Entanglement and tensor-network states
Use Schmidt weights to quantify bipartite entanglement and understand when matrix-product states compress quantum matter.
On this page
The question for today
What you’ll understand
- Compute a reduced-state entropy from Schmidt probabilities.
- Relate bond dimension to retained information across a cut.
- Identify the regimes where a compact matrix-product ansatz becomes costly.
A chain of L spin-half sites has exponentially many basis amplitudes, but many physically important states occupy a much more structured part of that space. Tensor networks exploit structure in correlations across partitions. Their usefulness is governed by entanglement and the accuracy required, rather than by the number of particles alone. We will start with an exact two-site decomposition, turn its singular values into a truncation rule, and then explain why one-dimensional ground states are often more accessible than generic long-time dynamics.
A cut turns amplitudes into singular values
Divide a pure state into subsystems A and B and arrange its amplitudes into a matrix. Singular-value decomposition writes the state as a sum of paired orthonormal states, with nonnegative coefficients . Their squares sum to one. Tracing out B leaves A with eigenvalues . A global pure state can therefore give a mixed local state: the uncertainty comes from correlations with the omitted subsystem, not from assuming an unknown classical preparation of the whole system.
The von Neumann entropy of that reduced state measures bipartite entanglement for a globally pure state. A product state has one nonzero Schmidt weight and zero entropy. A maximally entangled pair of qubits has two equal weights and entropy using natural logarithms. If the full state is already mixed, reduced-state entropy also contains classical and thermal uncertainty; it is no longer by itself a unique measure of entanglement between the parts. Always state the purity assumption before interpreting the number.
Bond dimension is a controlled compression choice
Repeated decompositions along a one-dimensional chain produce a matrix-product state, or MPS. For an open-chain MPS, a virtual bond index links neighboring tensors and carries correlations across that cut. If its dimension is , the Schmidt rank across that bond is at most and its entropy is at most . For finite open chains every state has an exact MPS representation if sufficiently large bond dimensions are permitted. The computational advantage comes only when a much smaller representation achieves the desired accuracy.
For one cut, retain the largest Schmidt weights and discard the rest. The discarded weight is the sum of the omitted probabilities. After normalizing the truncated state, its squared overlap with the original at that cut is one minus that weight. This is a precise local compression statement. A long sequence of truncations, a time-evolution algorithm, or an approximate variational optimizer needs additional error accounting; one small discarded weight is not a universal bound on every later observable or on a simulation's total error.
Why geometry and time change the cost
For one-dimensional chains with bounded finite-dimensional local spaces and bounded finite-range interactions, a unique ground state separated by a uniformly positive gap obeys an entanglement area law: entropy across a cut stays bounded as chain length grows. This motivates compact MPS approximations, though accuracy is governed by the full Schmidt tail rather than entropy alone. Critical chains can show logarithmically growing entanglement, and approaching small gaps can demand larger bonds. Density-matrix renormalization group optimizes an MPS variationally; it is a numerical method with convergence questions, not an exact solution merely because an area law is expected.
Generic highly excited states and long-time unitary dynamics can develop much more entanglement. A global quench often produces approximately linear growth before finite-size saturation, forcing the bond dimension needed for fixed accuracy to increase rapidly. Representing a two-dimensional system as a one-dimensional ordering also creates wider cuts and growing cost. Tensor-network variants exploit other geometries, but their contractions and optimization introduce further challenges. Report size, boundary conditions, retained bonds, discarded weights, and observable convergence rather than advertise compression without an error target.
Work it through
Compress one entangled pair
For |ψ⟩ = √0.8|00⟩ + √0.2|11⟩, calculate the entropy of the first qubit and the fidelity after keeping only the largest Schmidt component.
The displayed basis is already a Schmidt basis. The reduced state is diagonal with probabilities and .
Compute nats, or about bits. This is below the qubit maximum nats.
Keeping one component discards weight . The normalized retained state is , whose squared overlap with the original is .
Bond dimension two represents the pair exactly across this cut. Bond dimension one produces a product state and a measurable loss of overlap; it cannot preserve the entanglement.
The living notebook
Explore the model
Interactive lab · probability
Read two Schmidt weights as probabilities
Set the binomial trial count to one and choose success probability p = 0.8. The two exact bars are then 0.2 and 0.8, matching the two Schmidt probabilities up to order in the worked example. The lab is a binomial probability model, not an entangled-state simulator, and it does not calculate entropy, tensor contractions, or truncation error.
- Mean · np
- 5
- Variance · np(1−p)
- 2.5
- Total probability
- 1
These are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forSchmidt probabilities form a normalized spectrum. Quantum entanglement additionally requires the global pure-state structure, which these probability bars alone do not establish.
Pause & reason
Check your understanding
Your turn
Try it yourself
Replace the pair by (|00⟩+|11⟩)/√2. Calculate its entropy and the best squared overlap of a normalized one-component Schmidt truncation.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Both Schmidt probabilities are one half. Retaining either component gives the same answer.
Compare with the solution
The entropy is −2 × (1/2) log(1/2) = log 2 nats, or one bit. A one-component truncation discards weight 1/2 and has squared overlap 1/2 with the original. Bond dimension two is necessary for an exact representation across this cut, while bond dimension one can only represent a product state.
Keep the idea
Take it with you
- Schmidt probabilities quantify bipartite entanglement of a pure state.
- Bond dimension limits rank, while discarded weights diagnose a particular compression.
- Area laws, dimension, dynamics, and required accuracy determine when tensor networks remain efficient.
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