research29 min studyLesson 634 in Physics

CP violation in mixing and decay

Distinguish direct, mixing, and mixing-decay interference CP observables with explicit amplitude and asymmetry signs.

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What you’ll understand

  • Separate weak and strong phases in a direct rate asymmetry.
  • Classify CP violation in decay, mixing, and their interference.
  • Calculate a signed time-dependent asymmetry from a declared lambda convention.

CP reverses spatial orientation and exchanges particles with antiparticles. In flavor physics its violation can appear in decay magnitudes, in neutral-meson conversion, or in interference between direct decay and decay after conversion. These mechanisms use related complex amplitudes but are not interchangeable. A useful calculation must declare which initial rates are subtracted and which phases change under CP. We will retain the preceding lesson's meson eigenstate signs and define every asymmetry explicitly before interpreting its coefficient.

A direct rate difference needs two kinds of phase

Consider two decay contributions with real positive magnitudes a one and a two. After removing a common phase, write A=a1+a2ei(δs+ϕw)A=a_1+a_2e^{i(\delta_s+\phi_w)} and its CP-conjugate amplitude Aˉ=a1+a2ei(δs−ϕw)\bar A=a_1+a_2e^{i(\delta_s-\phi_w)}. The strong rescattering phase difference delta s is unchanged by CP, while the weak coupling phase difference phi w changes sign. This representation assumes the strong dynamics conserve CP. Complex conjugating the entire amplitude would incorrectly reverse the strong phase as well as the weak phase.

Squaring the amplitudes gives a difference proportional to the sine of each phase difference. Direct rate CP violation therefore requires interfering contributions with distinct weak phases and nontrivial relative strong phases. Either phase difference can eliminate this rate asymmetry when its sine vanishes. Equal magnitudes in a particular channel do not prove all CP observables vanish: another channel or an interference measurement can remain sensitive. Also, instrumental charge asymmetries and unequal production rates must be controlled before a measured counting imbalance is interpreted as a decay asymmetry.

ACPdir=∣Aˉ∣2−∣A∣2∣Aˉ∣2+∣A∣2,∣Aˉ∣2−∣A∣2=4a1a2sin⁡δssin⁡ϕwA_{\mathrm{CP}}^{\mathrm{dir}}=\frac{|\bar A|^2-|A|^2}{|\bar A|^2+|A|^2},\qquad |\bar A|^2-|A|^2=4a_1a_2\sin\delta_s\sin\phi_w
This sign follows from the explicitly stated particle-minus-antiparticle phase convention and the antiparticle-minus-particle rate numerator. Magnitudes share common amplitude units; the asymmetry is dimensionless.↔ Scroll wide equations horizontally.

Mixing and decay combine in a phase invariant

CP violation in mixing is diagnosed by ∣q/p∣≠1|q/p|\ne1, which makes the two opposite flavor-conversion probabilities differ under the usual CPT assumptions. For a CP eigenstate f accessible from both neutral flavors, define Af=⟨f∣H∣M⟩A_f=\langle f|H|M\rangle and Aˉf=⟨f∣H∣Mˉ⟩\bar A_f=\langle f|H|\bar M\rangle. Their interference depends on λf=(q/p)(Aˉf/Af)\lambda_f=(q/p)(\bar A_f/A_f). Under rephasing of the flavor basis, the change in q over p cancels the change in the amplitude ratio. Its phase consequently has a physical meaning unavailable to either factor separately.

An imaginary part of lambda can produce a CP asymmetry through interference even when its magnitude is one and mixing itself conserves CP. For a CP eigenstate dominated by one weak decay phase, the eigenvalue and mixing phase are included in the full lambda rather than added later by memory. If several weak decay amplitudes matter, extracting a fundamental phase requires their hadronic ratios. Calling every measured sine coefficient simply a weak angle would hide those channel-dependent assumptions. The invariant is a compact bookkeeping device, not a substitute for the amplitude analysis.

λf=qpAˉfAf,Cf=1−∣λf∣21+∣λf∣2,Sf=2Im⁡λf1+∣λf∣2,Af(t)=Sfsin⁡(ωt)−Cfcos⁡(ωt)\lambda_f=\frac qp\frac{\bar A_f}{A_f},\qquad C_f=\frac{1-|\lambda_f|^2}{1+|\lambda_f|^2},\qquad S_f=\frac{2\operatorname{Im}\lambda_f}{1+|\lambda_f|^2},\qquad \mathcal A_f(t)=S_f\sin(\omega t)-C_f\cos(\omega t)
Here A_f(t) denotes [rate(anti-M(t) to f) minus rate(M(t) to f)] divided by their sum. The final state f is a common CP eigenstate. The simple expression assumes equal widths, |q/p| = 1, and omega = (mH−mL)/hbar, with the preceding g-minus convention.↔ Scroll wide equations horizontally.

Check an asymmetry at a special time

At zero proper time the sine vanishes, so the defined rate asymmetry is minus C. This agrees with comparing the unmixed initial decay amplitudes directly when the mixing magnitude is one. At a quarter oscillation, where the full mass phase is pi over two, the cosine vanishes and the asymmetry equals S. These checks catch reversed numerators and inconsistent propagation signs. The coefficient bound Sf2+Cf2≤1S_f^2+C_f^2\le1 follows directly from the complex lambda definitions and provides another useful algebraic diagnostic.

Actual meson systems can require unequal-width hyperbolic terms, corrections from a nonunit mixing magnitude, time-resolution convolution, and flavor-tagging calibration. The displayed formula deliberately isolates one common controlled limit. A significant CP asymmetry establishes a symmetry failure only after those experimental and dynamical effects are accounted for; assigning it to new interactions further requires a Standard Model prediction with uncertainties. The same observed number may involve direct and interference contributions, so report the measured coefficients and conventions before attaching a microscopic explanation.

Strong and weak phases reinforce a direct asymmetry

For two CP-conjugate decay amplitudes in common units, set a1=1a_1=1, a2=1/2a_2=1/2, and δs=ϕw=π/2\delta_s=\phi_w=\pi/2. Compute both squared magnitudes and the defined direct CP asymmetry.

  1. The particle amplitude is A=1+(1/2)eiπ=1/2A=1+(1/2)e^{i\pi}=1/2. Its squared magnitude is one quarter because the two terms interfere destructively.

  2. The CP-conjugate weak phase reverses while the strong phase stays fixed. Hence Aˉ=1+(1/2)ei0=3/2\bar A=1+(1/2)e^{i0}=3/2, with squared magnitude nine quarters.

  3. The antiparticle-minus-particle numerator is two and the denominator is five halves. Their ratio is ACPdir=4/5A_{\mathrm{CP}}^{\mathrm{dir}}=4/5, positive in our declared convention.

The result

The particle and antiparticle squared amplitudes are 1/4 and 9/4; their direct asymmetry is +0.8.

Explore the model

Interactive lab

Interactive lab · waves

Interference can turn equal contributions into unequal sums

Reset and set BOTH Phase difference = 0° and Amplitude ratio = 0.5; predict sum amplitude 1.5. For a fresh comparison, Reset and set Phase difference = 180° and Amplitude ratio = 0.5; predict sum amplitude 0.5. Inspect or Play each independently reset waveform.

Interference can turn equal contributions into unequal sumsTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe squared amplitudes have ratio nine, illustrating coherent addition. These equal-frequency waves do not distinguish weak and strong phases, perform CP conjugation, or simulate meson decay.

Check your understanding

Which statement permits a nonzero direct partial-rate asymmetry in the two-amplitude model?

Try it yourself

For a common CP eigenstate f, assume equal widths, ∣q/p∣=1|q/p|=1, and λf=eiπ/6\lambda_f=e^{i\pi/6}. Find C, S, and the antiparticle-minus-particle asymmetry at ωt=π/2\omega t=\pi/2. Does this require direct CP violation in that channel?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The modulus of lambda is one, so evaluate its imaginary part before applying the time formula.

Compare with the solution

The modulus condition gives Cf=0C_f=0. The imaginary part is one half, so Sf=1/2S_f=1/2. At the specified mass phase the cosine is zero and sine is one, giving Af=+1/2\mathcal A_f=+1/2. Since the mixing magnitude is one, unit lambda magnitude also means equal particle and antiparticle direct decay magnitudes. This example exhibits CP violation through mixing-decay interference without requiring a direct partial-rate asymmetry in that channel.

Take it with you

  • Direct rate CP violation requires appropriate relative weak and strong phases.
  • The invariant lambda combines mixing and decay phases with consistent field conventions.
  • Signed time-asymmetry formulas require explicit numerator, mass ordering, and width assumptions.

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