noise

Calculate distinct noise mechanisms with explicit spectral and bandwidth conventions, and identify when independent-noise addition is justified.

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What you’ll understand

  • Use one-sided voltage and current noise spectra in hertz.
  • Compute thermal and Poisson shot-noise contributions at a common output.
  • Explain why flicker noise needs both low and high frequency limits.

Random fluctuations are physical parts of a measurement chain, not simply imperfections in the display. Thermal agitation produces resistor noise, discrete independent charge transfers produce shot noise, and slow device fluctuations often produce an approximately inverse-frequency spectrum. These mechanisms have different parameter dependences and validity limits. A useful budget identifies where each noise enters, how it propagates, and what frequency band the measurement accepts. Only then can one decide whether a quieter amplifier, a lower resistance, a different modulation frequency, or a longer measurement will help.

Thermal and shot spectra have explicit conventions

Throughout this module, a one-sided power spectral density is defined for nonnegative frequency f in hertz and integrates over that domain to give variance. Voltage PSD has units V²/Hz; its square root is an amplitude spectral density in V/√Hz. For a classical resistor in thermal equilibrium, the open-circuit voltage PSD is four kBTR. This approximation requires the frequencies to be low enough that the classical thermal limit applies and the resistance is approximately real and constant.

For statistically independent Poisson charge arrivals with elementary charge magnitude e and mean current magnitude I, the one-sided current PSD is two eI. A transimpedance converts current noise into voltage noise through its magnitude squared. The Poisson assumption is essential: correlations, gain statistics, or charge partitioning can modify the result. The external net bias current of a compensated amplifier is therefore not universally sufficient to predict its internal current noise.

Sv,R(1)=4kBTR,Si,shot(1)=2e∣I∣,σv2=Sv(1)Bfor white noise and an ideal band of width BS_{v,R}^{(1)}=4k_BTR,\qquad S_{i,\mathrm{shot}}^{(1)}=2e|I|,\qquad \sigma_v^2=S_v^{(1)}B\quad\text{for white noise and an ideal band of width }B
kB is Boltzmann’s constant, T absolute temperature, R resistance, and e the positive elementary charge. B is the accepted one-sided bandwidth in hertz. The voltage formula is open circuit; loading and a real filter require the appropriate transfer and equivalent bandwidth.↔ Scroll wide equations horizontally.

Compare noise only after referring it to the same point

An amplifier can add both an input voltage-noise source and current-noise sources. The latter create voltages across the impedances they encounter. A low voltage-noise part can consequently perform poorly with a high-impedance sensor. Noise from gain-setting resistors and subsequent stages must also be propagated. Referring every contribution to a common input or output makes the comparison meaningful and prevents a small current number from being compared directly with a voltage number.

Uncorrelated zero-mean contributions add in variance, giving a root-sum-square amplitude. Correlated fluctuations require covariance or cross-spectral terms instead. Ordinary signal gain amplifies an already present input signal and its input noise together, so it does not improve their ratio by itself. It can still make downstream noise less important when referred back to the sensor, provided the chain remains linear and does not overload.

σsum2=∑jσj2for uncorrelated sources,Sv(1)(f)=Cf⟹σv2=Cln⁡ ⁣(fHfL)\sigma_{\mathrm{sum}}^2=\sum_j\sigma_j^2\quad\text{for uncorrelated sources},\qquad S_v^{(1)}(f)=\frac{C}{f}\Longrightarrow\sigma_v^2=C\ln\!\left(\frac{f_H}{f_L}\right)
The second relation is a declared pure flicker model over 0<fL<fH, with ideal band limits. C has units V². A physical spectrum cannot be assumed proportional to 1/f over all frequencies; correlations invalidate the first relation’s simplified sum.↔ Scroll wide equations horizontally.

Slow noise is not automatically removed by averaging

White noise often permits an average to improve as the inverse square root of the number of independent measurements. Flicker noise carries long correlations and does not generally satisfy that independence model. Extending a measurement toward lower frequencies can admit additional slow fluctuations. A measured drift may also be nonstationary, in which case a stationary PSD model over an arbitrarily long record is itself questionable.

A noise statement should therefore include its measurement duration or low-frequency limit, high-frequency filtering, temperature, source impedance, and whether the number is RMS or peak to peak. There is no duration-independent universal conversion from Gaussian RMS noise to a strict maximum excursion. Modulation can move a desired signal away from a low-frequency noise region, but it does not remove noise already present around the modulation frequency. These distinctions guide practical changes to the experiment rather than just changes to a numerical noise label.

Combine two independent voltage contributions

A toy chain measures a 10 kΩ resistor at 300 K over an ideal 1000 Hz band. A separate independent Poisson current source of 1 µA contributes through a noiseless 10 kΩ transimpedance to the same output. Use kB=1.38×10⁻²³ J/K and e=1.60×10⁻¹⁹ C. Find both RMS voltage contributions and their combined RMS value; no other noises are included.

  1. The resistor variance is 4kBTRB=1.656×10−134k_BTRB=1.656\times10^{-13} V², giving approximately 0.40694 µV RMS at the stated common output.

  2. The current variance is 2eIB=3.20×10−222eIB=3.20\times10^{-22} A², giving 17.8885 pA RMS. Multiplication by 10 kΩ gives 0.178885 µV RMS.

  3. Because these two sources are stipulated independent, their voltage variances add. The result is 0.406942+0.1788852≃0.44452\sqrt{0.40694^2+0.178885^2}\simeq0.44452 µV RMS.

The result

The thermal and converted shot contributions are about 0.407 µV and 0.179 µV RMS, with a combined value of 0.445 µV RMS.

Explore the model

Interactive lab

Interactive lab · probability

Independent rare counts have fluctuations

For each fresh comparison, Reset and set BOTH Success probability p=0.05 and Trials n. Compare n=10 and n=20, predicting count means 0.50 and 1.00 and variances 0.475 and 0.950. This exact binomial model illustrates independent rare counts. It is not a resistor-noise spectrum or an exact Poisson shot-noise process, and its finite-trial variance is np(1−p), not np.

Independent rare counts have fluctuationsThese are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Current readings: Mean · np: 5; Variance · np(1−p): 2.5; Total probability: 1. All parameters are adjustable with the labeled controls below.03581000.070.150.220.3Successes kP(X = k)k = 0 · P = 9.77e-4
Exact probabilityHighlighted outcomeMean np
Mean · np
5
Variance · np(1−p)
2.5
Total probability
1
t = 0 s

These are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forIndependent count fluctuations have a calculable variance, but the statistical model must be declared.

Check your understanding

When may two RMS noise voltages be combined by a root-sum-square calculation?

Try it yourself

A separate pure flicker model has one-sided Sv(f)=C/f with C=4 nV². First integrate from 1 Hz to 100 Hz, then from 0.1 Hz to 100 Hz. Compute both RMS values and their ratio, using ln100≈4.60517 and ln1000≈6.90776. Does admitting lower frequencies reduce this contribution?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The variance is C times the logarithm of the ratio of band edges. Take the square root only after the integration.

Compare with the solution

The first variance is 18.42068 nV², giving 4.29193 nV RMS. The second is 27.63104 nV², giving 5.25652 nV RMS. The ratio is ln⁡1000/ln⁡100=1.5≃1.22474\sqrt{\ln1000/\ln100}=\sqrt{1.5}\simeq1.22474. Admitting the additional low-frequency decade increases this modeled contribution. This is a comparison of explicitly band-limited flicker spectra, not a universal prediction for every time average or a claim that a real device maintains a 1/f law down to zero frequency.

Take it with you

  • Thermal and Poisson shot noise have distinct physical and statistical assumptions.
  • Spectral conventions and common reference points are part of a valid noise budget.
  • Flicker correlations and finite measurement bands limit simple averaging claims.

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