advanced38 min studyLesson 608 in Physics

Turn an invariant amplitude into an event yield

Normalize scattering with invariant incoming flux, phase space, spin sums, and identical-particle counting before relating a cross section to integrated luminosity and efficiency.

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What you’ll understand

  • Use the invariant two-particle flux with a consistently normalized amplitude.
  • Identify initial spin averages, final spin sums, and final-state symmetry factors.
  • Translate an inclusive cross section into an expected selected event count.

A squared amplitude is not a cross section. The incident flux, the available final states, and the conventions used to count spin and identical particles must also enter. A measured event yield adds another layer: the luminosity delivered, branching fractions, acceptance, efficiency, and backgrounds. Keeping these layers explicit makes it possible to compare a theoretical prediction with a detector result without hiding factors in an undefined normalization.

Normalize the incoming state

Use ℏ=c=1\hbar=c=1, the positive-time metric, and relativistically normalized asymptotic states. For two incoming on-shell particles, the invariant flux denominator is four times the square root of (pa⋅pb)2−ma2mb2(p_a\cdot p_b)^2-m_a^2m_b^2. In the center-of-momentum frame this becomes 4pi∗s4p_i^*\sqrt s. The corresponding differential cross section is the squared amplitude times our invariant phase-space measure divided by that flux. The dimensions then give an area, represented as inverse energy squared in natural units.

The ordinary difference of beam velocities is not a Lorentz-invariant relative speed. In the center-of-momentum frame it can be used with the matching energy factors to reproduce the invariant formula, but it can exceed one without describing the speed of a single object. Avoid interpreting that flux factor as a signal velocity. For particles in hadrons, a partonic cross section also needs a convolution with momentum-fraction distributions before becoming the hadronic prediction. The beam luminosity alone does not remove that theoretical distinction.

dσ=∣M∣2‾4(pa⋅pb)2−ma2mb2 dΦn,dσdΩ∗=164π2spf∗pi∗∣M∣2‾d\sigma=\frac{\overline{|\mathcal M|^2}}{4\sqrt{(p_a\cdot p_b)^2-m_a^2m_b^2}}\,d\Phi_n,\qquad \frac{d\sigma}{d\Omega^*}=\frac{1}{64\pi^2s}\frac{p_f^*}{p_i^*}\overline{|\mathcal M|^2}
The second expression assumes a two-body distinguishable labeled final state in the CM frame, with our Φn including (2π)⁴. The bar denotes specified initial spin averaging and final spin summing. A final-state identical-particle correction is applied separately when required.↔ Scroll wide equations horizontally.

Specify what the spin average and symmetry factor mean

For unpolarized incoming particles of spins sa,sbs_a,s_b, average over their equally populated spin states by dividing the summed squared amplitude by (2sa+1)(2sb+1)(2s_a+1)(2s_b+1). Sum over unobserved final spin states. A polarized beam instead uses its actual spin density matrix, so the unpolarized average can be inappropriate. Massless gauge particles have only their physical helicities; counting fictitious extra polarizations as incident states would produce a wrong normalization. Color averaging, when relevant, is another separately declared internal-state average.

Identical final particles create a counting issue even after the amplitude has the required exchange symmetry. Integrating a full labeled phase space covers permutations of the same physical configuration, so divide by the factorial for each identical group. An explicitly nonduplicating ordered region is an alternative. Do not divide again simply because the incoming particles are identical: their prepared beam flux has already specified the collision normalization. Also keep combinatorial factors in an amplitude diagram distinct from a final-state phase-space symmetry factor.

∣M∣2‾=∑initial,final spins∣M∣2(2sa+1)(2sb+1),Nsel=Lint σ B ϵ\overline{|\mathcal M|^2}=\frac{\sum_{\mathrm{initial,final\ spins}}|\mathcal M|^2}{(2s_a+1)(2s_b+1)},\qquad N_{\mathrm{sel}}=\mathcal L_{\mathrm{int}}\,\sigma\,\mathcal B\,\epsilon
The spin formula assumes equally populated massive incoming spin multiplets; use physical helicity counts or a density matrix otherwise. The yield formula is a simplified background-free expectation with integrated luminosity in inverse-area units, branching fraction B, and a dimensionless combined acceptance-efficiency ε.↔ Scroll wide equations horizontally.

Compare like experimental and theoretical regions

Integrated luminosity counts collision exposure, while cross section measures an interaction's rate per that exposure. Their product is an expected produced count, not a guaranteed integer observation. A branching fraction restricts a produced particle to a specific final channel, and efficiency describes what fraction of that channel is selected. If a quoted cross section already refers to the exclusive channel, multiplying by its branching fraction again would undercount. Likewise, a fiducial cross section includes a declared truth-level region that should not receive a second acceptance extrapolation silently.

Observed counts include statistical fluctuations and background processes. Inferring a cross section generally requires a response model, luminosity calibration, background estimate, and uncertainties. Efficiency can vary across phase space, so a single number is only adequate when its averaging is appropriate for the signal distribution. Convert units explicitly: an inverse-picobarn luminosity must multiply a picobarn cross section to give a dimensionless count. To convert a natural-unit result, restore the squared factor of hbar c rather than treating inverse GeV squared as a barn.

Count one selected decay channel

An inclusive parent-production cross section is 4 pb4\,\mathrm{pb}. The collected integrated luminosity is 50 pb−150\,\mathrm{pb^{-1}}, the desired branching fraction is 0.25, and combined acceptance-efficiency for that channel is 0.8. Neglect backgrounds and find the expected selected count.

  1. Multiply cross section by exposure: 50 pb−1×4 pb=20050\,\mathrm{pb^{-1}}\times4\,\mathrm{pb}=200 expected produced parents. The area units cancel, leaving an expected count.

  2. Restrict to the desired decay: 200(0.25)=50200(0.25)=50 expected channel events before detector selection. The branching fraction is needed because the cross section was explicitly inclusive in the parent decay.

  3. Apply the channel's acceptance-efficiency: 50(0.8)=4050(0.8)=40 expected selected events. An observed count can fluctuate around this expectation and need not equal forty exactly.

The result

The expected selected signal count is forty. If the supplied four-picobarn cross section had already included the decay channel, the branching factor would need a different interpretation.

Explore the model

Interactive lab

Interactive lab · scattering

Check a power without assigning physical units

Reset and set g = 0.5 and θ = 90 degrees; predict schematic weight 0.0625. Compare with a fresh Reset, g = 1 and θ = 90 degrees, predicting weight 1, a factor of sixteen. The instrument evaluates only g⁴(1 + cos²θ). It has no incident flux, energy scale, spin sum, phase-space integration, luminosity, or barn units and does not compute a physical cross section.

Check a power without assigning physical unitsA schematic term diagram with dimensionless weight g⁴(1 + cos²θ). Lines denote terms, not particle paths; this is not a process cross-section or loop calculation. Current readings: Coupling factor g⁴: 0.24; Angular factor 1 + cos²θ: 1.329; Illustrative weight: 0.319. All parameters are adjustable with the labeled controls below.Incoming termsOutgoing termsθSchematic interaction term · no particle trajectories
Incoming termsOutgoing termsAngle θ
Coupling factor g⁴
0.24
Angular factor 1 + cos²θ
1.329
Illustrative weight
0.319
t = 0 s

A schematic term diagram with dimensionless weight g⁴(1 + cos²θ). Lines denote terms, not particle paths; this is not a process cross-section or loop calculation. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA schematic coupling power still needs physical normalization before it can predict an event rate.

Check your understanding

A cross section already includes the branching fraction for the final channel being counted. Which yield operation would double-count that channel restriction?

Try it yourself

A toy massless two-to-two process has distinguishable scalar particles, constant ∣M∣2=16π|\mathcal M|^2=16\pi, and s=100 GeV2s=100\,\mathrm{GeV^2}. Integrate the CM angular formula over all solid angle. Convert using 1 GeV−2=0.3894 mb1\,\mathrm{GeV^{-2}}=0.3894\,\mathrm{mb} and 1 mb=106 nb1\,\mathrm{mb}=10^6\,\mathrm{nb}.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The incoming and outgoing momentum magnitudes agree, and the full angular integral is four pi. No spin average or identical-final-state division is needed for this toy setup.

Compare with the solution

The momentum ratio is one. Thus σ=4π(16π)/(64π2s)=1/s=0.0100 GeV−2\sigma=4\pi(16\pi)/(64\pi^2s)=1/s=0.0100\,\mathrm{GeV^{-2}}. Converting gives 0.003894 mb=3894 nb0.003894\,\mathrm{mb}=3894\,\mathrm{nb}. This is the specified constant-amplitude model's cross section, not a general prediction for massless particles. A different amplitude, restricted angular region, internal-state average, or identical final state would change the result.

Take it with you

  • Cross sections require an invariant incident flux and a matched phase-space convention.
  • Initial averages, final sums, and identical-particle counting serve different purposes.
  • Event-yield comparisons must state luminosity, decay inclusiveness, selection, and units.

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