Transport momentum and energy between neighboring layers
Compute dilute-gas transport coefficients with their signs, units, and model limitations.
On this page
The question for today
What you’ll understand
- Relate molecular transport to viscosity and heat conductivity.
- Check dynamic versus kinematic coefficient dimensions.
- Explain the BGK Prandtl-number restriction.
Particles crossing between neighboring fluid layers carry the momentum and thermal energy characteristic of the layer they last visited. That transport produces viscous stress and heat conduction even in a gas with no lasting molecular bonds. The coefficient estimates depend on collision physics and the chosen closure, but their dimensions and smoothing signs are robust diagnostics. We will use the explicit BGK predictions while keeping them separate from exact transport coefficients of a specified intermolecular potential.
Momentum transport opposes shear differences
Suppose mean flow in the x direction increases along y. Molecules arriving from larger y tend to carry excess x momentum into a slower layer, while molecules arriving from smaller y carry a deficit. Random motion therefore transports x momentum down its gradient. In the kinetic pressure tensor convention, the off-diagonal momentum flux is minus viscosity times the velocity gradient. The viscous part of the Cauchy stress uses the opposite sign because stress is traction, while the pressure tensor appears as an outward momentum flux.
A dimensional estimate gives dynamic viscosity of order mass density times thermal speed times mean free path. At fixed temperature in a dilute gas, increasing number density increases the carriers but shortens their mean free path approximately inversely. These effects roughly cancel, explaining weak density dependence in the dilute regime. This cancellation fails near dense-fluid correlations, where the simple binary transport picture and collision frequency no longer suffice.
Thermal transport has an additional heat capacity
Molecules crossing a temperature gradient carry excess or deficient random energy, yielding heat flux down the gradient. Thermal conductivity therefore involves not only the flight scale but also energy per temperature carried by each molecule. Fourier’s law relates a heat flux in watts per square metre to a temperature gradient in kelvin per metre; its coefficient has units watts per metre kelvin. It must not be inserted directly as the diffusivity of a temperature equation.
To obtain a thermal diffusivity, divide conductivity by the relevant heat capacity per volume. For an ideal gas at approximately constant pressure, that capacity is mass density times specific heat at constant pressure. In a constrained fixed-density setting, a different caloric factor may appear. The dynamical and thermodynamic constraints matter just as much as the material coefficient. Calling conductivity and diffusivity by the same symbol can conceal this physically important distinction.
One relaxation time ties two coefficients together
First-order BGK gives viscosity equal to pressure times relaxation time. Its conductivity is five halves the gas constant per mass times that viscosity. Their dimensionless Prandtl ratio is therefore one. A more faithful elastic collision calculation can produce the near-two-thirds value characteristic of dilute monatomic gases. This is a model limitation with a concrete consequence: fitting the momentum diffusion time does not independently fit the thermal diffusion time.
The heat lab represents a diffusivity after such conversion. Reset and set mode to 2 and diffusivity to 0.25, then Step twice; predict amplitude exp(−1). Reset and set mode to 2 and diffusivity to 0.5, then Step twice; predict exp(−2). Read the decay rate as diffusivity times squared mode number. The lab has no mass density, viscosity, or heat-capacity control, so it cannot derive gas coefficients or compare Prandtl numbers.
Work it through
Convert a relaxation time into transport
For an illustrative BGK gas take p=8×10⁴ Pa, τ=2.5×10⁻¹⁰ s, kB/m=200 J/(kg·K), and mass density 1 kg/m³. Find η, κ, ν, α, and Pr.
The viscosity is pτ=8×10⁴×2.5×10⁻¹⁰=2×10⁻⁵ Pa·s. Pressure multiplied by time has the required dynamic-viscosity units, rather than diffusivity units.
The specific heat is cp=(5/2)×200=500 J/(kg·K). Conductivity is cpη=500×2×10⁻⁵=0.010 W/(m·K). This equality is the BGK transport relation for the supplied monatomic model.
Divide viscosity by density to get ν=2×10⁻⁵ m²/s. Divide conductivity by ρcp to get α=0.010/500=2×10⁻⁵ m²/s. Their ratio, or cpη/κ, is one, showing that this model ties thermal and momentum diffusion together.
The coefficients are η=2×10⁻⁵ Pa·s and κ=0.010 W/(m·K), with ν=α=2×10⁻⁵ m²/s and Pr=1.
The living notebook
Explore the model
Interactive lab · heat
Use diffusivity rather than conductivity
Reset and set n=2, κ=0.25, then Step twice; predict amplitude exp(−1). Reset and set n=2, κ=0.5, then Step twice; predict exp(−2).
- Current amplitude
- 1
- Spatial L² norm
- 1.772
- Decay rate · κn²
- 3.6 /s
The exact periodic heat-equation mode is u(x,t) = exp(−κn²t) sin(nx), on [0,2π]. Playback advances physical time. The initial sine is shown separately, and the unnormalized L² norm is √π exp(−κn²t). This analytic instrument does not run a finite-difference solver or test discretization stability. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThe control κ is the heat equation’s diffusivity. It is not gas thermal conductivity unless the required heat-capacity conversion has already been performed.
Pause & reason
Check your understanding
Your turn
Try it yourself
A near-equilibrium gas has η=3×10⁻⁵ Pa·s, κ=0.020 W/(m·K), shear gradient ∂yux=20 s⁻¹, and temperature gradient ∂yT=−50 K/m. Find Pxy and qy, including signs.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use the kinetic momentum-flux convention and Fourier’s minus sign; state the transport directions.
Compare with the solution
The off-diagonal kinetic momentum flux is Pxy=−η∂yux=−6×10⁻⁴ Pa. Heat flux is qy=−κ∂yT=+1.0 W/m², toward increasing y where temperature is lower. The associated viscous Cauchy shear stress is +6×10⁻⁴ Pa, opposite in sign to this pressure-tensor contribution.
Keep the idea
Take it with you
- Dynamic viscosity and kinematic viscosity have different dimensions.
- Conductivity becomes a diffusivity only after a heat-capacity conversion.
- Basic BGK predicts Pr=1 and cannot fit both transport channels independently.
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