advanced29 min studyLesson 129 in Physics

Normal coordinates and mode excitation

Project initial displacement and velocity onto mass-normalized modes and predict which collective motions are actually excited.

On this page

What you’ll understand

  • Transform between physical and mass-normalized modal coordinates.
  • Project both displacement and velocity initial conditions.
  • Distinguish genuine two-frequency beating from same-frequency interference.

Finding every normal mode tells us what a linear system can do. Initial conditions tell us what it actually does. A displacement of one mass usually excites several collective patterns, while a carefully prepared displacement can excite just one. Normal coordinates make that distinction explicit by separating the coupled motion into independent oscillators. The transformation also clarifies how energy is distributed and why an apparently complicated exchange between masses can arise from simple phase evolution.

Build the coordinate transformation with its inverse

Collect mass-normalized eigenvectors as columns of a matrix E. Write the physical displacement η as E Q, where Q lists modal coordinates. Since Eᵀ M E is the identity, the inverse projection is Q=Eᵀ Mη. It is not generally E transpose alone. This distinction is easy to miss if all demonstration masses happen to be one. A displacement that looks perpendicular to a mode in a drawing can still have a nonzero mass-weighted projection onto that mode.

Substituting this transformation into the quadratic Lagrangian removes kinetic and potential cross terms. Each modal coordinate obeys its own oscillator equation with the corresponding natural frequency. For positive nonzero frequencies, its solution combines a cosine fixed by initial displacement and a sine fixed by initial velocity. Both projections matter. A mass released at equilibrium with a nonzero velocity can excite a mode whose displacement coefficient is initially zero; looking only at the initial shape would miss it.

η=EQ,Q=ETMη,Qs(t)=Qs(0)cos⁡ωst+Q˙s(0)ωssin⁡ωst\eta=EQ,\qquad Q=E^{\mathsf T}M\eta,\qquad Q_s(t)=Q_s(0)\cos\omega_s t+\frac{\dot Q_s(0)}{\omega_s}\sin\omega_s t
The formula assumes mass-normalized modes and positive nonzero frequencies. Zero-frequency modes require their separate constant-plus-linear-time solution.↔ Scroll wide equations horizontally.

Predict selective excitation and energy

If the initial displacement is proportional to one mode and initial velocity is proportional to the same mode, no other modes are excited in this linear autonomous model. An applied generalized force similarly projects as E transpose times the force vector. Spatial alignment can therefore suppress a resonance even when its frequency is present in the spectrum. This is a selection rule from the forcing pattern, not proof that the unexcited mode does not exist. Small nonlinearities can later couple modes that are independent in the approximation.

The quadratic energy is the sum of one half of modal velocity squared plus one half of frequency squared times modal coordinate squared. In an undamped autonomous linear system, each of those modal energies is constant. The energies assigned to individual physical masses and springs can vary as cross-coordinate contributions rearrange. Calling that behavior energy transfer is useful only after specifying the subsystem definition. It does not mean the independent normal modes are exchanging energy in the exact linear model.

E2=∑s12(Q˙s2+ωs2Qs2),fs(t)=esTF(t)\mathcal E_2=\sum_s\frac12\left(\dot Q_s^2+\omega_s^2Q_s^2\right),\qquad f_s(t)=e_s^{\mathsf T}F(t)
With the stated normalization, each positive-frequency mode has unit modal mass. F is the generalized applied-force vector in the original coordinates.↔ Scroll wide equations horizontally.

Separate interference from a coupled-system simulation

Two frequencies can produce an envelope through trigonometric addition. For nearly equal frequencies, a fast oscillation is modulated by a slow difference-frequency factor, leading to familiar beats. A finite frequency separation still allows the identity but may not look like a slowly varying envelope. Equal frequencies with opposite phase instead give fixed cancellation. These are different statements: changing relative phase at one common frequency cannot reproduce the time-dependent relative phase of unequal-frequency modes.

The waves lab deliberately shows the equal-frequency case: it adds two waves with the same spatial and temporal frequency, controlled by phase difference and amplitude ratio. Predict cancellation at a phase difference of 180 degrees and amplitude ratio one, then test it. It does not have two mode-frequency controls, a mass matrix, or coupled spring energies, so it cannot demonstrate the worked system's beat dynamics. Use its cancellation example to understand superposition, while reconstructing unequal-frequency mechanical motion with the normal-coordinate equations.

Release one of two equal masses

In normalized units M=I and K=[[2,−1],[−1,2]]. Use e₊=(1,1)/√2 with ω₊=1 and e₋=(1,−1)/√2 with ω₋=√3. Initially η=(1,0) and ηdot=(0,0). Reconstruct both coordinates.

  1. Project the initial displacement: Q₊(0)=e₊·(1,0)=1/√2 and Q₋(0)=1/√2. Both modal velocities vanish, so both sine coefficients are zero.

  2. Evolve the independent modes: Q₊=cos t/√2 and Q₋=cos(√3 t)/√2. The original one-mass displacement has excited both collective patterns.

  3. Multiply by E to reconstruct x₁=[cos t+cos(√3 t)]/2 and x₂=[cos t−cos(√3 t)]/2. At t=0 these return x₁=1 and x₂=0 with zero velocities.

x1(t)=cos⁡t+cos⁡(3t)2,x2(t)=cos⁡t−cos⁡(3t)2x_1(t)=\frac{\cos t+\cos(\sqrt3t)}2,\qquad x_2(t)=\frac{\cos t-\cos(\sqrt3t)}2
An arbitrary small physical amplitude can multiply these normalized displacements when applying the linear approximation to a real spring system.↔ Scroll wide equations horizontally.
The result

The physical coordinates combine two distinct frequencies. In this normalized example the modal energies are 1/4 and 3/4, whose sum equals the initial potential energy one.

Explore the model

Interactive lab

Interactive lab · waves

Compare fixed cancellation with two-mode motion

Predict the sum at Phase difference 180 degrees and Amplitude ratio one, then test it. Both displayed waves share a frequency; the lab illustrates superposition and cannot reproduce unequal-frequency modal beats.

Compare fixed cancellation with two-mode motionTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA phase control at one frequency is not equivalent to exciting two different normal-mode frequencies.

Check your understanding

For mass-normalized modes, which initial conditions excite only mode j in the linear autonomous system?

Try it yourself

For the equal-mass example, choose η(0)=(a,a) and ηdot(0)=(0,0). Find the two initial modal coordinates and the resulting motion. How does the central coupling spring behave?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Take the dot products with the symmetric and antisymmetric normalized vectors.

Compare with the solution

Q₊(0)=√2 a and Q₋(0)=0. Therefore x₁=x₂=a cos t. Only the symmetric frequency-one mode is excited. The central spring's extension x₂−x₁ stays zero in the linear model, while the two outer springs provide the restoring forces.

Take it with you

  • Project initial velocities as well as displacements.
  • Mass normalization determines the inverse modal transformation.
  • Equal-frequency cancellation and unequal-frequency beating are distinct.

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