Action and Noether’s theorem
Turn continuous global symmetries into conserved currents, while keeping boundary terms and on-shell assumptions visible.
On this page
The question for today
What you’ll understand
- Derive the field Euler–Lagrange equation by varying an action.
- Construct a current for an internal continuous symmetry.
- Separate a local continuity equation from a globally conserved charge.
A field theory needs a rule for comparing whole histories, not just a force at one instant. The action supplies that rule. Its symmetry then lets us discover quantities that cannot change during the motion. Here we derive this connection rather than treating conservation as a slogan. Our examples are classical; quantum anomalies later explain why a classical symmetry need not survive quantization.
A history is the variable
Work in flat four-dimensional spacetime, with and metric . The field assigns a value to every spacetime event. An action integrates a local Lagrangian density over spacetime. “Local” here means that the density depends on fields and a finite set of derivatives at the same event. It does not mean that the resulting solution has no correlations between distant points.
Compare with , keeping the variation zero on the boundary. Integration by parts moves a derivative off and produces a boundary contribution. The remaining bulk coefficient must vanish because the interior variation is arbitrary. We have not minimized a positive function: Lorentzian actions generally have stationary points, which can be saddles. Keeping that distinction prevents a misleading picture of nature “choosing the least energy history.”
Promote the symmetry parameter to a diagnostic
Suppose a constant infinitesimal parameter changes the fields by without changing the action, apart from a total derivative. Temporarily let depend on position. This is a bookkeeping device, not a claim that the theory has acquired a gauge symmetry. The coefficient multiplying identifies a current. On solutions of the equations of motion, that current has zero divergence.
For a real shift symmetry, , the massless derivative Lagrangian is unchanged. The associated current is . Its continuity equation is exactly the massless wave equation. Add a potential depending on and the shift usually fails. A symmetry must be tested on the action before one names its charge; recognizing a familiar-looking transformation is not sufficient.
Charges need a boundary policy
Integrate the continuity equation over a spatial region. A decreasing charge inside can be exactly balanced by current flowing out through its boundary. The integral over all space is constant only when the flux at infinity vanishes, or another stated boundary condition supplies the same result. In a periodic box, opposite faces cancel. In an open detector volume, charge inside the apparatus can change even while the theory respects its symmetry.
Time translations similarly lead to energy conservation when the action has no explicit time dependence. Spatial translations lead to momentum. Currents themselves are not unique: adding the divergence of an antisymmetric tensor leaves the continuity equation intact and, with suitable boundaries, leaves the charge intact. This freedom matters when comparing canonical and improved stress tensors. Conservation is the robust statement; one particular local expression may be a convenient representative.
Work it through
A shift charge in a periodic box
Take in a periodic box of volume , and the spatially uniform history . Find its shift charge and test what a mass term would change.
The field equation is . The proposed history has zero second time derivative and zero spatial derivatives, so it is a solution.
For the unit shift , differentiating the density with respect to gives . Therefore and the spatial current vanishes.
Integrating gives , constant in time. A term changes the variation by and breaks the continuous shift; the uniform solution then oscillates rather than growing linearly.
The massless shift charge measures the uniform mode’s velocity, not the field’s constant offset. The massive theory can conserve energy while lacking this particular charge.
The living notebook
Explore the model
Interactive lab · fields
Boundary flux and circulation
Vary source strength q and rotation Ω in the softened two-dimensional field q r/(r² + ε) + Ω(−y, x). Compare the radial component crossing a circle with the rotational component running along it. Use the arrows to distinguish outward flux from circulation.
- Fx at (1, 0)
- 0.833
- Fy at (1, 0)
- 0.5
- Field magnitude there
- 0.972
The softened illustration is q·r/(r² + 0.2) + Ω(−y, x). Moving markers indicate local direction, not integrated particle paths or a Maxwell solution. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThis is an illustrative vector field, not a computed Noether current or a Maxwell solution. A current crossing a boundary must enter charge accounting, but this sketch alone proves no symmetry or conservation law.
Pause & reason
Check your understanding
Your turn
Try it yourself
For , compute the divergence of the candidate shift current . When is it conserved for all solutions?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use the field equation rather than imposing a special constant solution.
Compare with the solution
The Euler–Lagrange equation is , so . A continuous shift is a symmetry when the potential is constant throughout the field range. A stationary point of a nonconstant potential can make this divergence vanish on one special history, but does not establish a symmetry of the theory.
Keep the idea
Take it with you
- Vary the action with stated boundary conditions before naming the equations of motion.
- Noether currents are conserved on solutions for genuine continuous symmetries.
- Global charge conservation additionally requires control of boundary flux.
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