advanced35 min studyLesson 394 in Physics

Born approximation and Fourier potentials

Compute weak-potential amplitudes with an explicit Fourier convention and identify when repeated scattering cannot be neglected.

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What you’ll understand

  • Derive the first Born amplitude from a weak induced source.
  • Convert angle to wavenumber transfer with the correct units.
  • State sufficient weak-potential checks and the Coulomb exception.

At weak coupling, the wave inside an interaction region differs little from the incident plane wave. The first Born approximation uses that observation to replace an unknown exact scattering state inside a source integral by a known free state. The outgoing amplitude then samples a Fourier component of the potential. This is a powerful connection between angular structure and spatial structure, but neither a visually small potential nor a familiar final formula guarantees its validity.

Declare the transform and its prefactor

Take the incident wavevector k\mathbf k and outgoing wavevector k′\mathbf k' to have equal magnitude in elastic scattering. Define the transferred wavevector as outgoing minus incoming. It has inverse-length units; the transferred momentum is reduced Planck constant times that vector. Choose a Fourier transform with a negative exponential and no normalization factors inside its spatial integral. A different transform convention can move numerical factors, so it must be stated before comparing amplitudes from different references.

The scattered field is generated by the potential multiplied by the exact wave in the interaction region. At first order replace that exact wave by the incident plane wave, and use the far-field outgoing Green function. The incident phase and outgoing observation phase combine into the Fourier exponential. The resulting minus sign and mass factor follow from the Schrödinger Green function, not from whether the potential is attractive or repulsive. For a real central potential the resulting first-order amplitude is real.

V~(q)=∫d3r e−iq⋅rV(r),q=k′−k,fB=−μ2πℏ2V~(q)\widetilde V(\mathbf q)=\int d^3r\,e^{-i\mathbf q\cdot\mathbf r}V(\mathbf r),\quad \mathbf q=\mathbf k^\prime-\mathbf k,\quad f_B=-\frac{\mu}{2\pi\hbar^2}\widetilde V(\mathbf q)
V is an energy, Ṽ has energy times volume, q has m⁻¹ and fB has m. The prefactor uses the previously fixed unit incident amplitude plus outgoing f eⁱᵏʳ/r convention.↔ Scroll wide equations horizontally.

Relate spatial range to angular variation

For a central potential, the angular part of the Fourier integral can be performed by aligning its polar axis with the transfer vector. The remaining radial integral contains a sine divided by its argument. Small scattering angles correspond to small transfer, which probes the spatially integrated potential. Large transfer produces stronger cancellation among separated regions of a smooth potential. Consequently a smooth long-range but screened interaction often concentrates scattering toward forward angles without making the scattered state a classical trajectory.

A screened Coulomb or Yukawa potential supplies a soluble example. Its radial transform is a rational function of the squared transfer and inverse screening length. The screening scale regularizes the forward amplitude. Sending the screening length to infinity is not an innocuous way to recover every short-range assumption: the Coulomb limit changes the asymptotic wave and creates a forward singularity. Although its Born intensity has the Rutherford form, that special agreement does not prove the unmodified short-range wavefunction or perturbation argument is valid.

fB(q)=−2μℏ2q∫0∞rV(r)sin⁡(qr) dr,V(r)=ge−βrr⇒fB=−Cq2+β2,C=2μgℏ2f_B(q)=-\frac{2\mu}{\hbar^2q}\int_0^\infty rV(r)\sin(qr)\,dr,\qquad V(r)=g\frac{e^{-\beta r}}r\Rightarrow f_B=-\frac{C}{q^2+\beta^2},\quad C=\frac{2\mu g}{\hbar^2}
g has energy times length, β is a positive inverse screening length and C has inverse-length units. The radial expression has a continuous q → 0 limit when its integral converges.↔ Scroll wide equations horizontally.

Test the weak-wave-distortion assumption

The approximation is controlled when the rescattered correction is small within the interaction region, not merely when the far-field amplitude is small at a detector angle. For a bounded finite-range potential of characteristic strength and range, a small ratio of potential energy to confinement-scale kinetic energy is a useful sufficient low-energy estimate. At high incident energy, small accumulated scattering phase can support a different regime. Neither estimate is a universal necessary-and-sufficient criterion for arbitrary singular or resonant potentials.

Near a bound-state threshold or a narrow resonance, repeated encounters can strongly distort the internal wave even when a naive coupling comparison looks moderate. The first Born term then fails to capture the large scattering length or the unitary resonant limit. Its apparent optical-theorem mismatch also requires order-consistent interpretation rather than arbitrary repair. The schematic scattering lab uses a fourth power of its coupling control; a physical first Born amplitude is linear in a potential-strength parameter and its leading cross section is quadratic, so those are deliberately different scaling laws.

q=2ksin⁡(θ/2),2μ∣V0∣R2ℏ2≪1(useful finite-range weak-potential estimate)q=2k\sin(\theta/2),\qquad \frac{2\mu |V_0|R^2}{\hbar^2}\ll1\quad\text{(useful finite-range weak-potential estimate)}
θ is the elastic scattering angle in radians, R a characteristic range and V0 a characteristic bounded strength. The dimensionless estimate is not valid as a universal test for unscreened Coulomb or arbitrary singular potentials.↔ Scroll wide equations horizontally.

Screening sets a forward-to-backward ratio

For a weak Yukawa potential take β=1.0 nm−1\beta=1.0\,\mathrm{nm^{-1}}, C=0.020 nm−1C=0.020\,\mathrm{nm^{-1}} and incident k=0.50 nm−1k=0.50\,\mathrm{nm^{-1}}. Assume the Born regime. Find the forward and backward amplitudes and their differential cross-section ratio.

  1. Forward scattering has q=0q=0, giving fB(0)=−C/β2=−0.020 nmf_B(0)=-C/\beta^2=-0.020\,\mathrm{nm}. The inverse-length numerator divided by an inverse-area denominator correctly produces length.

  2. Backward scattering has θ=π\theta=\pi and q=2k=1.0 nm−1q=2k=1.0\,\mathrm{nm^{-1}}. The denominator doubles to 2.0 nm−22.0\,\mathrm{nm^{-2}}, giving fB(π)=−0.010 nmf_B(\pi)=-0.010\,\mathrm{nm}.

  3. Squaring gives forward and backward differential areas 4.0×10−44.0\times10^{-4} and 1.0×10−4 nm2/sr1.0\times10^{-4}\,\mathrm{nm^2/sr}. The backward-to-forward ratio is one quarter, not one half, because a cross section squares the amplitude.

The result

The amplitudes are −0.020 nm forward and −0.010 nm backward, giving a backward/forward differential cross-section ratio of 1/4.

Explore the model

Interactive lab

Interactive lab · scattering

Audit the schematic coupling exponent

Reset and set BOTH Coupling g = 0.50 and Scattering angle θ = 90°; predict exact schematic weight 0.0625 (displayed as 0.063). Reset and set g = 1 and θ = 90°; predict weight 1, a factor of sixteen. This follows the lab’s declared g⁴ weight, not a computed potential cross section. A Born cross section under doubling a parameter that multiplies V instead grows by four at leading order; the lab control has no such physical identification.

Audit the schematic coupling exponentA schematic term diagram with dimensionless weight g⁴(1 + cos²θ). Lines denote terms, not particle paths; this is not a process cross-section or loop calculation. Current readings: Coupling factor g⁴: 0.24; Angular factor 1 + cos²θ: 1.329; Illustrative weight: 0.319. All parameters are adjustable with the labeled controls below.Incoming termsOutgoing termsθSchematic interaction term · no particle trajectories
Incoming termsOutgoing termsAngle θ
Coupling factor g⁴
0.24
Angular factor 1 + cos²θ
1.329
Illustrative weight
0.319
t = 0 s

A schematic term diagram with dimensionless weight g⁴(1 + cos²θ). Lines denote terms, not particle paths; this is not a process cross-section or loop calculation. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA coupling exponent cannot be interpreted until the interaction and amplitude conventions are defined.

Check your understanding

If a weak potential V is multiplied by two while the Born approximation remains valid, how does its leading differential cross section change?

Try it yourself

A Gaussian potential V=V0e−r2/R2V=V_0e^{-r^2/R^2} has transform V~=π3/2V0R3e−q2R2/4\widetilde V=\pi^{3/2}V_0R^3e^{-q^2R^2/4}. At kR=1kR=1, find the ratio of backward to forward Born amplitudes and the corresponding differential cross-section ratio. State which assumption is still needed.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Backward transfer is 2k, so q²R²/4 equals one. The transform shape alone says nothing about the absolute potential strength.

Compare with the solution

The backward amplitude is e−1e^{-1} times the forward amplitude, with the same real sign for real V0. Its differential cross section is therefore e−2≈0.135e^{-2}\approx0.135 of the forward value. The condition kR=1kR=1 only specifies the angular-transfer scale; it does not establish weak scattering. One still needs a sufficiently small internal wave distortion, for example a suitable weak finite-range strength estimate, and must exclude a resonant situation. Doubling V0 would leave this angular ratio unchanged while multiplying both leading differential cross sections by four if that regime remains valid.

Take it with you

  • The Born transform has a convention-dependent prefactor and a dimensionful amplitude.
  • Transfer is a wavevector; multiplying by ℏ produces transferred momentum.
  • Weak internal distortion and proper long-range assumptions control the approximation.

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