research35 min studyLesson 792 in Physics

Anti-de Sitter geometry and its conformal boundary

Keep curvature, patch coordinates and the boundary conformal class distinct.

On this page

What you’ll understand

  • Identify bulk and boundary dimensions and metric signature.
  • Compute radial proper distances and curvature scales.
  • Explain why the conformal boundary is not an ordinary finite-distance wall.

Anti-de Sitter space is a spacetime of constant negative curvature, not a flat box with a physical screen attached. Its conformal boundary provides the geometric setting for specific gauge-gravity duality conjectures. Begin with Lorentzian AdS in d plus one bulk dimensions and d boundary spacetime dimensions, using one negative time direction. The Poincaré coordinates below cover a useful patch rather than the entire global spacetime. Neither this geometry nor a boundary correspondence by itself identifies our cosmological universe.

Read dimensions and units from the metric

Let L be the AdS curvature radius, z a positive radial coordinate and x the d coordinates parallel to the boundary. Take all these coordinates to have length units, with light speed set to one. The warp factor is dimensionless, so the line element has length-squared units. At any fixed positive z, the induced parallel metric is conformal to Minkowski space. The negative time sign specifies a Lorentzian geometry; a Euclidean treatment requires an explicit continuation.

The radial coordinate is not one more boundary spatial direction. Constant-z slices supply a convenient cutoff description, while the putative boundary theory lives in one fewer spacetime dimension. In ten-dimensional string examples there may also be a compact internal manifold; the AdS factor can then be described by a lower-dimensional effective gravity theory. Counting those compact directions as extra boundary coordinates would confuse dimensional reduction with the AdS boundary construction.

ds2=L2z2(dz2+ημνdxμdxν),ημν=diag⁡(−1,+1,…,+1),μ=0,…,d−1ds^2=\frac{L^2}{z^2}\left(dz^2+\eta_{\mu\nu}dx^\mu dx^\nu\right),\qquad \eta_{\mu\nu}=\operatorname{diag}(-1,+1,\ldots,+1),\quad \mu=0,\ldots,d-1
The bulk has d + 1 dimensions, the parallel coordinates have d, and L, z and xμ have length units. This is the Lorentzian Poincaré patch with z > 0.↔ Scroll wide equations horizontally.

Remove a divergent scale without removing curvature

As z approaches zero the physical metric diverges in these coordinates. Multiplying by the compensating conformal factor gives a finite representative of the boundary metric. Choosing a different defining coordinate or Weyl factor changes that representative while preserving the boundary conformal class. Thus the boundary data naturally couple to a conformal structure, with scale and anomaly subtleties handled in the field theory and renormalized gravitational action.

The boundary is at infinite proper distance along a constant-time radial curve. Integrating the radial line element gives a logarithm, so an arbitrarily small cutoff cannot be interpreted as a nearby material wall. At the same time, causal and optical statements are not determined by this spatial distance alone. The factor relating conformal metrics preserves local null cones, but global causal structure and boundary conditions still require the full spacetime and its chosen patch or covering.

g~μν ∂=lim⁡z→0z2L2gμν=ημν,ℓradial=L∣ln⁡z2z1∣\widetilde g_{\mu\nu}^{\,\partial}=\lim_{z\to0}\frac{z^2}{L^2}g_{\mu\nu}=\eta_{\mu\nu},\qquad \ell_{\rm radial}=L\left|\ln\frac{z_2}{z_1}\right|
The first expression chooses one representative of a conformal boundary metric. The proper-distance formula fixes the parallel coordinates and is a spatial radial length, not a light-travel time.↔ Scroll wide equations horizontally.

Check isometries and curvature invariants

Rescaling z and every parallel coordinate by the same positive factor leaves the Poincaré line element unchanged. This bulk isometry acts as a dilatation on boundary coordinates, motivating part of the conformal symmetry match. Curvature is nevertheless nonzero: scalar invariants are fixed by dimension and L. A large L relative to a microscopic string or Planck length can make curvature corrections small; merely rescaling coordinate labels cannot achieve that physical hierarchy.

The Einstein equation relates the constant curvature to a negative cosmological constant in a specified normalization. These formulas describe the model's AdS background rather than a measurement of the cosmological constant in nature. The spacetime lab performs a flat Lorentz transformation of one event and can check local signature-related coordinate arithmetic. It has no curvature, AdS radius, radial warp factor, global patch or conformal boundary, so it cannot simulate this geometry or test a holographic correspondence.

R=−d(d+1)L2,Λ=−d(d−1)2L2,(z,xμ)↦(az,axμ)(a>0)R=-\frac{d(d+1)}{L^2},\qquad \Lambda=-\frac{d(d-1)}{2L^2},\qquad (z,x^\mu)\mapsto(a z,a x^\mu)\quad(a>0)
The action convention is proportional to ∫√−g(R−2Λ). R and Λ have inverse-length-squared units; the coordinate rescaling is an isometry and leaves these invariants unchanged.↔ Scroll wide equations horizontally.

A radial logarithmic distance

In the Poincaré patch let L = 2 in a fixed length unit. At fixed parallel coordinates, compare points z1 = 1 and z2 = 4 in the same unit. Find the proper radial distance and explain what happens if the lower endpoint approaches zero.

  1. The radial metric gives dℓ=L dz/zd\ell=L\,dz/z. The ratio of endpoints is dimensionless because both use the same length unit.

  2. Integration gives ℓ=2ln⁡(4/1)≈2.7726\ell=2\ln(4/1)\approx2.7726 length units. The coordinate separation three is not the proper distance in the warped metric.

  3. Keeping the upper endpoint fixed while the lower tends to zero makes the logarithm diverge. This is why the conformal boundary cannot be treated as an ordinary finite-proper-distance surface, even though a rescaled representative metric is finite there.

The result

The proper radial distance is 2 ln 4 ≈ 2.7726 length units and diverges when one endpoint tends to the boundary.

Explore the model

Interactive lab

Interactive lab · spacetime

A local flat-space check only

Reset and set BOTH Relative velocity β = 0 and Event time ct = 1; the fixed event has x = 0.6. Reset and set β = 0.60 and ct = 1; predict γ = 1.25, x′ = 0 and ct′ = 0.80. These flat Lorentz coordinates illustrate signature and local frame arithmetic, not AdS curvature, radial distance or a conformal boundary.

A local flat-space check onlyA fixed x = 0.6 event is Lorentz transformed with c = 1. Playback highlights the relation between coordinate descriptions; it does not move the event. Current readings: Lorentz factor γ: 1.12; Event x′: 0.168; Event ct′: 0.817. All parameters are adjustable with the labeled controls below.−4.69−2.3502.354.69−2.2−1.101.12.2x or x′ · c = 1ct or ct′EE′ct² − x² = 0.64
Original eventTransformed eventLight cone
Lorentz factor γ
1.12
Event x′
0.168
Event ct′
0.817
t = 0 s

A fixed x = 0.6 event is Lorentz transformed with c = 1. Playback highlights the relation between coordinate descriptions; it does not move the event. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA local Lorentz comparison cannot determine a curved spacetime or its global boundary.

Check your understanding

What is fixed geometrically by the usual AdS boundary construction before choosing a Weyl representative?

Try it yourself

For AdS5, so d = 4, take L = 2 km as an illustrative unit choice. Find the scalar curvature R and cosmological constant Λ in inverse square kilometers. Would doubling all Poincaré coordinate labels change these invariants?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Insert the boundary dimension d, not the bulk dimension, into the stated d + 1 formulas.

Compare with the solution

The scalar curvature is R=−4(5)/(2 km)2=−5 km−2R=-4(5)/(2\,\mathrm{km})^2=-5\,\mathrm{km^{-2}}. The cosmological constant is Λ=−4(3)/[2(2 km)2]=−1.5 km−2\Lambda=-4(3)/[2(2\,\mathrm{km})^2]=-1.5\,\mathrm{km^{-2}}. A simultaneous coordinate rescaling of z and x leaves the geometry and these invariants unchanged. Changing the physical radius L would be a different model parameter change, not a coordinate transformation or a prediction about the cosmological constant measured in our universe.

Take it with you

  • AdS bulk and boundary spacetime dimensions differ by one.
  • The conformal boundary is not a finite-distance material wall.
  • Coordinate rescaling does not change the physical curvature radius.

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