Landau free energy and first-order transitions
Use symmetry-constrained local free-energy expansions to distinguish equilibrium coexistence, metastable branches, and mean-field spinodals.
On this page
The question for today
What you’ll understand
- State the analyticity and small-order-parameter assumptions in Landau theory.
- Find coexistence by comparing free-energy values rather than curvatures alone.
- Locate local spinodals and explain their relation to nucleation and hysteresis.
A local free-energy landscape organizes several different questions: which uniform states are stationary, which are locally stable, and which have the lowest free energy? A first-order transition is decided by the last question. A metastable state may persist after it ceases to be the equilibrium minimum, while a spinodal marks the disappearance of a local minimum within the chosen mean-field landscape. These are distinct locations, not interchangeable definitions of the transition temperature.
Symmetry restricts the expansion but does not choose coefficients
For a scalar order parameter with reversal symmetry and no conjugate field, the local expansion contains only even powers. A field adds a linear term that explicitly breaks that symmetry. Analyticity of this coarse-grained local function near small order parameter is an assumption; the final thermodynamic free energy can become nonanalytic after minimization and the infinite-system limit. One must not assume the exact critical free energy itself has an ordinary Taylor series everywhere.
A positive quartic coefficient gives the familiar continuous mean-field onset when the quadratic coefficient changes sign. A negative quartic term requires a positive higher-order stabilizer, for which the sextic term is the simplest choice. This truncated polynomial is useful only over amplitudes where omitted terms remain small or where it is explicitly adopted as an illustrative model. Symmetry alone does not guarantee a continuous transition, fix a critical temperature, or determine the numerical coefficients.
Equal minima determine coexistence
At zero field, the disordered stationary point is . Nonzero stationary points obey a quadratic equation for . For negative u, a pair of ordered minima can coexist locally with the central minimum while the quadratic coefficient is still positive. The first-order coexistence condition requires the nonzero stationary point to have the same free energy as the origin, not merely that the two states both exist.
Combining stationarity with equality of free energies gives a finite jump in squared order parameter and a positive coexistence value of r. In a sample with a conserved spatial average, the equilibrium state between coexisting values may separate into domains, adding interfacial costs at finite size. The resulting equilibrium free energy respects convexity in its proper constrained variable. The nonconvex local polynomial should therefore be read as a coarse-grained landscape rather than the fully convex thermodynamic answer for arbitrary constrained mixtures.
A barrier makes kinetics different from equilibrium
A local minimum with higher free energy is metastable. Reaching the equilibrium phase requires an appropriately sized fluctuation that creates a nucleus and overcomes an interfacial barrier. Its lifetime depends on temperature, sample volume, defects, and dynamics, none of which is determined by uniform minimization alone. Sweeping a control parameter too rapidly can therefore follow different metastable branches and produce hysteresis even though equilibrium comparison selects a unique coexistence condition.
A spinodal solves stationarity and vanishing curvature together: a minimum merges with an intervening maximum. The central minimum loses curvature at r=0, while the ordered extrema first appear at the discriminant threshold above coexistence. In short-range finite-dimensional systems, nucleation can end metastable persistence before this ideal endpoint, and a sharp thermodynamic spinodal need not exist. A smooth experimental fit with a negative quartic coefficient is consequently a model inference requiring checks, not a stand-alone proof of a phase boundary.
Work it through
A sextic model with simple coexistence values
Take , , and zero field in the sextic free energy. Find the coexistence r, the magnitude of the order-parameter jump from the central state, and both local spinodal values. Compare their order along increasing r.
The equal-depth condition gives . Therefore the ordered minima at coexistence have , separated by a finite jump from the central value zero.
Insert the same coefficients into to obtain . At this value , making the equal values at zero and plus or minus one explicit.
The central spinodal is zero, and the ordered spinodal is in units E0. Thus coexistence lies strictly between the two endpoints, and neither endpoint equals the equilibrium crossing.
Coexistence occurs at r=E0 with |m| jumping from zero to one; local spinodals are r=0 and r=4E0/3.
The living notebook
Explore the model
Interactive lab · function
Curvature is a local test
For each fresh run, Reset and set BOTH Coefficient a and Position x. At x=0 compare a=1 and a=−1, predicting a local minimum and maximum of y=ax² with zero tangent slope in both cases. This quadratic instrument cannot display the sextic landscape, two minima, nucleation, or coexistence.
- y at chosen x
- 0.608
- Tangent slope · 2ax
- 1.35
- Signed area · ax³/3
- 0.182
This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forStationarity alone does not determine stability. The lab isolates a local curvature distinction and cannot locate a first-order transition.
Pause & reason
Check your understanding
Your turn
Try it yourself
Use the same model with , , but set . Its nonzero stationary squared amplitudes are and . Classify them and decide whether the ordered local minimum or the origin is the equilibrium uniform state.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Evaluate the curvature at a stationary point using , then compare its free energy with f(0)=0.
Compare with the solution
At , the curvature is , so these are maxima. At , it is , so these are local minima. At a nonzero stationary point the free energy simplifies to , giving at q=5/6. The origin has positive curvature r and free energy zero, so it is the equilibrium uniform state. The ordered local minima are metastable, consistent with r lying above coexistence but below the ordered spinodal.
Keep the idea
Take it with you
- An analytic local Landau expansion is an assumption about coarse-grained variables.
- Coexistence compares minimum values; spinodals test loss of local stability.
- Hysteresis and metastable lifetimes require kinetic information beyond the uniform polynomial.
Read further
Original sources and deeper explanations to follow at your own pace.
- Cambridge, Tong: Statistical Field Theory §1.2.2 and §1.3.1 — metastability, spinodals, and analytic local expansions
- MIT 8.334, Kardar: Lecture 2, PDF pp. 5–9 — phenomenological Landau theory and saddle points
- Cambridge, Tong: Statistical Physics §5.1.1 and §5.4.1–5.4.2 — coexistence, metastability, and stabilizing higher powers
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