The epsilon expansion and critical exponents
Locate the Wilson–Fisher fixed point near four dimensions and compute a consistently ordered correlation-length exponent.
On this page
The question for today
What you’ll understand
- State the coupling normalization and momentum-scale convention of a one-loop beta function.
- Compute the perturbative Wilson–Fisher fixed point and the first epsilon correction to nu.
- Explain why inserting epsilon equal to one is an extrapolation rather than a controlled small-parameter proof.
Critical fluctuations are strongly coupled in many physical dimensions, yet the same family of models can become weakly interacting near an upper critical dimension. The epsilon expansion exploits that nearby solvable point. It analytically organizes calculations in dimension four minus epsilon, then asks how much information survives toward lower dimension. The control parameter and the distinction between a series and its extrapolation must remain explicit throughout.
Fix the convention before finding a fixed point
Take the Euclidean model with interaction and a tuned mass. Use dimensional regularization near and define a dimensionless renormalized coupling by factoring from the quartic coefficient. Our beta function differentiates with respect to increasing momentum scale . The engineering contribution is then negative epsilon times g; changing to increasing length would reverse the flow convention.
At one loop the positive quadratic term balances that engineering contribution and gives a nonzero fixed point proportional to epsilon. This is the Wilson–Fisher point for small positive epsilon and positive physical component number. The numerical value assigned to g depends on its normalization and subtraction scheme; a critical exponent computed consistently to its stated order does not acquire that arbitrary normalization dependence. Finding a zero of one truncated beta function is only the first step, not a complete construction of a fixed-point theory.
Extract a universal exponent at consistent order
A small departure of the thermal or mass-like scaling variable grows under coarse graining with eigenvalue . The correlation length diverges with exponent . Evaluating the mass anomalous dimension at the perturbative fixed point gives . The two comes from the Gaussian mass dimension, and the correction comes from interacting critical fluctuations. A field anomalous dimension starts only at second order in epsilon in this model.
Invert the series and then truncate at the same order: . Numerically taking the reciprocal of the truncated expression for without re-expanding includes an uncontrolled subset of higher powers. That can be a declared approximation, but it is not the unique first-order prediction. This distinction becomes noticeable at epsilon near one, where different partial rearrangements disagree by terms that the calculation has not determined.
From a controlled neighborhood to a physical dimension
For sufficiently small epsilon the fixed point is weakly coupled, so omitted loop terms are parametrically suppressed. In three dimensions epsilon is one, and small-epsilon control alone no longer establishes numerical accuracy. Higher orders, carefully justified resummation, lattice calculations, experiments, and bootstrap bounds provide complementary evidence. Agreement among independent methods is more informative than treating a single low-order decimal as an exact critical exponent.
Universality also has conditions. The symmetry, dimensionality, interaction range, and relevant perturbations must place the system in the claimed universality class. Long-range forces, anisotropies, disorder, or an additional massless mode can change the fixed-point problem. The epsilon expansion is powerful because it tracks operators and eigenvalues systematically; it does not license relabeling every continuous transition as the same model. Some candidate fixed points disappear or require genuinely nonperturbative information away from the controlled neighborhood.
Work it through
A small-epsilon Ising calculation
For N = 1 and epsilon = 0.1, compute the fixed coupling, thermal eigenvalue, and consistently first-order nu.
Insert N + 8 = 9 into the fixed-point expression. The leading coupling is 6 times 0.1/9, approximately 0.0666667 in our normalization.
The thermal correction coefficient is (N + 2)/(N + 8) = 1/3, giving y_t = 2 − 0.1/3, approximately 1.9666667 through this order.
Use the re-expanded exponent: nu = 0.5 + 0.1/12, approximately 0.5083333. The direct reciprocal of 1.9666667 differs by terms of order epsilon squared, which have not been computed.
The correction is small in this controlled near-four-dimensional example. These numbers are perturbative estimates with omitted higher orders, rather than exact exponents in dimension 3.9.
The living notebook
Explore the model
Interactive lab · optimization
Separate stability from a specific renormalization flow
Inspect gradient descent on f(x) = x²/2 using the step size η and initial x₀. Its update xₙ = (1−η)ⁿx₀ shows how a linearized update can approach or leave a fixed point. It is not the O(N) beta function, does not vary spacetime dimension, and cannot calculate critical exponents or Wilson–Fisher trajectories.
- Position x0
- 2
- Objective x²/2
- 2
- Iteration behavior
- Stable step
Gradient descent on f(x) = x²/2: xₙ = (1 − η)ⁿx₀. Playback advances two discrete iterations per second. Values outside |x| ≤ 4 are explicitly reported. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forStability depends on the evolution convention and local eigenvalues. A descent diagram supplies an analogy, while critical exponents require the actual renormalization-group calculation.
Pause & reason
Check your understanding
Your turn
Try it yourself
For N = 2 and epsilon = 0.1, compute the leading fixed coupling and first-order nu. Explain what changes if epsilon is then set to one.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
The two ratios are 6/(N + 8) and (N + 2)/[4(N + 8)]. Keep the order label.
Compare with the solution
The fixed coupling is 6 times 0.1/10 = 0.06 plus higher orders. Nu is 0.5 + 4 times 0.1/40 = 0.51 plus terms of order epsilon squared. Setting epsilon to one gives the first-order extrapolation 0.6, but no small parameter then bounds its error; higher-order and independent nonperturbative information are needed before assigning precision.
Keep the idea
Take it with you
- A beta function needs its coupling normalization and scale direction stated before its signs are interpreted.
- Critical exponents must be expanded consistently with the perturbative order used to obtain the fixed point.
- Three-dimensional estimates from epsilon equal to one require evidence beyond small-epsilon control.
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