advanced34 min studyLesson 411 in Physics

System–environment entanglement and decoherence

Derive local coherence loss from environmental distinguishability while keeping the joint evolution unitary.

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What you’ll understand

  • Compute a reduced state from conditional environment states.
  • Relate interference visibility to an environment overlap.
  • Separate decoherence, energy relaxation, and selective measurement.

An isolated composite can obey perfectly reversible quantum dynamics while one accessible part loses interference. The missing information is then stored in correlations rather than destroyed by a modified Schrödinger equation. To see the mechanism, keep the environment in the calculation until the final partial trace. This also reveals why a diagonal reduced density matrix does not, by itself, identify a unique outcome in an individual experimental run.

A record can form without changing populations

Take orthogonal system states ∣0⟩,∣1⟩|0\rangle,|1\rangle and an initially uncorrelated environment in ∣e⟩|e\rangle. A controlled interaction sends each system basis state to itself while attaching a normalized conditional environment state. Linear extension determines the evolution of any superposition. The system populations do not change in this model, so if this basis diagonalizes its Hamiltonian, its mean energy is unchanged. Nevertheless the interaction can change all interference experiments involving superpositions of these states.

The conditional environment states need not be orthogonal. Their inner product tells us how well the environment can distinguish the two alternatives. Parallel states leave no distinguishable record; orthogonal states carry a perfectly distinguishable record in principle, whether anyone reads it or not. Such an interaction can be embedded in a unitary transformation because the two specified input vectors are orthogonal and their output vectors remain orthogonal through the system factor. One must also complete the action on the remaining composite basis.

(a∣0⟩+b∣1⟩)∣e⟩⟼a∣0⟩∣e0⟩+b∣1⟩∣e1⟩,∣a∣2+∣b∣2=1(a|0\rangle+b|1\rangle)|e\rangle\longmapsto a|0\rangle|e_0\rangle+b|1\rangle|e_1\rangle,\qquad |a|^2+|b|^2=1
The amplitudes a and b and normalized environment vectors are dimensionless. This is an exact controlled isometry on a fixed initial environment subspace, extendible to a unitary; it is not a general dissipative model.↔ Scroll wide equations horizontally.

The partial trace multiplies coherences

Expand the projector onto the joint final vector before tracing. A diagonal term contains the norm of a conditional environment state, which is one. An off-diagonal term contains the overlap η=⟨e1∣e0⟩\eta=\langle e_1|e_0\rangle. Thus local coherence is suppressed without reducing the joint state purity. Cauchy–Schwarz guarantees an overlap magnitude at most one and thereby keeps the reduced matrix positive. A complex overlap can both reduce contrast and shift the phase of an interference fringe.

For an equal initial superposition, measuring along a transverse direction gives fringe visibility equal to the overlap magnitude. The reduced eigenvalues are half of one plus or minus that magnitude. This is a useful distinction between a coherent phase rotation and decoherence: rotation moves a pure Bloch vector around the sphere, whereas entanglement can shorten the reduced vector. Equal computational-basis populations cannot distinguish the two situations, so a population-only experiment is insufficient to diagnose lost coherence.

ρS=(∣a∣2ab∗ηa∗bη∗∣b∣2),Tr⁡ρS2=∣a∣4+∣b∣4+2∣ab∣2∣η∣2\rho_S=\begin{pmatrix}|a|^2&ab^*\eta\\a^*b\eta^*&|b|^2\end{pmatrix},\qquad \operatorname{Tr}\rho_S^2=|a|^4+|b|^4+2|ab|^2|\eta|^2
The density matrix and purity are dimensionless. The expression assumes the controlled interaction above and an initially pure product state. Purity one indicates a pure reduced state; purity can fall even when the composite remains pure.↔ Scroll wide equations horizontally.

What is reversible, and what was measured?

With access to the full composite, applying the inverse joint unitary restores the initial product and its interference. Access only to the system generally prevents this recovery by a system unitary, because a unitary cannot change its eigenvalues. Measuring the environment and conditioning on an outcome creates a different, selective description. Averaging those conditioned states reproduces the reduced density operator. The same local mixed state may also arise from a classical mixture, so its preparation history is not recoverable from local tomography alone.

A finite environment can return information and produce revivals. Irreversible exponential decay instead needs further assumptions about many modes, timescales, and accessible controls. Decoherence is also basis dependent: here the interaction selects the displayed basis, and another coupling can select different robust states. Calling the final diagonal matrix a complete solution of the measurement problem goes beyond the calculation. What has been established is suppression of local interference and the presence of correlations, without selecting an observed result.

A partly distinguishable environment record

Start the system in (∣0⟩+∣1⟩)/2(|0\rangle+|1\rangle)/\sqrt2. Let ∣e0⟩=∣0⟩E|e_0\rangle=|0\rangle_E and ∣e1⟩=(3∣0⟩E+4∣1⟩E)/5|e_1\rangle=(3|0\rangle_E+4|1\rangle_E)/5. Find the reduced matrix, its purity, and the probability of the system outcome ∣+⟩=(∣0⟩+∣1⟩)/2|+\rangle=(|0\rangle+|1\rangle)/\sqrt2.

  1. Both environment vectors have norm one; their overlap is η=3/5\eta=3/5. The trace therefore leaves each population at one half and changes each off-diagonal entry from one half to 3/103/10.

  2. The reduced eigenvalues are 1/2±3/101/2\pm3/10, or 4/54/5 and 1/51/5. Squaring and summing gives purity 16/25+1/25=17/25=0.6816/25+1/25=17/25=0.68. Its trace remains one and both eigenvalues are positive.

  3. The plus-state probability sums all four entries with a factor one half: P(+)=12(1+3/5)=4/5P(+)=\tfrac12(1+3/5)=4/5. The unentangled input would give probability one, so the interference contrast has decreased.

The result

The reduced matrix has diagonal entries 0.5 and off-diagonal entries 0.3; its purity is 0.68 and the plus probability is 0.8. The composite state is still pure.

Explore the model

Interactive lab

Interactive lab · quantum

A pure phase change as a control comparison

Reset and set both controls to θ = 90° and φ = 0°; predict Bloch x = 1 and equal basis probabilities. Reset and set both to θ = 90° and φ = 90°; predict Bloch x = 0, Bloch y = 1, with the same basis probabilities. Keep playback paused for these initial comparisons. The lab contains pure states only; it cannot display the shortened mixed-state vector or the environment in this lesson.

A pure phase change as a control comparisonA normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Current readings: Probability |0⟩: 71.1%; Probability |1⟩: 28.9%; Bloch (x, y, z): 0.78, 0.45, 0.42. All parameters are adjustable with the labeled controls below.xyz|0⟩|1⟩Basis probabilitiesP(0)71.1%P(1)28.9%
Bloch vector / P(0)P(1)Phase latitude
Probability |0⟩
71.1%
Probability |1⟩
28.9%
Bloch (x, y, z)
0.78, 0.45, 0.42
t = 0 s

A normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forChanging a coherent relative phase preserves purity, even when a chosen transverse component changes.

Check your understanding

In the controlled model, what follows when the conditional environment states become orthogonal?

Try it yourself

Use the same controlled interaction with orthogonal environment records, but start the system in 3∣0⟩/2+∣1⟩/2\sqrt3|0\rangle/2+|1\rangle/2. Find its final purity and plus-state probability.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Keep the unequal populations when the overlap vanishes; then evaluate the plus projector.

Compare with the solution

The reduced state is diag⁡(3/4,1/4)\operatorname{diag}(3/4,1/4) because the two cross terms have zero environment trace. Its purity is 9/16+1/16=5/89/16+1/16=5/8. The plus probability is one half of the trace, hence 1/21/2, despite unequal basis populations. A fully mixed qubit would instead have purity 1/21/2, so complete dephasing of an unequal superposition does not imply maximal mixing.

Take it with you

  • Environment overlap controls local interference in this exact record model.
  • Tracing a pure entangled state can produce a mixed reduced state.
  • Decoherence alone does not specify a selective measurement outcome.

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