core36 min studyLesson 120 in Physics

Kepler geometry and time-averaged energy

Relate two-body inverse-square motion to orbital elements, the vis-viva equation, and the bounded-motion assumptions behind the virial relation.

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What you’ll understand

  • Distinguish a two-body relative orbit from either body's barycentric orbit.
  • Calculate bound-orbit speed and period with a consistent gravitational parameter.
  • Explain why the virial relation is an average and requires a controlled boundary term.

The inverse-square gravitational interaction is special: isolated Newtonian two-body bound trajectories with nonzero angular momentum are closed ellipses in their relative coordinate. Radial point-mass collisions are excluded from this regular-orbit statement. Kepler's geometric laws, the orbital energy relation, and the virial theorem describe different aspects of this same model. They should reinforce one another without being treated as interchangeable formulas. State whether a radius describes the separation of the bodies or one body's distance from their common center of mass before assigning masses or interpreting a measured orbital period.

The relative ellipse belongs to a two-body model

For two isolated point masses, separate the inertial motion of their center of mass from the relative coordinate joining them. The relative separation obeys an inverse-square acceleration with gravitational parameter G times the sum of the masses. A noncolliding bound orbit with nonzero angular momentum has negative specific relative energy and eccentricity below one; its relative trajectory is an ellipse with one focus at the origin of that relative coordinate. Each physical body traces its own scaled ellipse around the barycenter. Replacing the mass sum by the larger mass is a controlled approximation only when the other mass is sufficiently small.

Angular-momentum conservation makes the areal sweep rate constant. The object therefore moves faster near closest approach and slower near farthest separation. This is a time statement, not just an ellipse-drawing rule. The orbital period depends on the relative ellipse's semimajor axis, not its instantaneous radius or the average of arbitrary sampled positions. The closed conic result assumes an exact inverse-square central interaction with no drag, additional bodies, or relativistic corrections. Small violations can produce precession or secular evolution without making the two-body approximation useless as a leading description.

P2=4π2a3G,G=G(M+m),rp=a(1−e),ra=a(1+e)P^2=\frac{4\pi^2a^3}{\mathcal G},\qquad \mathcal G=G(M+m),\qquad r_p=a(1-e),\quad r_a=a(1+e)
For a bound isolated Newtonian two-body relative orbit, a is its semimajor axis, e its eccentricity, and 𝒢 the gravitational parameter in m³/s². P is the period and rp, ra are pericenter and apocenter separations.↔ Scroll wide equations horizontally.

Energy predicts speed at any allowed radius

Write energy per unit reduced mass for the relative motion. In the inverse-square problem its bound-orbit value is minus the gravitational parameter divided by twice the semimajor axis. Equating that constant to one half relative speed squared minus the gravitational parameter over radius gives the vis-viva equation. It predicts speed magnitude at an allowed separation, but not the direction of velocity or where the orbit lies in space. Angular momentum and orientation data supply the missing information. A radius outside the orbit's turning points cannot become physical merely because the speed expression is algebraically positive.

For a circular orbit, radius equals semimajor axis and the speed reduces to the square root of gravitational parameter divided by radius. At a fixed separation, escape speed is the zero-energy value and exceeds circular speed by the square root of two. These comparisons use the same potential zero at infinite separation. Adding a constant to the potential changes the numerical energy reference, so a statement that negative energy means bound must name the convention. It also presumes an attractive inverse-distance potential with suitable asymptotic behavior; energy-sign classifications are not universal for every central force.

ε=v22−Gr=−G2a,v2=G(2r−1a)\varepsilon=\frac{v^2}{2}-\frac{\mathcal G}{r}=-\frac{\mathcal G}{2a},\qquad v^2=\mathcal G\left(\frac2r-\frac1a\right)
ε is energy per unit reduced mass and v is relative speed, not automatically the speed of either body about the barycenter. This bound-orbit formula uses zero gravitational potential at infinite separation.↔ Scroll wide equations horizontally.

The virial relation requires an average and a vanishing boundary term

Define a virial quantity as the dot product of relative position with relative momentum. Differentiating it gives twice kinetic energy plus position dotted into force. For inverse-distance attraction, that force term equals the potential energy, yielding a derivative equal to twice kinetic plus potential energy. Average over one complete periodic orbit: the virial quantity returns to its starting value, so the average derivative vanishes. Thus twice the average kinetic energy plus average potential energy is zero. Neither kinetic nor potential energy must be constant separately on an eccentric orbit.

For a more general long-time average, justify why the endpoint difference in the virial quantity divided by averaging duration tends to zero. A bounded periodic orbit satisfies this condition, but an escaping trajectory does not automatically do so. Nor does one instantaneous measurement establish virial equilibrium for a many-body system with evolving boundaries or external tides. In the isolated Kepler problem, the averaged relation connects total energy to the mean kinetic and potential energies and implies that the time average of inverse separation equals inverse semimajor axis. This is a useful consistency check on numerical orbit sampling, especially when uneven speed makes uniform-angle sampling different from uniform-time sampling.

ddt(r⋅p)=2T+V,2⟨T⟩+⟨V⟩=0\frac{d}{dt}(\mathbf r\cdot\mathbf p)=2T+V,\qquad 2\langle T\rangle+\langle V\rangle=0
For the isolated inverse-distance relative problem, the averaged equality follows when the endpoint virial term divided by the averaging interval vanishes, in particular over a full bound-orbit period. It is not generally an instantaneous equality.↔ Scroll wide equations horizontally.

An eccentric orbit in normalized units

Let the gravitational parameter be G=4\mathcal G=4 in consistent units. A relative ellipse has semimajor axis a=2a=2 and eccentricity e=1/2e=1/2. Find the closest and farthest separations, their speeds, and the orbital period.

  1. The turning separations are rp=2(1−1/2)=1r_p=2(1-1/2)=1 and ra=2(1+1/2)=3r_a=2(1+1/2)=3. Specific orbital energy is ε=−4/(2×2)=−1\varepsilon=-4/(2\times2)=-1.

  2. Vis-viva gives vp2=4(2−1/2)=6v_p^2=4(2-1/2)=6 and va2=4(2/3−1/2)=2/3v_a^2=4(2/3-1/2)=2/3. Thus vp=6v_p=\sqrt6 and va=2/3v_a=\sqrt{2/3}. At both apsides velocity is tangential, and rpvp=rava=6r_pv_p=r_av_a=\sqrt6, checking angular momentum.

  3. The period is P=2πa3/G=2π2P=2\pi\sqrt{a^3/\mathcal G}=2\pi\sqrt2. The virial relation gives mean kinetic energy per unit reduced mass ⟨T⟩/μ=1\langle T\rangle/\mu=1 and mean potential energy per unit reduced mass ⟨V⟩/μ=−2\langle V\rangle/\mu=-2, whose sum is the specific total energy −1.

The result

The closest-approach speed is three times the farthest-point speed. Energy and angular momentum agree with the orbital geometry, while the averaged virial values differ from most instantaneous values.

Explore the model

Interactive lab

Interactive lab · function

Test a circular-orbit scaling comparison

Set coefficient a to 0.5 and position x to 1, then 2: normalized kinetic energy rises from 0.5 to 2. With positive a and nonnegative x, y = ax² illustrates speed-squared energy dependence. Only the circular orbits compatible with the chosen gravitational parameter supply the corresponding radii. The lab does not draw Kepler ellipses, vary orbital elements, or verify a virial time average.

Test a circular-orbit scaling comparisonThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forEnergy scales quadratically with speed, while the orbit determines which speeds and radii are compatible.

Check your understanding

Which statement correctly uses the virial relation for a bound eccentric Kepler orbit?

Try it yourself

For the same isolated two-body model, a circular orbit has radius R and period P. A second circular orbit has radius 4R. Compare its speed, period, and specific orbital energy with the first.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use circular speed proportional to inverse square root of radius, Kepler period proportional to radius to the power 3/2, and energy −𝒢/(2R).

Compare with the solution

The speed is half the first orbit's speed, because v∝R−1/2v\propto R^{-1/2}. The period is 43/2P=8P4^{3/2}P=8P. Specific energy is one quarter of the original negative energy: ε2=ε1/4\varepsilon_2=\varepsilon_1/4, so it is less negative and closer to escape. These comparisons hold at fixed gravitational parameter and do not include perturbing bodies or atmospheric drag.

Take it with you

  • Kepler's two-body parameter uses the mass sum, and the relative ellipse differs from each barycentric ellipse.
  • Vis-viva connects energy, separation, and speed within the allowed orbit.
  • The virial theorem is an averaged statement whose endpoint term must be controlled.

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