Nuclear magnetic resonance and spin relaxation
Separate a static shift from frequency-filtered fluctuations and state the conditions behind simple relaxation formulas.
On this page
The question for today
What you’ll understand
- Separate orbital and spin shifts from a calibrated resonance frequency.
- Relate longitudinal recovery to transverse fluctuating local fields.
- Explain the assumptions behind a Korringa comparison and the distinction between T1 and T2.
A nuclear spin is a local magnetic probe embedded at a crystallographically defined site. Its resonance frequency records an effective static field, while its return toward equilibrium records fluctuations of that field. These are complementary observables rather than two ways of measuring the same susceptibility. Hyperfine couplings connect the nucleus to electronic spins and orbitals, and their spatial pattern filters momentum space. The challenge is to identify which part of a changing line or recovery curve belongs to the electronic property of interest.
A shift requires a reference and a coupling model
For a spin-one-half nucleus in a strong uniform field, the leading resonance frequency is the angular gyromagnetic ratio times field divided by two pi. Define the fractional shift relative to a suitable reference at the same field. Its spin contribution is proportional to the uniform static electronic susceptibility, with a hyperfine coupling whose units depend on the susceptibility convention. Orbital or chemical shifts, demagnetizing fields, and macroscopic susceptibility corrections may also contribute. A measured total shift cannot be substituted for its spin part without separating these terms.
Nuclei with spin greater than one half additionally possess an electric quadrupole moment. Coupling to an electric-field gradient can split or shift lines, and second-order effects may affect even a central transition. Structural changes can therefore move a line without changing spin susceptibility. Multiple sites, orientation-dependent tensors, and disorder broaden the interpretation further. Field and orientation dependence, known reference compounds, and comparisons across nuclear species help disentangle magnetic and quadrupolar contributions before a microscopic conclusion is assigned.
Relaxation selects fluctuations near the nuclear frequency
Longitudinal relaxation restores the nuclear population imbalance after a pulse perturbs it. Transverse local fields drive transitions between nuclear Zeeman levels, so their noise near the Larmor angular frequency controls a weak-coupling T1 rate. The electronic response enters through a momentum sum weighted by the hyperfine form factor. In contrast, the spin shift samples the uniform static response. Antiferromagnetic fluctuations can therefore enhance relaxation strongly while changing the uniform shift relatively little, or can be filtered at a particular nuclear site.
A useful illustrative classical-noise model takes each transverse field component to have equal variance and an exponentially decaying correlation. In the high-temperature, stationary, weak-coupling and motional-narrowing regime its Lorentzian spectral density gives the rate below. Slowing the noise first increases the rate, then decreases it once the correlation time becomes long compared with the inverse Larmor frequency. Thus a relaxation maximum does not by itself show that fluctuation amplitude peaks; the spectral weight may simply move through the nuclear detection window.
Recovery, dephasing, and Korringa tests answer different questions
For fully saturated spin-one-half nuclei with a single uniform relaxation time, longitudinal magnetization recovers exponentially. Inversion recovery has a different amplitude, while quadrupolar level populations, distributions of environments, or incomplete saturation can require multiple exponentials. T2 characterizes transverse relaxation, while the free-induction time T2* can additionally include static frequency inhomogeneity; an echo refocuses part of that static phase spread. A broad line is therefore not automatically a short T1, and a fitted stretched exponential needs a physical interpretation rather than automatic identification with one microscopic rate.
A simple noninteracting metal with contact hyperfine coupling gives the Korringa relation between spin shift and relaxation. It uses a dimensionless spin shift, not a percentage number or a shift contaminated by orbital contributions. Correlations, multiband weights, momentum-dependent couplings, and spin-orbit effects can alter the comparison. Likewise, a decrease below a superconducting transition must be interpreted with field orientation, orbital subtraction, vortex contributions, and the pairing model specified; a single relaxation curve cannot uniquely identify a gap symmetry.
Work it through
A shift and a recovery time are separate measurements
For a hypothetical spin-one-half site, the reference frequency is and resonance is . An independently known orbital shift is 0.003. After complete saturation, magnetization reaches half its equilibrium value at . Find the spin shift and T1.
The total fractional shift is , or one percent. The dimensionless form, not the number one, is used in a Korringa product.
Subtract the stipulated orbital contribution: . This subtraction assumes the orbital reference remains applicable to this state and orientation.
At half recovery, , so . The calculation relies on saturated single-exponential spin-one-half recovery.
The spin shift is 0.007, or 0.7 percent, and the stipulated recovery gives T1 about 14.43 milliseconds.
The living notebook
Explore the model
Interactive lab · markov
Population relaxation versus its stationary value
For separate fresh runs Reset and set p and q to , then ; press Step once in each run. The clock advances half a second, hence one transition. Predict state-one probabilities 0.2 and 0.4 with the same stationary value 0.5. This exact discrete population analogy is not a nuclear spin-noise, precession, or T1 fitting simulator.
- P(state 1) at step 0
- 0%
- Stationary P(state 1)
- 60%
- Chain behavior
- Monotone convergence
Exact finite-step probabilities for a two-state chain starting in state 0, not sampled trajectories. Playback advances two transitions per second. When p = q = 0 every distribution is stationary; when p = q = 1 the chain alternates forever. A single zero transition creates an absorbing state. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThe approach rate and the equilibrium population are distinct properties.
Pause & reason
Check your understanding
Your turn
Try it yourself
In the illustrative noise model use and . Compare relaxation rates at and , with fixed variance.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Compute the dimensionless product omega0 tau_c before evaluating each Lorentzian denominator.
Compare with the solution
At one microsecond the product is one, so . At 0.1 microsecond the product is 0.1, giving . Both weak-coupling products are small. The change follows a spectral-window shift at fixed field variance, not a fivefold increase in moment amplitude.
Keep the idea
Take it with you
- A calibrated total shift needs orbital and other contributions separated before it becomes spin susceptibility.
- T1 probes filtered dynamics and can peak as the fluctuation timescale changes.
- Recovery laws and Korringa tests require nuclear, coupling, and electronic assumptions.
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