advanced30 min studyLesson 578 in Physics

Nuclear pairing and odd-even masses

Use explicit mass-difference conventions to diagnose pairing while distinguishing empirical staggering from a model gap.

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What you’ll understand

  • Calculate one-neutron separation staggering and a signed three-point indicator.
  • Explain pair correlations and blocking in finite nuclei.
  • Evaluate a quasiparticle model without equating its gap parameter to every mass difference.

Neighboring nuclear masses show alternating patterns associated with whether protons and neutrons can form correlated pairs. These patterns connect binding energies to shell filling and collective inertia, but they do not directly photograph a condensate. Nuclear pairing is a finite-system many-body phenomenon. Its interpretation requires a sign convention for binding, a prescription for removing smooth trends, and a model that distinguishes correlated pair motion from an ordinary independent-particle energy gap.

Pair time-reversed states and identify blocking

An attractive pairing interaction often couples time-reversed orbitals into total angular momentum zero. It can mix configurations differing in which pair of orbitals is occupied, lowering the energy of a correlated superposition. This is more than assigning a fixed extra attraction to two labeled particles. All valence identical nucleons participate through antisymmetrized configurations, with proton and neutron pairing commonly treated in separate channels before introducing additional proton-neutron correlations.

In an odd system, an unpaired nucleon can block one orbital from participating in the same pair-scattering pattern. This helps explain why adding the next neutron may bind more strongly when it completes an even neutron population. The effect coexists with ordinary level spacing, deformation, and polarization of the core. Consequently an odd-even pattern is evidence of correlation, but extracting an interaction strength requires calculating those other contributions within the chosen many-body framework.

Hpair=−GP†P,P†=∑k>0ak†akˉ†,G>0H_{\rm pair}=-G P^\dagger P,\qquad P^\dagger=\sum_{k>0}a_k^\dagger a_{\bar k}^\dagger,\qquad G>0
The bar labels a time-reversed partner and the sum counts each pair once, with phase conventions chosen consistently. G has energy units; this constant-pairing Hamiltonian is a schematic model.↔ Scroll wide equations horizontally.

Make the mass-filter sign explicit

Use positive total nuclear binding B at fixed proton number. The three-point indicator compares twice the central binding with its two neighbors, then multiplies by a parity-dependent sign. This convention gives a positive indicator for a simple pattern with enhanced even-neutron binding. Authors using negative total energies instead of positive binding reverse the apparent finite-difference sign. Writing the definition before inserting data prevents a purely conventional negative gap.

The filter removes a linear smooth background but retains its curvature. Near a shell closure, a large single-particle gap can therefore contaminate an indicator otherwise interpreted as pairing. Odd-centered and even-centered filters have different sensitivities to such filling effects. Experimental mass uncertainties and correlations also propagate into the difference. A small error bar on each total mass does not automatically establish that every residual fluctuation is a new pairing mechanism.

Δn(3)(N)=(−1)N2[2B(N,Z)−B(N−1,Z)−B(N+1,Z)]\Delta_n^{(3)}(N)=\frac{(-1)^N}{2}\left[2B(N,Z)-B(N-1,Z)-B(N+1,Z)\right]
The displayed sign assumes positive binding energies, all in one energy unit and at fixed Z. It is an empirical three-point indicator, not an exact definition of a microscopic quasiparticle gap.↔ Scroll wide equations horizontally.

Interpret a quasiparticle approximation

A Bardeen-Cooper-Schrieffer-type approximation mixes empty and doubly occupied time-reversed pairs. It introduces a chemical potential and a pairing gap that determine quasiparticle excitation energies and occupation probabilities. Orbitals close to the chemical potential acquire fractional mean occupations. These are expectation values in a correlated approximation, not statements that each event contains a fraction of a neutron. The simplest product ansatz does not have an exact particle number.

Number projection, blocking prescriptions, and finite-space treatment matter in real nuclei, especially when correlations are weak. The fitted gap parameter need not equal a three-point mass indicator, and a quasiparticle excitation need not equal a measured odd-nucleus energy without rearrangement effects. Pairing also changes rotational response, connecting odd-even masses with moments of inertia. Agreement with both classes of observables is a stronger test than fitting one indicator and assuming every other consequence follows.

Ek=(ϵk−λ)2+Δ2,vk2=12(1−ϵk−λEk)E_k=\sqrt{(\epsilon_k-\lambda)^2+\Delta^2},\qquad v_k^2=\frac12\left(1-\frac{\epsilon_k-\lambda}{E_k}\right)
Epsilon-k, chemical potential lambda, gap Delta, and quasiparticle energy E-k have energy units. The occupation formula is the standard schematic BCS result for a time-reversed pair and is not an exact fixed-number nuclear solution.↔ Scroll wide equations horizontally.

A toy odd-centered pairing indicator

At fixed even Z, toy positive bindings for neutron numbers 10, 11, and 12 are 82, 88, and 98 MeV. Find the two one-neutron separations and the three-point indicator centered on N eleven.

  1. Adding neutron eleven changes binding from 82 to 88 MeV, so Sn(11)=6 MeVS_n(11)=6\,\mathrm{MeV}. Adding neutron twelve changes it from 88 to 98 MeV, so Sn(12)=10 MeVS_n(12)=10\,\mathrm{MeV}.

  2. The central finite-difference bracket is 2(88)−82−98=−4 MeV2(88)-82-98=-4\,\mathrm{MeV}. Because the central N is odd, the prefactor is minus one half, giving Δn(3)(11)=2 MeV\Delta_n^{(3)}(11)=2\,\mathrm{MeV}.

  3. The separation difference is four MeV, twice this indicator. These numbers can arise from a linear background plus two MeV enhanced even-N binding. They illustrate a finite-difference pattern without determining a unique microscopic pairing interaction.

The result

The toy separations alternate from 6 to 10 MeV, and the declared odd-centered three-point indicator is positive 2 MeV.

Explore the model

Interactive lab

Interactive lab · quantum

A paired-amplitude analogy

Treat the two basis labels abstractly as empty and paired. Reset and set mixing angle 60∘60^\circ, phase zero; predict paired-basis probability one quarter. Compare a fresh Reset run at 120∘120^\circ, phase zero; predict three quarters. This pure two-state analogy contains no fermionic many-body space, number projection, gap equation, or nuclear mass filter.

A paired-amplitude analogyA normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Current readings: Probability |0⟩: 71.1%; Probability |1⟩: 28.9%; Bloch (x, y, z): 0.78, 0.45, 0.42. All parameters are adjustable with the labeled controls below.xyz|0⟩|1⟩Basis probabilitiesP(0)71.1%P(1)28.9%
Bloch vector / P(0)P(1)Phase latitude
Probability |0⟩
71.1%
Probability |1⟩
28.9%
Bloch (x, y, z)
0.78, 0.45, 0.42
t = 0 s

A normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forFractional mean pair occupancy can arise from amplitudes, but a two-state illustration does not solve finite-nucleus pairing.

Check your understanding

Why can a three-point mass indicator differ from a fitted BCS gap parameter?

Try it yourself

In the schematic quasiparticle model take ϵk−λ=3 MeV\epsilon_k-\lambda=3\,\mathrm{MeV} and Δ=4 MeV\Delta=4\,\mathrm{MeV}. Find E and the mean occupation probability. Repeat for an orbital equally far below the chemical potential and compare the zero-gap limit.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use the three-four-five square root, then retain the sign of the energy relative to the chemical potential in the occupation formula.

Compare with the solution

The upper orbital has E=9+16=5 MeVE=\sqrt{9+16}=5\,\mathrm{MeV} and v2=(1−3/5)/2=0.2v^2=(1-3/5)/2=0.2. The lower orbital has the same E but v2=(1+3/5)/2=0.8v^2=(1+3/5)/2=0.8. As the gap tends to zero away from the chemical potential, the upper occupation tends to zero and the lower to one. These are mean occupations per magnetic partner in the approximation; they do not directly give a three-point mass difference.

Take it with you

  • A signed mass-filter definition must accompany any quoted pairing indicator.
  • Blocking and pair scattering connect odd-even masses to many-body correlations.
  • A quasiparticle gap is model dependent and need not equal an empirical finite difference.

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