advanced28 min studyLesson 805 in Physics

A geodesic transports its own tangent with an affine parameter

Separate parallel transport, coordinate acceleration, and reparameterization effects using a flat polar example.

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What you’ll understand

  • Write vector transport along a specified curve.
  • Derive the affine geodesic equation by transporting its tangent.
  • Diagnose nonzero coordinate acceleration and nonaffine parameter terms.

A connection lets us compare vectors along a chosen path through parallel transport. A geodesic is the special case in which the transported vector is the path’s own tangent. Its familiar zero-right-hand-side equation requires an affine parameter. We will apply it to a straight Cartesian line written in polar coordinates, where ordinary coordinate acceleration is nonzero, and then show how a nonlinear parameter can create an extra tangent term even in a one-dimensional flat example.

Transport is a rule along a path rather than equality of arrays

Given a curve x(λ), its tangent contracts the covariant derivative of a vector carried along it. Parallel transport sets that derivative to zero. The components need not remain constant because the coordinate basis changes. With the Levi-Civita connection, inner products of parallel vectors are preserved. Comparing vectors at separated points requires such a rule; subtracting their coordinate arrays without specifying transport is generally not a coordinate-independent comparison. The result can depend on the chosen path when curvature or global holonomy is present.

In the flat polar plane a constant Cartesian vector pointing along x has orthonormal polar components (cosφ,−sinφ). Those numbers rotate as the point moves around a circle even though the Cartesian vector is parallel. This is basis variation rather than a physical torque. On a curved manifold, transporting around a small loop can yield a genuine holonomy. Flatness eliminates such local contractible-loop effects, but nontrivial global identifications can still matter. One should not infer global path independence merely from a local flat patch.

DVμdλ=dVμdλ+ΓμαβdxαdλVβ=0,Vμ=dxμdλ⇒d2xμdλ2+Γμαβdxαdλdxβdλ=0\frac{DV^\mu}{d\lambda}=\frac{dV^\mu}{d\lambda}+\Gamma^\mu{}_{\alpha\beta}\frac{dx^\alpha}{d\lambda}V^\beta=0,\qquad V^\mu=\frac{dx^\mu}{d\lambda}\Rightarrow \frac{d^2x^\mu}{d\lambda^2}+\Gamma^\mu{}_{\alpha\beta}\frac{dx^\alpha}{d\lambda}\frac{dx^\beta}{d\lambda}=0
The second equation uses an affine parameter λ. For timelike geodesics proper time or proper length cτ is affine; null geodesics have no proper-time parameter and require a separate affine choice. Units of components depend on the coordinate and parameter units.↔ Scroll wide equations horizontally.

Coordinate acceleration is cancelled by connection terms

In polar coordinates, the affine geodesic equations are r double-dot minus r times angular-rate squared equals zero, and angular double-dot plus twice radial rate times angular rate divided by r equals zero. A straight line missing the origin has changing r and φ, so neither coordinate is generally linear in affine distance. The connection terms account for that changing basis. A fixed-r circle in a Euclidean plane instead requires acceleration; it is not a geodesic of the plane even though its speed can be constant.

A nonlinear reparameterization of a geodesic preserves its unparameterized path but changes the equation. The left side becomes a function times the tangent. Only transformations between affine parameters of the form λ′=aλ+b, with constant nonzero a, preserve the homogeneous form. A vanishing ordinary second derivative in some arbitrary parameter is therefore neither necessary nor sufficient for the full geometric statement. The metric norm of an affinely transported tangent stays constant, preserving whether it is timelike, null, or spacelike.

r¨−rφ˙2=0,φ¨+2r˙φ˙r=0,d2xμdσ2+Γμαβdxαdσdxβdσ=f(σ)dxμdσ\ddot r-r\dot\varphi^2=0,\qquad \ddot\varphi+\frac{2\dot r\dot\varphi}{r}=0,\qquad \frac{d^2x^\mu}{d\sigma^2}+\Gamma^\mu{}_{\alpha\beta}\frac{dx^\alpha}{d\sigma}\frac{dx^\beta}{d\sigma}=f(\sigma)\frac{dx^\mu}{d\sigma}
Dots in the first two equations denote a common affine parameter on the flat plane r>0. σ in the final equation is an arbitrary regular reparameterization; f=dln|dλ/dσ|/dσ for an affine λ. All equations use the Levi-Civita connection.↔ Scroll wide equations horizontally.

Local extremality has qualifications

For a positive-metric geometry, geodesics are locally length-stationary and minimize length over sufficiently short segments. In Lorentzian geometry, timelike geodesics are proper-time stationary and locally maximizing before the relevant conjugate-point limitations. Null geodesics are derived from the affine tangent or a suitable constrained action, not by dividing by their zero proper time. Multiple geodesics can connect the same events, and a long stationary path need not provide a global optimum. These are geometric conditions separate from the coordinate ODE representation.

The vector lab illustrates the flat polar component rotation. Reset and set both controls to angle zero and magnitude one, predicting (1,0). Reset and set angle −90 degrees and magnitude one, predicting (0,−1). Interpret these as orthonormal polar components of the same fixed Cartesian vector at φ=0 and φ=π/2. They are separately entered component arrays; the lab has no moving coordinate frame, transport connection, or curved manifold. This comparison tests basis geometry without presenting playback as a physical transport trajectory.

Check a straight line in polar coordinates

In a flat spatial plane take x(s)=s and y(s)=a=2 m, with s an affine length parameter. At s=0 find r, dr/ds, dφ/ds, and d²r/ds², then verify both polar geodesic equations.

  1. At s=0, r=√(s²+a²)=a=2 m and φ=π/2. The radial rate is s/r=0, while the angular rate from the Cartesian line is −a/(s²+a²)=−0.50 m⁻¹.

  2. The radial second derivative at the point is 1/a=0.50 m⁻¹. The angular second derivative vanishes there by differentiation of −a/(s²+a²).

  3. The radial equation is 0.50−2×0.50²=0 m⁻¹. The angular equation is zero plus 2 times the zero radial rate times the angular rate divided by r, hence zero as well.

The result

The straight line has nonzero radial coordinate acceleration 0.50 m⁻¹, exactly cancelled by its polar connection term. It satisfies both affine geodesic equations.

Explore the model

Interactive lab

Interactive lab · vectors

Rotate components of one fixed Cartesian direction

Reset and set BOTH controls to angle 0°,magnitude 1, predicting (1,0). Reset and set angle −90°,magnitude 1, predicting (0,−1). Assign these to polar-frame components at φ=0 and π/2. This is basis geometry, with no connection or transport trajectory.

Rotate components of one fixed Cartesian directionPlayback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Current readings: x component: 1.393; y component: 0.975; Magnitude: 1.7. All parameters are adjustable with the labeled controls below.−7.46−3.7303.737.46−3.5−1.7501.753.5xyvvₓ = 1.39
Vectorx / y projectionsTrace marker
x component
1.393
y component
0.975
Magnitude
1.7
t = 0 s

Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forParallel geometric vectors can have changing coordinate or frame components.

Check your understanding

What does a nonlinear change of parameter generally do to an affinely parameterized geodesic equation?

Try it yourself

In a flat one-dimensional line with coordinate x in metres and zero connection, write x=Lσ² for σ>0 dimensionless and L=1 m. Find the nonaffine coefficient f(σ) in x″=f x′, evaluate it at σ=2, and supply an affine parameter.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Differentiate with respect to σ, then divide x″ by x′. The path can be straight even when this ratio is nonzero.

Compare with the solution

x′=2Lσ and x″=2L, so f=1/σ. At σ=2 the value is 1/2 per unit σ. Choosing λ=Lσ²=x as a length-valued parameter gives x(λ)=λ and d²x/dλ²=0. The original nonzero second derivative came from a nonlinear parameter rather than curvature or a nongeodesic path.

Take it with you

  • Parallel transport compares vectors using a connection along a path.
  • A geodesic transports its own tangent with an affine parameter.
  • Coordinate acceleration and parameter acceleration need not represent a geometric force.

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