advanced38 min studyLesson 604 in Physics

Map a three-body decay onto invariant masses

Use pair-invariant constraints and pair-rest-frame angles to construct the physical Dalitz region and distinguish a constant-amplitude baseline from resonance dynamics.

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What you’ll understand

  • Relate the three pair masses to the parent and daughter masses.
  • Check a proposed Dalitz point against angular and energy constraints.
  • Explain when uniform population in squared invariant masses is a phase-space prediction.

A three-body decay has more freedom than a two-body decay: one daughter can carry different energies while the others share the recoil. A Dalitz plot records that freedom using two pair-invariant masses squared. The boundary is kinematic, while variation inside it can reveal resonances and interference. Separating those ingredients is especially valuable because a striking band in a detector plot can also be affected by acceptance and by which mass coordinates were chosen.

Reduce three pair masses to two coordinates

For an on-shell parent P with P2=M2P^2=M^2, define sij=(pi+pj)2s_{ij}=(p_i+p_j)^2 using the module's natural units and positive-time metric. Expand the three pair invariants and use P=p1+p2+p3P=p_1+p_2+p_3. Their sum is fixed by the parent and daughter masses, leaving two independent pair coordinates. The energy of daughter 3 in the parent rest frame follows by squaring P−p3=p1+p2P-p_3=p_1+p_2. Thus one pair mass directly determines the energy carried by the recoiling daughter.

Each pair mass must be at least the sum of that pair's masses, and at most the parent mass minus the third daughter mass. These one-coordinate limits are necessary but do not define a rectangle of physical events. At a fixed pair mass, the other coordinate must also correspond to a real relative angle. For nonzero daughter masses the resulting boundary is generally curved. Checking all three pair thresholds while ignoring the angle condition can still admit impossible configurations.

s12+s23+s13=M2+m12+m22+m32,E3=M2+m32−s122Ms_{12}+s_{23}+s_{13}=M^2+m_1^2+m_2^2+m_3^2,\qquad E_3=\frac{M^2+m_3^2-s_{12}}{2M}
The energy is measured in the parent rest frame, while the sij are invariant in every frame. Squared invariants use energy-squared units. Positive-energy on-shell daughters and exact four-momentum conservation are assumed.↔ Scroll wide equations horizontally.

Construct the boundary in a pair rest frame

Choose a value of s12s_{12} and transform to the rest frame of particles 1 and 2. Particle 2 then has energy (s12−m12+m22)/(2s12)(s_{12}-m_1^2+m_2^2)/(2\sqrt{s_{12}}), while particle 3 has energy (M2−s12−m32)/(2s12)(M^2-s_{12}-m_3^2)/(2\sqrt{s_{12}}). Their momenta follow from their mass shells. The second pair invariant depends linearly on the cosine of the angle between those two momenta. Parallel and antiparallel configurations therefore set the allowed extrema.

For three massless distinguishable daughters the geometry simplifies: all pair invariants are nonnegative and their sum is M2M^2. In the (s12,s23)(s_{12},s_{23}) plane this is a triangle bounded by zero and s12+s23=M2s_{12}+s_{23}=M^2. For a spinless parent and constant squared amplitude, the density is uniform in this triangle because the phase-space Jacobian is constant in the squared-invariant coordinates. A plot in pair masses rather than their squares has additional Jacobians and need not look uniform even for the same dynamics.

s23=m22+m32+2(E2∗E3∗−p2∗p3∗cos⁡θ23∗),dΓ=∣M∣2‾256π3M3 ds12 ds23s_{23}=m_2^2+m_3^2+2(E_2^*E_3^*-p_2^*p_3^*\cos\theta_{23}^*),\qquad d\Gamma=\frac{\overline{|\mathcal M|^2}}{256\pi^3M^3}\,ds_{12}\,ds_{23}
Stars now denote the 12-pair rest frame, not the parent rest frame. The width formula uses our phase-space convention after overall orientations are integrated for a scalar or rotationally unpolarized parent, with distinguishable labeled daughters and the appropriate spin-summed amplitude.↔ Scroll wide equations horizontally.

Read structures without confusing density and support

A resonance in one pair produces enhanced amplitude when that pair's invariant mass approaches the resonant mass. The corresponding band is tied to an invariant coordinate, while its intensity and interference pattern depend on the full coherent amplitude. Several pathways to the same final state must generally be added before squaring. Adding independent event histograms can miss interference and does not reproduce the same amplitude model. The physical boundary remains fixed by the external masses even when resonant structures change the interior distribution.

Identical daughters require consistent labeling or an explicitly folded region. Symmetrizing the amplitude and avoiding duplicate phase-space counting are separate operations. In data, efficiency, resolution, and mistaken particle assignments can distort both bands and apparent endpoints. A phase-space baseline should be passed through the relevant selection model or compared with appropriately corrected observations. A kinematically allowed point is not necessarily likely, and a sparsely populated part of the allowed region is not necessarily forbidden by a conservation law.

Reconstruct and test a massless Dalitz point

A parent of mass 6 GeV6\,\mathrm{GeV} decays into three distinguishable massless particles. A proposed point has s12=12 GeV2s_{12}=12\,\mathrm{GeV^2} and s23=9 GeV2s_{23}=9\,\mathrm{GeV^2}. Find the third invariant, the three parent-rest-frame energies, and the pair-rest-frame angle needed to check the point.

  1. The invariant sum is 36 GeV236\,\mathrm{GeV^2}, so s13=36−12−9=15 GeV2s_{13}=36-12-9=15\,\mathrm{GeV^2}. All pair invariants are nonnegative and the two plotted coordinates sum to less than 36.

  2. The parent-rest-frame energies are E1=(36−9)/12=2.25 GeVE_1=(36-9)/12=2.25\,\mathrm{GeV}, E2=(36−15)/12=1.75 GeVE_2=(36-15)/12=1.75\,\mathrm{GeV}, and E3=(36−12)/12=2 GeVE_3=(36-12)/12=2\,\mathrm{GeV}. Their sum is six GeV.

  3. In the 12 rest frame, E2∗=3 GeVE_2^*=\sqrt3\,\mathrm{GeV} and E3∗=23 GeVE_3^*=2\sqrt3\,\mathrm{GeV}. Thus s23=12(1−cos⁡θ23∗)s_{23}=12(1-\cos\theta_{23}^*), giving cos⁡θ23∗=1/4\cos\theta_{23}^*=1/4. This is a real allowed angle.

The result

The point is physically allowed, with third invariant 15 GeV² and parent-frame energies 2.25, 1.75, and 2 GeV. The pair-frame angle check is consistent with the triangular massless region.

Explore the model

Interactive lab

Interactive lab · vectors

Check the role of a real relative angle

Reset and set angle to 60 degrees and magnitude to 2; predict x = 1 and y = √3. Compare with a fresh Reset, angle 120 degrees and magnitude 2, which reverses x while leaving y unchanged. These projections illustrate the bounded cosine entering a dot product. The lab draws one planar vector; it does not generate three on-shell momenta, a Dalitz boundary, decay probabilities, or resonance bands.

Check the role of a real relative anglePlayback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Current readings: x component: 1.393; y component: 0.975; Magnitude: 1.7. All parameters are adjustable with the labeled controls below.−7.46−3.7303.737.46−3.5−1.7501.753.5xyvvₓ = 1.39
Vectorx / y projectionsTrace marker
x component
1.393
y component
0.975
Magnitude
1.7
t = 0 s

Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forAn invariant-coordinate proposal must correspond to real angles as well as algebraic conservation.

Check your understanding

For three massless daughters of a parent of mass M, which point is outside the physical Dalitz triangle?

Try it yourself

For the same M=6 GeVM=6\,\mathrm{GeV} massless decay, assume a constant squared amplitude and perfect acceptance. What fraction of events has s12≥18 GeV2s_{12}\ge18\,\mathrm{GeV^2}? Also test whether (s12,s23)=(25,16) GeV2(s_{12},s_{23})=(25,16)\,\mathrm{GeV^2} is allowed.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The allowed region is a uniformly populated right triangle. The cut leaves a smaller similar triangle.

Compare with the solution

The full triangle has legs of length 36 GeV236\,\mathrm{GeV^2}. The cut leaves a triangle with legs of length 18, so its area and event fraction are (18/36)2=1/4(18/36)^2=1/4. The proposed point has coordinate sum 41, exceeding 36, and would require s13=−5 GeV2s_{13}=-5\,\mathrm{GeV^2}. It is therefore forbidden. The one-quarter fraction relies on constant amplitude and the squared-invariant measure; resonances or nonuniform efficiency generally change it.

Take it with you

  • Two pair masses squared determine the third through the invariant sum.
  • Pair-rest-frame angular bounds define the physical region beyond separate endpoint limits.
  • A uniform Dalitz density requires a constant amplitude and controlled counting and acceptance.

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