advanced27 min studyLesson 467 in Physics

Franck–Condon factors and electronic transitions

Factor electronic and nuclear transition amplitudes, derive a displaced-oscillator progression, and separate overlap weights from complete measured intensities.

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What you’ll understand

  • State the Condon approximation and define a Franck–Condon factor.
  • Calculate simple displaced-harmonic overlap weights.
  • Explain how geometry changes can redistribute intensity without changing electronic selection rules.

An electronic excitation changes the potential felt by the nuclei. The nuclei do not immediately jump to the new equilibrium bond length, so the initially occupied nuclear wavefunction overlaps several vibrational states of the excited surface. That overlap produces vibrational progressions in electronic spectra. Franck–Condon factors quantify this distribution under a specified transition-moment approximation. They do not replace the electronic selection rule or the other ingredients of measured intensity, but they connect a spectral envelope to changes in molecular geometry with unusual directness.

A transition samples overlapping nuclear states

For two electronic surfaces a and b, integrate electronic coordinates first to obtain an electronic transition-dipole function of nuclear geometry. The remaining nuclear amplitude is the integral of this function between the initial and final vibrational wavefunctions. The Condon approximation replaces that electronic function by a constant over the nuclear region contributing significantly. The squared nuclear overlap is then the Franck–Condon factor. This approximation can fail when the transition dipole varies rapidly or vanishes by symmetry at the reference geometry.

The common vertical-transition picture means the electronic interaction is fast compared with nuclear rearrangement, so the initial nuclear coordinate distribution is projected onto a different surface before it relaxes. It is not a claim that a molecule follows a single classical coordinate with no quantum spread. The final vibrational distribution depends on wavefunction overlaps, including their signs and nodes. Rotational factors, electronic transition strength, photon-frequency factors, and initial populations must still be included to compare actual absorption or emission intensities.

Mbv′,av=∫χbv′∗(R) μba(R) χav(R) dR≃μba(R∗)⟨χbv′∣χav⟩,fv′v=∣⟨χbv′∣χav⟩∣2M_{bv',av}=\int\chi_{bv'}^*(R)\,\mu_{ba}(R)\,\chi_{av}(R)\,dR\simeq\mu_{ba}(R_*)\langle\chi_{bv'}|\chi_{av}\rangle,\qquad f_{v'v}=|\langle\chi_{bv'}|\chi_{av}\rangle|^2
The displayed reduction is the Condon approximation. The factor f is dimensionless and is an overlap probability weight, not the complete electronic oscillator strength or a measured spectral line intensity.↔ Scroll wide equations horizontally.

A displaced harmonic pair gives an exact model progression

Take one nuclear coordinate with the same reduced mass and harmonic angular frequency on both surfaces, but equilibrium positions separated by d. Start in the lower surface’s vibrational ground state. The displacement measured in oscillator-width units defines a dimensionless parameter S=μωd2/(2ℏ)S=\mu\omega d^2/(2\hbar). Overlapping the two Gaussian ground states gives amplitude e−S/2e^{-S/2} and therefore zero-to-zero factor e−Se^{-S}. A larger displacement suppresses that origin band without requiring a weaker electronic dipole.

Expanding the displaced ground state in the upper oscillator’s number basis gives weights e−SSn/n!e^{-S}S^n/n!. These form a Poisson distribution with mean S, and their sum over the complete infinite harmonic ladder is one. The derivation uses identical curvatures, one mode, an initial ground vibration, and a constant transition dipole. It does not justify a Poisson envelope for arbitrary anharmonic or many-mode molecules, where mode rotations and changed frequencies can reshape the overlaps.

S=μωd22ℏ,fn0=e−SSnn!,∑n=0∞fn0=1,⟨n⟩=SS=\frac{\mu\omega d^2}{2\hbar},\qquad f_{n0}=e^{-S}\frac{S^n}{n!},\qquad \sum_{n=0}^{\infty}f_{n0}=1,\qquad \langle n\rangle=S
Here S is the dimensionless displacement or Huang–Rhys parameter, not thermodynamic entropy. Mu is nuclear reduced mass, omega is angular frequency, d is a length, and n is the final oscillator quantum number.↔ Scroll wide equations horizontally.

An envelope is informative but model dependent

When two surfaces have similar equilibrium geometries, low-vibrational overlaps can dominate. Larger displacement distributes weight among higher final vibrations, so the strongest observed transition need not be the electronic origin. This explains why a vertical absorption maximum and the relaxed electronic energy difference can differ. Emission after nuclear relaxation starts from a different initial nuclear state and can produce a shifted envelope, even before solvent or other environmental effects are considered.

Extracting geometry from intensities requires checking those assumptions rather than simply reading a peak number as a bond displacement. Non-Condon transition moments can borrow intensity, thermal occupation adds hot bands, and overlapping rotational structure or linewidths can obscure individual weights. Isotopes also change oscillator widths through reduced mass while leaving the leading electronic equilibrium displacement similar. The overlap calculation below is therefore an exact result for a declared illustrative model and a useful diagnostic starting point for richer spectroscopy.

Where does the overlap weight go?

For the equal-curvature displaced-oscillator model take S = 1 and an initial vibrational ground state. Find the final n = 0, 1, 2 overlap factors, their sum, and the remaining weight above n = 2.

  1. The zero-to-zero factor is f00=e−1≃0.3679f_{00}=e^{-1}\simeq0.3679. For n = 1 the factor is also e−1≃0.3679e^{-1}\simeq0.3679, because S and 1! are both one.

  2. For n = 2, divide by 2!=22!=2 to obtain f20=e−1/2≃0.1839f_{20}=e^{-1}/2\simeq0.1839. These are overlap weights before other spectral factors.

  3. The three weights sum to 2.5/e≃0.91972.5/e\simeq0.9197. Completeness gives the remaining weight 1−2.5/e≃0.08031-2.5/e\simeq0.0803, so truncating the model to these three final levels loses about eight percent.

The result

The first three overlap factors are approximately 0.368, 0.368, and 0.184. Their sum is 0.920, leaving about 0.080 in higher vibrational levels.

Explore the model

Interactive lab

Interactive lab · probability

Probability normalization is a separate check

Use exact binomial probabilities only as a normalization analogy. Reset, set Success probability p = 0.5 and Trials n = 2, and predict mean 1. For a fresh comparison Reset, set p = 0.5 and n = 4, and predict mean 2. The displayed distributions are exact, not resampled.

Probability normalization is a separate checkThese are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Current readings: Mean · np: 5; Variance · np(1−p): 2.5; Total probability: 1. All parameters are adjustable with the labeled controls below.03581000.070.150.220.3Successes kP(X = k)k = 0 · P = 9.77e-4
Exact probabilityHighlighted outcomeMean np
Mean · np
5
Variance · np(1−p)
2.5
Total probability
1
t = 0 s

These are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThese are binomial distributions, not the Poisson Franck–Condon progression. The lab has no displacement or molecular potential controls and cannot calculate vibrational overlap integrals.

Check your understanding

Under the Condon approximation, what is a Franck–Condon factor?

Try it yourself

In an equal-curvature displaced-oscillator model, the zero-to-zero overlap factor is 1/2. Isotope substitution quadruples reduced mass while retaining the force constants and displacement on both surfaces. Find the new zero-to-zero factor.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

At fixed force constant omega scales as inverse square root of mass, so the product mu omega changes differently from either factor alone.

Compare with the solution

Quadrupling mass halves angular frequency, so μω\mu\omega doubles. The displacement parameter S therefore doubles. Since the old factor is e−S=1/2e^{-S}=1/2, the new one is e−2S=(1/2)2=1/4e^{-2S}=(1/2)^2=1/4. This isotope-dependent overlap change can occur on unchanged leading electronic surfaces and does not by itself imply nonadiabatic coupling.

Take it with you

  • Franck–Condon weights describe nuclear overlaps after a stated electronic transition-moment approximation.
  • The Poisson progression is specific to a displaced equal-curvature oscillator starting in its ground vibration.
  • Intensity envelopes reveal geometry only after populations, transition operators, and other spectral factors are accounted for.

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