research38 min studyLesson 99 in Physics

Bootstrap crossing and positivity

Translate conformal crossing into a positive-coefficient consistency problem and understand what a numerical exclusion certificate proves.

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What you’ll understand

  • Write the crossing equation for identical scalar primaries with a stated reduced-correlator convention.
  • Explain the role of squared OPE coefficients and reflection positivity in a unitary bootstrap.
  • Distinguish a rigorous exclusion under assumptions from an allowed region or an approximate spectrum reconstruction.

The conformal bootstrap asks whether proposed operator data can satisfy all the consistency requirements of a conformal field theory. It combines symmetry, operator-product expansions, crossing, and positivity without first choosing a microscopic Lagrangian. This can constrain strongly interacting fixed points. The logic is especially important: ruling out data under stated assumptions is different from constructing a theory, and surviving a finite numerical test is not a proof of existence.

The same four-point function has different expansions

Take four identical Hermitian scalar primary operators with scaling dimension Δϕ\Delta_\phi in a unitary Euclidean conformal field theory. Factor the two-point-distance dependence so that the remaining function is G(u,v)G(u,v), where u and v are conformal cross ratios. Expanding the operator product of the first pair gives a sum of conformal blocks. Exchanging an appropriate pair of insertion points yields another expansion of the same correlator. Equality of these descriptions is crossing symmetry, rather than a new dynamical force.

With the conventional prefactor 1/(x122Δϕx342Δϕ)1/(x_{12}^{2\Delta_\phi}x_{34}^{2\Delta_\phi}), crossing reads vΔϕG(u,v)=uΔϕG(v,u)v^{\Delta_\phi}G(u,v)=u^{\Delta_\phi}G(v,u). The block sum separates known kinematic functions from unknown dimensions, spins, and OPE coefficients. The identity contribution has fixed normalization once the external two-point function is normalized. Changing the prefactor convention changes the displayed crossing equation, so a numerical implementation must use mutually consistent blocks and prefactors.

G(u,v)=∑OλϕϕO 2gΔ,ℓ(u,v),vΔϕG(u,v)=uΔϕG(v,u)G(u,v)=\sum_{\mathcal O}\lambda_{\phi\phi\mathcal O}^{\,2}g_{\Delta,\ell}(u,v),\qquad v^{\Delta_\phi}G(u,v)=u^{\Delta_\phi}G(v,u)
The expression uses normalized identical real scalar external operators and an orthonormal exchanged-operator basis in a unitary theory. Degenerate operators contribute sums of nonnegative squares.↔ Scroll wide equations horizontally.

Positivity turns consistency into an exclusion problem

Reflection positivity and an appropriate real operator basis make the identical-scalar OPE coefficients enter as nonnegative squares. Move crossing into a vector equation containing the identity vector plus a nonnegative sum of exchanged-operator vectors. A linear functional can rule out a proposed spectrum if it evaluates positively on the identity and nonnegatively on every exchanged vector allowed by the assumptions. Applying it would make zero equal a strictly positive quantity, which is impossible.

The word every is doing essential work. A sampled grid of a few dimensions and spins is not automatically a certificate over a continuous unbounded spectrum. Practical numerical methods use controlled block approximations, derivative bases, spin treatment, and positive-polynomial or semidefinite constraints. Numerical tolerances and approximation errors must be assessed before calling a result rigorous. In mixed-correlator systems, positivity becomes a matrix condition rather than the simple scalar-square form used here.

F1+∑OpOFO=0,pO≥0;α(F1)>0, α(FO)≥0 ⟹ exclusionF_{\mathbf 1}+\sum_{\mathcal O}p_{\mathcal O}F_{\mathcal O}=0,\quad p_{\mathcal O}\geq0;\qquad \alpha(F_{\mathbf 1})>0,\ \alpha(F_{\mathcal O})\geq0\ \Longrightarrow\ \text{exclusion}
The implication applies only when the functional inequalities hold for the entire spectrum permitted by the stated assumptions, with approximation and numerical errors controlled.↔ Scroll wide equations horizontally.

Interpret a bound with its hypotheses attached

Bootstrap bounds depend on dimension, external dimensions, global symmetry representations, unitarity, and any assumed gaps or operator multiplicities. A gap assumption is additional physical input, even when motivated by a known model. An isolated allowed island can strongly identify candidate data, but survival at finite derivative order is still necessary consistency evidence rather than a complete constructive definition of the theory. Convergence under stronger tests makes that evidence more persuasive.

The worked example compresses the functional logic to one scalar constraint. It teaches why nonnegative coefficients can make a proposed cancellation impossible, without pretending that two arbitrary numbers are conformal blocks. Actual research calculations combine infinitely many potential operators and exploit their analytic structure. Extending sharp bounds to less symmetric theories, real-time observables, and situations without ordinary positivity remains challenging; those directions require new arguments rather than silently reusing the unitary identical-scalar setup.

A miniature exclusion certificate

In a finite illustrative consistency problem, suppose a linear functional gives identity value 1 and allowed-vector values 0.2 and 0.7. Can nonnegative coefficients p and q satisfy the resulting crossing condition?

  1. Apply the functional to the assumed vector equation. It becomes 1 + 0.2p + 0.7q = 0, with p and q nonnegative.

  2. The two coefficient terms are each at least zero, so the complete left side is at least one. For example, p = 2 and q = 3 would give 3.5, not zero.

  3. No nonnegative choices can cancel the positive identity term. The assumed allowed-vector set is excluded by this functional; allowing a vector with negative functional value would change the premise.

The result

The example demonstrates the logic of a positivity certificate. It excludes only the stated finite toy spectrum and does not calculate conformal blocks, a physical gap bound, or a real CFT spectrum.

Explore the model

Interactive lab

Interactive lab · vectors

Inspect directions before imposing positive combinations

The lab shows one two-dimensional vector with angle and magnitude controls and its x/y projections. Compare directions whose projection on a chosen axis is positive or negative to understand the geometry of a separating functional. It does not sum a spectrum, construct a convex cone, evaluate conformal blocks, or run a bootstrap optimizer.

Inspect directions before imposing positive combinationsPlayback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Current readings: x component: 1.393; y component: 0.975; Magnitude: 1.7. All parameters are adjustable with the labeled controls below.−7.46−3.7303.737.46−3.5−1.7501.753.5xyvvₓ = 1.39
Vectorx / y projectionsTrace marker
x component
1.393
y component
0.975
Magnitude
1.7
t = 0 s

Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA separating functional detects which directions could cancel an identity contribution. The actual bootstrap requires positivity over the full allowed operator spectrum.

Check your understanding

What does a candidate point surviving a finite bootstrap calculation establish by itself?

Try it yourself

Change the toy functional identity value to −1 while retaining allowed values 2 and 4. Solve −1 + 2p + 4q = 0 for p when q = 0.1 and q = 0.3. Which choice respects positivity?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Rearrange to p = 1/2 − 2q, then inspect the sign rather than only the equality.

Compare with the solution

For q = 0.1, p = 0.3, so both coefficients are nonnegative and the scalar equation is satisfied. For q = 0.3, p = −0.1, which violates positivity. The first choice merely satisfies one toy constraint; many additional crossing components could still rule it out in a full problem.

Take it with you

  • Crossing equates different OPE expansions of the same correlator, with convention-dependent prefactors.
  • Unitarity supplies positivity that can turn a functional into an exclusion certificate.
  • An allowed numerical region is necessary consistency evidence, with its spectral and numerical assumptions still attached.

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