Nuclear shell model and magic numbers
Count fermionic orbital capacities and interpret shell closures without confusing a mean field with the full nuclear interaction.
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The question for today
What you’ll understand
- Count single-species orbital and oscillator-shell degeneracies.
- Infer spin and parity in a stated one-valence-nucleon approximation.
- Distinguish shell gaps from a universal fixed orbital ordering.
Nuclear masses and spectra show changes when particular proton or neutron populations close a shell. The shell model interprets these patterns through fermions occupying quantum orbitals in an effective mean field, supplemented by residual interactions. The orbitals are basis states, not paths of little particles circling a central object. Their occupation organizes a many-body calculation, while the size of energy gaps and the strength of configuration mixing determine whether a simple filling picture is reliable.
Count states for each nucleon species
In a spherical field, label an orbital by a radial index, orbital angular momentum l, and total single-particle angular momentum j. For a spin-one-half nucleon, j is l plus or minus one half, except that l zero permits only one half. Each j orbital has two j plus one magnetic substates. Pauli exclusion applies separately to protons and neutrons: the same spatial-spin orbital can contain one proton and one neutron because their internal species states differ.
A completely filled j multiplet is rotationally invariant and has zero total angular momentum. For an even-even closed core with positive parity, one additional valence nucleon has the spin and parity of its orbital in the extreme independent-particle approximation. A single hole in a filled orbital carries the same j and parity labels. Residual coupling to core excitations can change the content of the actual state, so these assignments are conditional predictions rather than an automatic rule for every odd nucleus.
Test a simple oscillator baseline
The isotropic three-dimensional oscillator provides a useful solvable reference. Its major shell number K counts total Cartesian oscillator quanta. The number of triples of nonnegative integers summing to K is half of K plus one times K plus two. Including two spin states doubles that count. Filling major shells gives cumulative populations two, eight, twenty, forty, and so on for one species, before adding spin-orbit splitting or changing the central potential.
The early agreement with familiar magic populations does not establish the oscillator as an exact nuclear Hamiltonian. Near ordinary stability, prominent closures include two, eight, twenty, twenty-eight, fifty, eighty-two, and one hundred twenty-six. The higher sequence requires substantial changes in level ordering, especially the nuclear spin-orbit interaction. Far from stability even familiar gaps can weaken or new ones can appear. A magic number summarizes observed or predicted shell behavior in a region, not a topological invariant of the nucleon count.
Add residual correlations in a model space
A practical valence-space calculation selects orbitals outside a core and diagonalizes an effective Hamiltonian among many allowed occupation configurations. Even if each basis configuration resembles independent filling, the eigenstate may be a superposition with no unique last-particle orbital. Good total angular momentum and parity remain useful when the Hamiltonian preserves those symmetries. Two or more valence nucleons require angular-momentum coupling and exchange constraints, not simple addition of their individual spin labels.
The core and truncated space also influence transition operators. Polarization of excluded orbitals can enter effective interactions and effective electromagnetic charges. Parameters fitted in one region should not be transported unchanged without checking their domain. Comparing spectra alone can conceal an inadequate transition operator or missing configuration mixing. Mass differences, transfer strengths, moments, and transition probabilities provide complementary tests of whether the selected space captures the relevant structure.
Work it through
One neutron outside a filled core
Assume an even proton core with spin-parity zero-plus and neutron ordering . Fill nine neutrons in the extreme independent-particle model and predict the total spin-parity.
The first orbital holds neutrons. The next holds four and the third holds two, so the first three orbitals accommodate eight neutrons in complete magnetic multiplets.
The ninth neutron enters . Its orbital angular momentum is two, giving positive parity, and its single-particle total angular momentum is five halves.
The filled neutron orbitals and stipulated proton core together carry zero angular momentum. Coupling the unpaired neutron therefore gives . This result assumes the stated ordering and weak enough mixing for one valence orbital to dominate.
The specified model predicts a five-halves positive-parity state; it is an inference from explicit filling assumptions rather than from neutron number alone.
The living notebook
Explore the model
Interactive lab · probability
Independent occupancy as a counting analogy
For a purely mathematical occupancy analogy, Reset and set ; predict mean three occupied slots and variance 1.5. Compare a fresh Reset run at , giving exactly six occupied slots with zero variance. This binomial model assumes independent slots and does not enforce fixed nuclear particle number, fermionic correlations, shell energies, or angular-momentum coupling.
- Mean · np
- 5
- Variance · np(1−p)
- 2.5
- Total probability
- 1
These are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forCounting available substates is distinct from predicting the correlated occupation pattern of a fixed nucleus.
Pause & reason
Check your understanding
Your turn
Try it yourself
Compute the spin-inclusive degeneracy of oscillator shell and the cumulative population through it. Separately, what spin-parity follows for one hole coupled to a zero-plus core in the same extreme approximation?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Sum the shell capacities for K from zero through three. A hole retains the angular-momentum and parity labels of the removed orbital.
Compare with the solution
The shell-three capacity is . Earlier capacities are two, six, and twelve, so the cumulative population is forty. This oscillator baseline does not produce a gap at twenty-eight without additional level rearrangement. A hole has and , giving negative parity. Coupled to the stipulated core, it yields . Both conclusions depend on their declared model assumptions.
Keep the idea
Take it with you
- Orbital capacities count magnetic substates separately for neutrons and protons.
- Single-particle spin-parity predictions require a specified core and dominant configuration.
- Shell closures depend on effective level gaps and can evolve across the nuclear chart.
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