advanced36 min studyLesson 298 in Physics

Alfvén and magnetosonic waves

Resolve magnetic tension and compression into three ideal MHD branches with explicit propagation-angle dependence.

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What you’ll understand

  • Relate shear Alfvén waves to field-line tension and transverse motion.
  • Calculate fast and slow magnetosonic phase speeds.
  • Check parallel and perpendicular limiting cases without assigning adjustable dispersion to the lab.

A magnetized fluid supports more than one kind of wave because magnetic forces can resist both bending and compression. The shear Alfvén branch bends the field with a transverse displacement. Fast and slow magnetosonic branches couple pressure and magnetic compression. Their speeds depend on propagation direction, so specifying a wave number without its angle to the background field is insufficient to identify a frequency.

Linearize about a uniform equilibrium

Take a homogeneous static plasma with constant density ρ0\rho_0, scalar pressure p0p_0, and magnetic field B0\mathbf B_0. Small perturbations vary as exp⁡[i(k⋅x−ωt)]\exp[i(\mathbf k\cdot\mathbf x-\omega t)]. Linear continuity links density perturbation to k⋅δu\mathbf k\cdot\delta\mathbf u, while the adiabatic closure links pressure to density. The induction equation links magnetic perturbation to fluid displacement. Substituting these relations into momentum balance produces an eigenvalue problem for three velocity polarizations.

Define the Alfvén speed from background field strength and mass density, and the sound speed from the selected adiabatic pressure response. Let θ\theta be the angle between wavevector and background magnetic field. These definitions refer to a uniform, ideal, scalar-pressure medium. Equilibrium gradients, background flow, kinetic resonances, and collisions can change the spectrum. Calling a measured disturbance Alfvénic is therefore a comparison with these assumptions, not just a claim that a magnetic field is present.

vA=B0μ0ρ0,cs2=γp0ρ0,ωA2=k2vA2cos⁡2θ=k∥2vA2v_A=\frac{B_0}{\sqrt{\mu_0\rho_0}},\qquad c_s^2=\frac{\gamma p_0}{\rho_0},\qquad \omega_A^2=k^2v_A^2\cos^2\theta=k_\parallel^2v_A^2
Both speeds are in m/s, k is angular wave number in rad/m, and ω is angular frequency in rad/s. The shear Alfvén dispersion assumes small perturbations in uniform ideal MHD. Its velocity polarization is perpendicular to both k and B₀ when those directions are distinct.↔ Scroll wide equations horizontally.

Tension and compression give distinct branches

For the shear Alfvén mode, perturbed velocity lies normal to the plane containing k\mathbf k and B0\mathbf B_0. Its divergence vanishes, so density and scalar pressure are unperturbed to first order. Magnetic tension supplies the restoring force. The frequency depends on the parallel wave number; when that component is zero this ideal branch has zero frequency, rather than a propagating shear oscillation at the perpendicular Alfvén crossing rate. Its group velocity points along the background field.

The other two polarizations lie in the wavevector–field plane and generally compress the fluid. The magnetosonic quadratic gives fast and slow phase-speed squares. The nonnegative discriminant and nonnegative roots can be checked from their sum and product. Fast and slow denote eigenbranches, not two arbitrary wave packets moving at user-selected speeds. Their velocity and magnetic perturbations are coupled, so identifying a branch requires polarization information as well as a frequency estimate.

vf,s2=12[vA2+cs2±(vA2+cs2)2−4vA2cs2cos⁡2θ],ωf,s2=k2vf,s2v_{f,s}^2=\frac12\left[v_A^2+c_s^2\pm\sqrt{(v_A^2+c_s^2)^2-4v_A^2c_s^2\cos^2\theta}\right],\qquad \omega_{f,s}^2=k^2v_{f,s}^2
The plus sign is the fast branch and minus sign the slow branch. These are phase speeds along the wavevector, not generally group-speed magnitudes. Ideal MHD gives no dependence on wave-number magnitude at fixed angle; finite-orbit and kinetic dispersion lie outside this formula.↔ Scroll wide equations horizontally.

Use limiting angles as a diagnostic

For propagation parallel to the field, magnetosonic phase speeds reduce to the larger and smaller of vAv_A and csc_s. One transverse magnetic branch is degenerate with the shear Alfvén speed; special-angle eigenvectors should be treated using the linear equations rather than a division by a vanishing component. For perpendicular propagation, fast speed becomes vA2+cs2\sqrt{v_A^2+c_s^2} while both slow and shear frequencies vanish in this homogeneous ideal limit.

At fixed angle the frequency is proportional to wave-number magnitude, yet the medium remains directionally anisotropic. A phase front and a wave packet need not travel in the same direction. Zero-frequency limiting branches are also not evidence that all plasma disturbances stop: other geometries, entropy perturbations, and physics beyond the ordering remain possible. The useful habit is to test angle, pressure closure, and microscopic scale before extrapolating a familiar sound-wave picture to a magnetized plasma.

A perpendicular fast wave

A uniform ideal plasma has vA=4000 m/sv_A=4000\,\mathrm{m/s} and cs=3000 m/sc_s=3000\,\mathrm{m/s}. A small perturbation propagates exactly perpendicular to the field with wavelength 1000 m. Find the fast-mode speed and frequency, and state the shear and slow frequencies in this limit.

  1. At θ=90∘\theta=90^\circ, the cosine vanishes. The fast-speed square becomes vA2+cs2=(4000)2+(3000)2=25×106 m2/s2v_A^2+c_s^2=(4000)^2+(3000)^2=25\times10^6\,\mathrm{m^2/s^2}, a useful 3–4–5 triangle in speed space.

  2. Thus vf=5000 m/sv_f=5000\,\mathrm{m/s}. Ordinary frequency is speed divided by wavelength, ff=5000/1000=5.0 Hzf_f=5000/1000=5.0\,\mathrm{Hz}. Angular frequency is 2πff=31.4 rad/s2\pi f_f=31.4\,\mathrm{rad/s}, using angular wave number k=2π/1000k=2\pi/1000.

  3. The shear formula contains k∥=0k_\parallel=0, giving ωA=0\omega_A=0. The slow root also vanishes because the magnetosonic product is proportional to cos⁡2θ\cos^2\theta. These are nonpropagating limiting branches of this particular uniform ideal calculation.

The result

The perpendicular fast wave moves at 5.0 km/s and oscillates at 5.0 Hz for the stated wavelength. Shear and slow branches have zero frequency in this exact limiting geometry.

Explore the model

Interactive lab

Interactive lab · waves

Superposition after choosing a branch

Reset and set both controls to phase 0° and amplitude ratio 1; predict a sum with twice a component's amplitude. Reset and set both controls to phase 180° and ratio 1; predict cancellation, then Step or Play. Both components are fixed equal-frequency waves sin(2x − t); controls do not change MHD angle, branch speeds, dispersion, or propagation direction.

Superposition after choosing a branchTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forLinear superposition can be tested after a wave model is chosen; this lab does not derive the Alfvén or magnetosonic spectrum.

Check your understanding

In uniform scalar-pressure ideal MHD, what happens to the shear Alfvén frequency when the wavevector becomes exactly perpendicular to the background field?

Try it yourself

Keep vA=4000 m/sv_A=4000\,\mathrm{m/s} and cs=3000 m/sc_s=3000\,\mathrm{m/s}. For a wavevector at 60° to the background field with angular magnitude k=0.002 rad/mk=0.002\,\mathrm{rad/m}, find the shear Alfvén angular frequency and period. Then give the two magnetosonic speeds for parallel propagation.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use the parallel projection for the shear branch, and the maximum/minimum speed rule for the separate parallel case.

Compare with the solution

The parallel component is k∥=0.002cos⁡60∘=0.001 rad/mk_\parallel=0.002\cos60^\circ=0.001\,\mathrm{rad/m}. Hence ∣ωA∣=4.0 rad/s|\omega_A|=4.0\,\mathrm{rad/s} and its period is 2π/4=1.57 s2\pi/4=1.57\,\mathrm s. In the separate parallel-propagation case, fast and slow speeds are respectively 4000 and 3000 m/s. The 60° shear period must not be paired with the parallel magnetosonic geometry as though they described the same eigenmode. The given k is angular wave number, so inserting another factor of 2π2\pi into the frequency would be incorrect.

Take it with you

  • Shear Alfvén waves are transverse and restored by magnetic tension.
  • Fast and slow magnetosonic speeds depend on sound speed, Alfvén speed, and wavevector angle.
  • Check special-angle limits and distinguish angular wave number from inverse wavelength.

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