Adiabatic invariants in mechanics
Predict slow oscillator changes using approximate action conservation and identify why rapid changes and separatrices invalidate it.
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The question for today
What you’ll understand
- Estimate whether a parameter change is slow relative to an orbit.
- Predict energy and amplitude changes at approximately fixed action.
- Distinguish adiabatic mechanical evolution from an instantaneous parameter reset.
A pendulum whose length changes slowly does not keep exactly the same energy, because the external mechanism can do work. Yet a different quantity can remain approximately fixed: the action associated with its fast periodic motion. Mechanical adiabatic invariance is a separation-of-timescales result. It should not be confused with zero heat flow in thermodynamics or with exact conservation under an arbitrary parameter change. The assumptions concern how slowly parameters vary and whether a regular periodic orbit remains available.
Compare the change rate with the orbital rate
For an oscillator with a smoothly varying positive frequency, a useful local small parameter is the magnitude of its frequency rate divided by frequency squared. It compares the fractional parameter change over a typical oscillation with unity, up to the usual two-pi convention in the cycle duration. The condition should hold throughout the interval, not merely at its endpoints. Abrupt switching, sharp transients, or a frequency approaching zero can defeat an apparently long overall adjustment time.
Averaging over the fast phase suppresses the leading net action drift under suitable regularity and scale-separation assumptions. The action can still have small phase-dependent oscillations, and accumulated errors depend on the time interval and smoothness of the protocol. Calling J an adiabatic invariant therefore does not assert that its derivative is exactly zero at every instant. State both the approximation and the orbit family when using it to predict a measurable change.
Energy and amplitude respond differently
Keep mass fixed and increase the oscillator frequency slowly. At approximately fixed J, energy increases in proportion to frequency, while amplitude decreases as its inverse square root. There is no contradiction: higher frequency raises the stiffness, so a smaller displacement can store more energy. The work comes from changing the parameter. Conservation of energy applies to an appropriately enlarged closed system, not automatically to the oscillator subsystem whose Hamiltonian depends explicitly on time.
The momentum amplitude behaves oppositely to the position amplitude: it grows as the square root of frequency. Thus the phase-space ellipse becomes narrower and taller while keeping its enclosed area approximately fixed. This picture links adiabatic invariance to canonical area, but it must not be used as a proof that every area-preserving deformation keeps each orbit's action fixed. The result relies on slow evolution within the specified regular family and the averaging over its rapid phase.
Sudden changes and separatrix crossings are different problems
If frequency changes instantaneously, position and momentum can remain continuous while the Hamiltonian value jumps. The new action depends on the phase at which the change occurred. At a position maximum, raising stiffness changes the potential energy immediately; at a zero crossing, the same change initially leaves the kinetic energy unchanged. That phase dependence is precisely what slow averaging avoids. An animation slider that rebuilds a solution with fresh initial data is neither of these physical protocols unless it explicitly models them.
Near a separatrix, an orbit's period can become arbitrarily long. A parameter variation that was slow compared with ordinary oscillations is then no longer slow compared with that orbit, even if the external adjustment rate remains small in laboratory units. Action changes at separatrix crossings require their own analysis. This limitation becomes important in resonance capture, slowly driven nonlinear systems, and magnetic confinement; a familiar invariant should not be extrapolated into a region where its underlying fast cycle has disappeared.
Work it through
Compress a slowly changing oscillator orbit
A unit-mass oscillator initially has ω = 2 and amplitude A = 3. Increase ω smoothly to 8 while remaining adiabatic and away from degeneracy. Estimate final energy and amplitude.
The initial energy is . Its normalized action is . This action, rather than energy, is approximately conserved.
At the final frequency, . The oscillator gains 54 energy units through the externally controlled change; it is not an isolated time-independent subsystem.
The final amplitude is . Momentum amplitude grows from to , leaving the ellipse area approximately unchanged.
The estimated final energy is 72 and amplitude is 1.5. A fourfold frequency increase doubles momentum amplitude and halves position amplitude at approximately fixed action.
The living notebook
Explore the model
Interactive lab · oscillator
Tell a reset from an adiabatic protocol
Before playback at t = 0, set damping to zero and natural frequency to 1. Predict that the fixed initial displacement of 1 gives J = 0.5. Change frequency to 2 and verify that initial displacement remains 1, so its action becomes 1. This is intentionally a comparison of separately initialized constant-frequency solutions: the control does not ramp ω(t) or enforce an adiabatic invariant. Use the lesson formulas, rather than this reset, to predict the smaller amplitude of a genuinely slow ramp.
- Displacement x(t)
- 1
- Velocity v(t)
- 0
- Regime
- underdamped
Unit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA parameter slider's initialization rule matters; a new constant-frequency solution is not a simulation of slow parameter evolution.
Pause & reason
Check your understanding
Your turn
Try it yourself
A unit-mass oscillator at q = 0 and p = 4 undergoes an ideal sudden jump from ω = 2 to ω = 8 without an impulse. Find old and new actions and compare with the adiabatic expectation.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
At a zero crossing the potential energy vanishes before and immediately after the jump.
Compare with the solution
Initially and immediately after the jump, energy is . The old action is , whereas the new action is . This sudden protocol does not conserve action. A slow protocol starting from the original orbit would instead give approximately . The difference follows from the protocol, not an arithmetic inconsistency.
Keep the idea
Take it with you
- Mechanical adiabatic invariance requires a genuine separation of timescales.
- At fixed action, oscillator energy grows with frequency while amplitude shrinks.
- Rapid changes and separatrix crossings require separate analysis.
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