Guiding-centre electric and gradient drifts
Derive common electric drift and charge-dependent magnetic drift with explicit vector directions and ordering.
On this page
The question for today
What you’ll understand
- Obtain a perpendicular force drift from averaged force balance.
- Separate charge-independent electric transport from magnetic drift current.
- Check drift directions, units, and guiding-centre validity.
A rapidly gyrating particle can slowly move across the magnetic field. The centre of its orbit then carries information that the circle alone hides. Different causes of this drift have different dependences on charge, mass, and energy. In particular, electrons and ions share the same leading electric drift but generally acquire opposite gradient drifts. That distinction separates bulk transport from one source of electric current.
A perpendicular force has a sideways response
Suppose an additional perpendicular force varies little during one gyroperiod. At leading averaged order, balance . Crossing with the field gives . This is a drift of the guiding centre, superposed on fast gyration. It is not the instantaneous acceleration direction: particles still accelerate throughout each orbit even when their averaged centre moves steadily.
For electric force , the signed charge cancels. The resulting electric cross magnetic drift is identical for electrons and singly charged ions in the same slowly varying fields. A quasineutral population therefore carries no leading net current from their common drift alone. An electric field parallel to the magnetic field cannot be balanced this way; it accelerates particles along the field and must be treated separately.
A field-strength gradient separates species
In a field that strengthens across an orbit, curvature of the trajectory is greater on the stronger-field side. The two sides no longer close into an identical circle. Equivalently, gyroaveraging produces an effective force . Applying the force-drift formula gives a gradient drift perpendicular to both field direction and field-strength gradient. Its denominator contains signed charge, while the scalar magnetic moment stays positive; that is where the charge dependence enters.
Particles with larger perpendicular kinetic energy have larger gradient drift at fixed charge and field geometry. Electrons and ions can therefore contribute to a transverse current even while maintaining nearly equal densities. A particle guiding-centre drift is not the entire macroscopic pressure current: assembling a fluid current also involves the gyromotion's magnetization contribution and the distribution of particles. Do not identify a single representative orbit with a complete fluid transport law.
Ordering decides which drift terms survive
Field-line curvature produces another magnetic drift proportional to parallel energy and inverse signed charge. A changing perpendicular electric field produces a polarization correction, which depends on mass and the rate of electric-field change. These effects are absent from a uniform static electric-drift example, not prohibited in general. Comparing their orders requires the field-variation scale, gyrofrequency, parallel speed, and electric-field timescale rather than a list of drift names alone.
A practical direction check starts with a right-handed Cartesian basis. Compute the electric cross product before dividing by the positive squared field magnitude. For gradient drift, compute the unit-field cross gradient, then include the sign of charge. Finally compare the drift speed with the fast perpendicular speed and the orbit radius with the gradient scale. If these assumptions fail, a numerical orbit calculation or kinetic treatment may be needed instead of another term in the same truncated formula.
Work it through
Two transverse motions with different charge rules
Let , , and . A proton has perpendicular energy 10 eV. Use and neglect curvature and time dependence. Find both leading drift vectors.
Since , the electric drift is . The same result holds for an electron in these fields.
Convert perpendicular energy to . Its scalar moment is energy divided by field: . The field-strength length is .
Now , and . Thus the proton gradient drift is , giving a combined leading velocity of .
The proton has −500 m/s electric drift and +25 m/s gradient drift along y. An electron with the same perpendicular energy shares the former and reverses the latter, so those two effects have different current implications.
The living notebook
Explore the model
Interactive lab · vectors
Make the drift-direction sign visible
Represent a normalized drift vector in the plane. Reset and set both controls to angle −90° and magnitude 1; predict negative y projection. Reset and set both controls to angle 90° and magnitude 1; predict positive y projection. This compares directions only: the lab does not compute cross products, guiding-centre orbits, or a magnetic-field gradient.
- x component
- 1.393
- y component
- 0.975
- Magnitude
- 1.7
Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThe charge sign can reverse a magnetic drift while a common electric drift keeps its direction; the vector lab verifies projections only.
Pause & reason
Check your understanding
Your turn
Try it yourself
Keep the fields of the worked example, but consider an electron with perpendicular energy 20 eV. Find its gradient drift and combined leading drift. State what happens to the electric drift if the magnetic field is reversed while electric field is unchanged.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use perpendicular energy directly in the moment and keep the electron charge negative.
Compare with the solution
The electron moment is . Its gradient drift is negative y with magnitude . Adding the common electric drift gives . Reversing the magnetic vector changes the electric cross product's sign but leaves its squared magnitude fixed, so the electric drift becomes positive y at 500 m/s. These results assume the electron remains magnetized and other drift mechanisms remain negligible.
Keep the idea
Take it with you
- Electric drift is a common leading perpendicular motion, independent of species charge and mass.
- Gradient drift changes sign with charge and scales with perpendicular energy.
- A drift formula is an ordered gyroaverage, not a replacement for all particle or fluid dynamics.
Read further
Original sources and deeper explanations to follow at your own pace.
Optional progress, saved in this browser when available. Revisit any lesson at any time.
Lesson not marked complete.