One-loop four-point amplitudes
Assemble the scalar s, t, and u bubbles, subtract their ultraviolet pole, and check renormalization-scale dependence.
On this page
The question for today
What you’ll understand
- Identify three crossing channels and their common bubble coefficient.
- Separate a local ultraviolet counterterm from momentum-dependent finite functions.
- Verify cancellation of explicit scale dependence against one-loop coupling running.
A four-point amplitude combines several diagrams that share the same external particles but route momentum through different channels. Their sum tests crossing symmetry, local renormalization, and scale dependence in one compact setting. We use massive real quartic scalar theory with the conventions already fixed. The result is a representative one-loop calculation, rather than a prediction for an unspecified experimental cross section: amplitudes must still be squared with the appropriate interference, external normalization, flux, and final-state phase space.
Keep the channel and normalization bookkeeping explicit
Define the scattering matrix through and the connected matrix element of T by a momentum-conserving delta function times . The interaction gives tree amplitude . At one loop, joining two quartic vertices by two internal lines produces a bubble in each of the s, t, and u channels. Each labeled channel has the same factor one half, while its scalar integral depends on the corresponding momentum invariant.
In , write the bare quartic coupling as . We display the reduced amplitude after factoring one overall , and use the scalar loop measure inside its coefficient. This convention avoids multiplying the scale factor twice. After subtraction and the four-dimensional limit, the amplitude is dimensionless. For on-shell equal masses, the invariants satisfy , so setting all three to zero is not a physical scattering configuration.
The divergence is local, the finite answer carries kinematics
The three bubble poles do not depend on the external invariants, so a single local quartic counterterm cancels their sum. In modified minimal subtraction, its value is three times the common channel pole coefficient. It cannot remove arbitrary momentum-dependent logarithms without changing the theory’s local operator content. A momentum-subtraction scheme instead fixes a coupling by a chosen off-shell vertex condition and generally differs by finite terms. Translating the coupling definition is essential when comparing finite amplitudes between schemes.
Define a finite channel function as minus the parameter integral of the causal logarithm. The renormalized amplitude is the tree term plus the sum of those three functions with their common coefficient. Permuting s, t, and u leaves this identical-scalar expression unchanged. Above the two-particle threshold a channel can become complex. A real Euclidean matching point is useful for defining parameters, but its vertex should not be reported as an on-shell cross section without analytic continuation and the remaining scattering factors.
An arbitrary subtraction scale must cancel to the stated order
At fixed external invariants and mass, each finite channel has explicit derivative two with respect to logarithm of mu. Three channels therefore generate a positive explicit scale derivative proportional to six times their common coefficient. The tree term changes because the renormalized coupling runs. Its one-loop beta function cancels that derivative. Changing lambda inside the loop term would contribute only at the next perturbative order in this check, so it is consistently omitted here.
Residual scale dependence after truncation is a higher-order effect, not a license to treat the scale as an independently measured parameter. Its variation can diagnose sensitivity but is not a rigorous complete uncertainty bound. Also, a one-loop correction to a probability involves interference between tree and loop amplitudes; squaring only the loop part starts at a different order. The wave lab illustrates coherent addition and cancellation, with two fixed-frequency classical components rather than scalar scattering channels or renormalization-group evolution.
Work it through
Check the one-loop scale derivative
At a reference scale, let . Compute the leading derivative of the tree amplitude and the explicit derivative of the summed finite bubble contribution with respect to .
The tree contribution is , so its scale derivative is . Numerically this is approximately .
Each F function has explicit scale derivative two. Three channels give six, so the explicit loop derivative is .
Add the two terms: they cancel through order lambda squared. Running the coupling inside the one-loop coefficient generates order-lambda-cubed terms, beyond this one-loop consistency check.
The tree and explicit loop derivatives cancel at about ±0.000190, leaving only higher-order scale dependence.
The living notebook
Explore the model
Interactive lab · waves
Add amplitudes before inferring weights
Reset and set phase difference , amplitude ratio one; predict resultant amplitude two. Repeat from Reset with both controls , one; predict cancellation to zero. These are equal-frequency, co-propagating classical waves, not s, t, and u loop amplitudes, running couplings, or a cross-section calculator.
- Sum at x = 0
- 0.866
- Resultant amplitude
- 1.732
- Phase difference
- 60°
Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forCoherent contributions can interfere; diagram probabilities cannot simply be added before amplitudes are assembled.
Pause & reason
Check your understanding
Your turn
Try it yourself
For an illustrative supplied analytic point, take finite channel functions , , and . Assemble the finite reduced amplitude through one loop. These supplied values are an algebra exercise, not asserted on-shell kinematics.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Sum channels once, then multiply by the common bubble coefficient and add the negative tree term.
Compare with the solution
The finite sum is six, so the loop correction is . The reduced amplitude is therefore . This number is an amplitude in the stated normalization. A cross section would require the tree-loop interference at the desired order, as well as flux and phase space; the supplied F values alone do not define a physical scattering event.
Keep the idea
Take it with you
- The three scalar crossing channels share a coefficient but carry different invariant dependence.
- A local counterterm removes a local ultraviolet divergence while finite channel functions remain.
- Coupling running cancels explicit subtraction-scale dependence through the computed order.
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