advanced34 min studyLesson 586 in Physics

Compound nuclei and Breit–Wigner resonances

Relate formation, partial decay widths, spin averaging, and inverse-channel reciprocity for an isolated resonance.

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What you’ll understand

  • Compute a resonance peak from partial widths and a spin statistical factor.
  • Distinguish an isolated-resonance approximation from an overlapping statistical regime.
  • Apply detailed balance between specified inverse two-body channels.

A nuclear collision can form a long-lived intermediate excitation before particles or photons emerge. In a compound-nucleus description, many internal degrees of freedom share the excitation, making entrance formation and subsequent decay approximately separable at fixed conserved quantum numbers. An isolated resonance gives a simple quantitative line shape. The same calculation also shows why a branching ratio, total lifetime, peak cross section, and inverse reaction cross section are related but different quantities.

A total width contains every open exit

A resonance state can decay through several allowed channels, each with a partial energy width. Their sum is the total width, and the fraction assigned to a given exit is its branching probability in the exponential-decay approximation. Time reversal relates coupling into a specified entrance to coupling out through its inverse channel. It does not equate that entrance partial width with the sum of all decay widths. The total mean lifetime is set by the total width.

The compound hypothesis suppresses detailed memory of the entrance mechanism after equilibration, but retains energy, angular momentum, parity, and any other relevant conserved quantities. It therefore does not justify identical decay patterns for arbitrarily different resonance spins or excitation energies. Direct reactions can coexist and interfere, especially in the elastic channel. A formation-times-branching description is an approximation whose usefulness depends on the degree of internal mixing and the energy resolution of the experiment.

Γ=∑cΓc,bb=ΓbΓ,τ=ℏΓ,gJ=2J+1(2sa+1)(2IA+1)\Gamma=\sum_c\Gamma_c,\qquad b_b=\frac{\Gamma_b}{\Gamma},\qquad\tau=\frac{\hbar}{\Gamma},\qquad g_J=\frac{2J+1}{(2s_a+1)(2I_A+1)}
Γc and Γ are energy widths in the same unit, τ is seconds when ℏ uses the matching energy–second unit, and gJ is dimensionless. The statistical factor averages unpolarized distinguishable projectile and target spins sa and IA for one compound spin J.↔ Scroll wide equations horizontally.

One pole produces a conditional Lorentzian approximation

For a single isolated resonance, the reaction cross section contains the product of entrance and exit partial widths divided by detuning squared plus one quarter of total width squared. The prefactor is an entrance-channel wavelength area times the spin factor. Near a narrow resonance, treating that area and the widths as constant gives a Lorentzian whose full width at half maximum equals the total width. At the peak, the entrance-to-exit coupling balance matters as much as the lifetime.

This constant-width approximation requires a resonance well separated from neighbors, a background that can be neglected or explicitly modeled, and sufficiently slow energy variation of penetrabilities and wave number across the width. Threshold-adjacent or broad resonances can violate these assumptions. If many levels overlap, adding isolated probabilities can miss interference and statistical correlations. Experimental beam spread, Doppler broadening, and resolution convolutions can also make a measured line wider than the natural width.

σa→b(E)=πka2 gJ ΓaΓb(E−Er)2+Γ2/4\sigma_{a\to b}(E)=\frac{\pi}{k_a^2}\,g_J\,\frac{\Gamma_a\Gamma_b}{(E-E_r)^2+\Gamma^2/4}
E and Er are entrance centre-of-mass energies for the specified channel, ka is the entrance relative wave number in inverse length, and σ is an area. This is a single isolated resonance contribution for unpolarized distinguishable particles; it omits a nonresonant amplitude and its interference.↔ Scroll wide equations horizontally.

Inverse reactions require both spin and phase-space factors

For time-reversal-invariant dynamics, the same resonance couplings appear in the inverse process at the same total energy. However, cross sections divide a transition rate by incident flux and average over initial spin states. Different channel momenta and spin degeneracies therefore produce different forward and reverse cross sections. Detailed balance compares their spin-degeneracy times momentum-squared weighted values, rather than asserting that the raw cross sections are equal.

This comparison must specify individual target and residual internal states. Thermally populated excited nuclei require an additional ensemble average; a laboratory ground-state cross section cannot simply be used as that stellar average. Identical particles and polarization also require appropriate counting conventions beyond the simple distinguishable spin-average formula. Before applying reciprocity, check that both channels are open at the chosen total energy and that the inverse calculation uses its own centre-of-mass wave number.

daka2σa→b=dbkb2σb→a,da=(2sa+1)(2IA+1),db=(2sb+1)(2IB+1)d_a k_a^2\sigma_{a\to b}=d_b k_b^2\sigma_{b\to a},\qquad d_a=(2s_a+1)(2I_A+1),\quad d_b=(2s_b+1)(2I_B+1)
This reciprocity relation compares specified inverse two-body channels at the same total energy under time-reversal-invariant dynamics. The particles are distinguishable and unpolarized, k values are their respective relative wave numbers, spin degeneracies d are dimensionless, and each σ is the integrated cross section with consistent final-state counting.↔ Scroll wide equations horizontally.

A spin-averaged isolated peak

A toy isolated compound level has J=1J=1, entrance spins sa=IA=1/2s_a=I_A=1/2, partial widths Γa=2 eV\Gamma_a=2\,\mathrm{eV} and Γb=3 eV\Gamma_b=3\,\mathrm{eV}, and no other channels. Locally take π/ka2=2 b\pi/k_a^2=2\,\mathrm b. Find the peak cross section, exit-b branching fraction, and mean lifetime using ℏ=6.58×10−16 eV s\hbar=6.58\times10^{-16}\,\mathrm{eV\,s}.

  1. The total width is 2+3=5 eV2+3=5\,\mathrm{eV}, and the statistical factor is (2J+1)/[(2sa+1)(2IA+1)]=3/4(2J+1)/[(2s_a+1)(2I_A+1)]=3/4. This is an unpolarized entrance average, not an extra decay branch.

  2. At the resonance energy, the width ratio is 4ΓaΓb/Γ2=4(2)(3)/25=24/254\Gamma_a\Gamma_b/\Gamma^2=4(2)(3)/25=24/25. Multiplying by the area and spin factor gives 2(3/4)(24/25)=1.44 b2(3/4)(24/25)=1.44\,\mathrm b.

  3. The exit-b branching fraction is 3/5=0.63/5=0.6. The mean lifetime is 6.58×10−16/5=1.316×10−16 s6.58\times10^{-16}/5=1.316\times10^{-16}\,\mathrm s, and the natural full width is 5 eV under the constant-width approximation.

The result

The peak reaction cross section is 1.44 b, the exit-b fraction is 0.60, and the mean lifetime is 1.316 × 10⁻¹⁶ s. A short lifetime alone does not determine the peak height.

Explore the model

Interactive lab

Interactive lab · probability

A branch fraction tested through repeated decays

Reset and set both controls to p = 0.60 and n = 10 for independent preparations of the toy resonance. Predict mean exit-b count 6 and variance 2.4. The lab displays exact binomial branch counts, with no resonance-energy, spin, width, or line-shape controls; it is not a Breit–Wigner cross-section solver.

A branch fraction tested through repeated decaysThese are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Current readings: Mean · np: 5; Variance · np(1−p): 2.5; Total probability: 1. All parameters are adjustable with the labeled controls below.03581000.070.150.220.3Successes kP(X = k)k = 0 · P = 9.77e-4
Exact probabilityHighlighted outcomeMean np
Mean · np
5
Variance · np(1−p)
2.5
Total probability
1
t = 0 s

These are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forBranch probabilities enter counting statistics, while formation and wavelength factors separately set cross sections.

Check your understanding

When is the constant-width single-resonance Breit–Wigner expression most justified?

Try it yourself

For distinguishable unpolarized inverse two-body channels at one total energy, use daka2σa→b=dbkb2σb→ad_a k_a^2\sigma_{a\to b}=d_b k_b^2\sigma_{b\to a}, with spin degeneracies da=4d_a=4, db=2d_b=2, and kb2=2ka2k_b^2=2k_a^2. If the forward cross section is 0.30 b, find the inverse value and explain which factors compensate.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Keep the degeneracy and momentum ratio together before cancelling ka².

Compare with the solution

The weighted relation gives 4ka2(0.30)=2(2ka2)σb→a4k_a^2(0.30)=2(2k_a^2)\sigma_{b\to a}, so the inverse cross section is also 0.30 b in this particular case. Equality occurs because the smaller inverse spin degeneracy is exactly compensated by its larger momentum squared; it is not a general rule that inverse cross sections match. Both channels must be compared at the same total energy and for the specified internal states.

Take it with you

  • Total and partial widths determine different resonance observables.
  • Spin averaging and entrance wavelength affect a resonance peak.
  • Detailed balance includes channel phase space and internal-state degeneracies.

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